(Atomic mass of Ca=40) A. 30.6 B. 75 C. 69.4 D. 25 Solution: (B) Weight of CaO = 0.56 g... View Article
A. 1.5:3 B. 3:1.5 C. 1:1 D. 2:3 Solution: (A)
A. 0.45 g B. 22.05 g C. 2.2 g D. 0.49 g Solution: (B) Mohr’s salt is FeSO4.(NH4)2S04.6H20 Only oxidisable... View Article
A. 39.4 g B. 197 g C. 591 g D. 985g Solution: (D) Ba(OH)2 + CO2 → BaCO3 + H2O... View Article
A. 22.4 L B. 8.80 g C. 4.40g D. 2.24 L Solution: (B) CaCO3 + 2HCl → CaCl + CO2... View Article
A. 60.3% B. 80% C. 93.1% D. 70% Solution: (C) Weight of AgCl precipitated = 7.2 g Weight of Ag... View Article
A. CH2O B. C2H5O C. C2H2O D. C3H6O3 Solution: () The empirical formula is CH2O. Therefore, the empirical weight =... View Article
A. C3H6 B. C3H8 C. CH2 D. C2H2 Solution: (A) The empirical formula is CH2 Empirical weight of CH2 =... View Article
A. CH2Cl2 B. CCl4 C. CHCl3 D. CH3Cl Solution: (C) Carbon. 10.06 / 12 = 0.8383 Hydrogen 0.84 / 1... View Article
A. 168 B. 68 C. 152 D. 56 Solution: (A) Atomic mass of element = Equivalent mass of element ×... View Article
A. M B. M / 2 C. M / 5 D. M / 3 Solution: (C) MnO−4 + 8H+ +... View Article
SnCl2 + Cl2 → SnCl4 A. 95 B. 45 C. 60 D. 30 Solution: (A) SnCl2 + Cl2 → SnCl4... View Article
A. It is readily available B. It has a very high cryoscopic constant C. It is volatile D. It is... View Article
A. 3:2 B. 2:1 C. 1:2 D. 1:1 Solution: (A) For first oxide, Moles of oxygen = 22 / 16... View Article
A. Five B. Four C. Three D. Two Solution: (D) Amount of nitrogen present in one mole of alkaloid i.e.,... View Article
A. 45 B. 9 C. 18 D. 36 E. 27 Solution: (E) Let us assume the atomic mass of M... View Article
A. 79 B. 31.6 C. 52.16 D. 158 Solution: (B) An equivalent weight of a solution is defined as the... View Article
A. M1, M2 B. M1, M2 / 2 C. 2M1, M2 D. M1, 2M2 Solution: (B) ∴ Equivalent mass of... View Article
A. 50 B. 100 C. 150 D. 200 Solution: (D) As 2g of metal carbonate is neutralised by 100mL of... View Article
A. 32 u B. 64 u C. 67 u D. 98 u Solution: (A) Molecular weight of X4O6 = (4a... View Article
