Solution: (2) Given: f (0) = 1, f (1) = 5 and f (2) = 11 f (x) = ax2 + bx + c f (0) = 1 f (0) = c = 1 c = 1 f (2) = 11 4a + 2b + 1 = 11... View Article
If f : R → R is given by . Then, (fof) (√5) = 1) 1 2) -1 3) √3 4) 0 Solution: (1) Let x = √5, (fof) (√5) = f (f (√5)) = f (0) = 1... View Article
Solution: (3) f (x) = ax + b g (x) = cx + d f{g(x)} = a (cx + d) + b = acx + ad + b g {f(x)} = c (ax + b) + d = acx + bc + d f{g(x)} = g... View Article