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If I 2 1 Then Sum Of I Plus I Power 2 Up To 1000 Terms Is Equal To

Solution: i+i2+i3+....1000 terms = i-1-i+1 ...1000 terms = 0... View Article

Solution: eiθ = cos θ+ i sin θ eiπ/2 = cos π/2+ i sin π/2 = i Let (a+ib) = ii Taking log on both sides log (a+ib) = i log i = i log... View Article

Solution: (1+2i)/(1-2i) Multiply numerator and denominator with (1+2i) =(1+2i)(1+2i)/(1-2i)(1+2i) = (1+4i-4)/(1+4) = (-3+4i)/5 =... View Article

Solution: (1+i)8+(1-i)8 (1+i)2 = (1+2i-1) = 2i ((1+i)2)4 = (2i)4 = 16 (1-i)2 = (1-2i-1) = -2i ((1-i)2)4 = (-2i)4 = 16 (1+i)8+(1-i)8 =... View Article

Solution: In+in+1+in+2+in+3 = in(1+i+i2+i3) = in(1+i-1-i) = 0 Hence option (1) is the answer.... View Article

Solution: x+1/x = 2 cos θ Rearranging , we get x2+1-2x cos θ = 0 x2-2x cos θ +1 = 0 x = [2 cos θ±√(4 cos2θ-4)]/2 = [2 cos θ±√4(... View Article

Solution: i(1+3+5..(2n+1) 1+3+5+...(2n+1) = sum of (n+1) terms of A.P Sn+1 =[ (n+1)/2](2+n+1-1)2 = [(n+1)/2](2+2n) = (n+1)2 Put n = 1... View Article