Solution: Given √2, 2/3, 2√2/9,... is 16/2187 This is a GP with a = √2 r = √2/3 The nth term of GP = arn-1 √2(√2/3)n-1 = 16/2187... View Article
If a, b and c are positive numbers in a GP, then the roots of the quadratic equation (loge a)x2 -(2 loge b)x+ (loge c)= 0 are Solution: Given... View Article
Solution: Given sum of infinite geometric series = 4 a/(1-r) = 4 ..(i) Second term = 3/4 So ar = ¾ ..(ii) a = 3/4r Substitute a in (i)... View Article
Solution: Given a,b,c are in AP Check the options. If a2, b2, c2 are in AP, then b2-a2 = c2-b2 (b-a)(b+a) = (c-b)(c+a) Since (b-a = c-b... View Article
Solution: LCM of 3 and 5 is 15. The numbers between 1 and 100 which are divisible by both 3 and 5 are 15, 30, 45, ..90 a = 15 an = 90 d =... View Article
Solution: Let x = log2 7 Then 2x = 7 (since logb(x) = y, then by = x) This is possible only for irrational number. Hence option (3) is the... View Article
Let a1, a2, a3,... be terms of an AP. If (a1+a2+...ap.)/(a1+a2+...aq) = p2/q2, p not equal to q, then a6/a21 equals (1) 7/2 (2) 2/7 (3) 11/41 (4)... View Article
If a/(b+c), b/(c+a), c/(a+b) are in AP, then (1) a,b,c are in AP (2) c,a,b are in AP (3) a2, b2,c2 are in AP (4) a,b,c are in GP. Solution:... View Article
Solution: Given a2, b2, c2 are in AP. b2-a2 = c2-b2 …(i) a/sin A = b/sin B = c/sin C = k (sine rule) a = k sin A b = k sin B c = k sin C... View Article
The sets S1 ,S2, S3,... are given by S1 = { 2/1}, S2 = { 3/2, 5/2}, S3 = { 4/3, 7/3, 10/3}, S4 = { 5/4, 9/4, 13/4, 17/4}.... Then the sum of the... View Article