If n is odd positive integer and (1+x+x^2+x^3)^n = sigma r = 0 to 3n arx^r, then a0-a1+a2-a3+...-a3n is equal to (1) 4^n (2) 1 (3) -1 (4) 0... View Article
Solution: Given α, β are the roots of x2-x+p = 0 Sum of roots, α+β = 1…(i) Product of roots, αβ = p γ, δ are the roots of x2-4x+q = 0 Sum... View Article
Solution: Let S = 1+3x+6x2+10x3 + ...∞ ..(i) Multiply by x xS = x+3x2+6x3+10x4+ ...∞ (ii) (i)-(ii) (1-x)S = 1+2x+3x2+4x3+....∞ (iii)... View Article
Solution: Since a,b,c in AP 2b = a+c x = 1 + a + a2 + ...+ ∞ This is an infinite GP. Sum = 1/(1-r) x = 1/(1-a) ..(i) y = 1 + b + b2 +... View Article
If A1, A2, G1 , G2 and H1, H2 are two AM's, GM's and HM's between two quantities, then the value of G_1G_2/H_1H_2 is (1) (A_1+A_2)/H_1+H_2 (2)... View Article
If H1 and H2 are two harmonic means between two positive numbers a and b (a not equal b), A and G are the arithmetic and geometric means between... View Article
Solution: Let a and b be the two numbers. AM = 2 GM (a+b)/2 = 2√(ab) (a+b) = 4√(ab) Squaring both sides (a+b)2 = 16ab ..(i) a2+b2-14ab =... View Article
The inflorescence of cotton is scorpioid cyme. It is a type of monochasial cyme, where lateral branches alternate on both sides of the axis.... View Article
The inflorescence of a marigold is capitulum or head. It is a type of racemose inflorescence. The peduncle is short and flattened. Flowers are... View Article