If A A1 A2 A2n B Are In Arithmetic Progression And A G1 G2 G2n B Are In Geometric Progression And Is The Harmonic Mean Of A And B Then (1) 2nh (2) n/h (3) nh (4) 2n/h Solution: Given a, a1, a2, ,...,a2n, b are in arithmetic progression. a1, a2, ,...,a2n are AMs... View Article
If Am And Hm Between Two Numbers Are 27 And 12 Respectively Then Their Gm Is (1) 9 (2) 18 (3) 24 (4) 36 Solution: Given AM = 27 HM = 12 We know GM2 = AM × HM = 27×12 = 324 GM = v324 = 18 Hence option... View Article
If A1 A2 A3 An Are In Hp Then The Expression A1a2 Plus A2a3 Plus An 1an Is Equal To (1) (n - 1) (a1 - an) (2) na1an (3) (n - 1)a1an (4) n(a1 - an) Solution: Given a1, a2, a3,...,an are in HP. So 1/a1, 1/a2, 1/a3... View Article
If The 7th Term Of Hp Is 1 By 10 And The 12th Term Is 1 By 25 Then The 20th Term Is (1) 1/41 (2) 1/45 (3) 1/49 (4) 1/37 Solution: Given 7th term of HP = 1/10 12th term = 1/25 7th term of AP = 10 12th term of AP... View Article
If A1 A2 A3 Are In A Harmonic Progression With A1 Eq 5 And A20 Eq 25 The Least Positive Integer N For Which An Less Than 0 Is (1) 22 (2) 23 (3) 24 (4) 25 Solution: Given a1, a2, a3,...are in HP. So 1/a1, 1/a2, 1/a3 are in AP. Let d be the common... View Article
In A Geometric Progression Consisting Of Positive Terms Each Term Equals The Sum Of The Next Two Terms Then The Common Ratio Of This Progression Equals (1) 1/2(1 - v5) (2) 1/2(v5) (3) v5 (4) 1/2(v5 - 1) Solution: Let a, ar, ar2 be the terms of the GP. Given a = ar+ar2 1 = r+r2... View Article
If Sum Of The Series Sigma N Eq 0 To Infinity Rn Eq S For R Less Than 1 Then The Sum Of The Series (1) S2 (2) S2/(2S + 1) (3) 2S/(S2 - 1) (4) S2/(2S - 1) Solution: S = Sn=08 rn = 1+r+r2+...8 = 1/(1-r) r = (S-1)/S Sn=08 r2n... View Article
A Man Saves Rs 200 In Each Of The First Three Months Of His Service In Each Of The Subsequent Months (1) 19 months (2) 20 months (3) 21 months (4) 18 months Solution: Saving for first 3 months = 3×200 = 600 Let the time taken to... View Article
Let A1 A2 A3 A100 Be An Arithmetic Progression With A1 Eq 3 And Sp Eq Sigma 1 To P For Any Integer N With 1 Let M Eq 5n If Sm By Sn Does Not Depend On N Then A2 Is (1) 9 (2) 2 or 4 (3) 4 or 16 (4) None of these Solution: Sum of n terms of AP = (n/2)(2a+(n-1)d Given m = 5n a = 3 Sm/Sn =... View Article
In A Triangle The Lengths Of Two Larger Sides Are 10 Cm And 9 Cm If The Angles Of The Triangle Are In Ap Then The Length Of The Third Side Is (1) v5 - v6 (2) v5 + v6 (3) v5 ± v6 (4) 5 ± v6 Solution: Let x-d, x, x+d be the 3 angles of triangle ABC in AP. Since sum of... View Article
Let Alpha And Beta Are The Roots Of The Equation Px2 Plus Qx Plus R Equal 0 P Not Eq 0 If P Q And R Are In Ap Then The Value Of (1) v61/9 (2) 2v17/9 (3) v34/9 (4) 2v13/9 Solution: Given a and ß be the roots of the equation px2 + qx + r = 0. Sum of roots, a... View Article
The Sequence Log A Log A2 By B Log A3 By B2 Is (1) GP (2) AP (3) HP (4) GP and HP Solution: log a, log a2/b, log a3/b2,... Let x = log a y = log a2/b = 2 log a - log b z =... View Article
The Four Arithmetic Means Between 3 And 23 Are (1) 5,9,11,13 (2) 7,11,15,19 (3) 5,11,15,22 (4) 7,15,19,21 Solution: Let a+d, a+2d, a+3d and a+4d be the four arithmetic means... View Article
If A B C D E F Are In Ap Then The Value Of E C Will Be (1) 2(c - a) (2) 2(f - d) (3) 2(d - c) (4) d - c Solution: Given a, b, c, d, e, f are in A.P. Let p be the common difference. b... View Article
Three Numbers Are In Ap Whose Sum Is 33 And Product Is 792 Then The Smallest Number From These Numbers Is (1) 4 (2) 8 (3) 11 (4) 14 Solution: Let a-d, a, a+d be the 3 numbers in AP. Sum = a-d+a+a+d = 33 3a = 33 a = 11 Product,... View Article
If The Sides Of A Right Angled Triangle Are In Ap Then The Sides Are Proportional To (1) 1 : 2 : 3 (2) 2 : 3 : 4 (3) 3 : 4 : 5 (4) 4 : 5 : 6 Solution: Let a-d, a, a+d be the 3 sides of the right triangle. Let a+d... View Article
If Log 2 Log 2n 1 And Log 2n Plus 3 Are In Ap Then N Equal (1) 5/2 (2) log2 5 (3) log3 5 (4) 3/2 Solution: Given log 2, log(2n - 1) and log(2n + 3) are in A.P. 2 log(2n - 1) = log 2 + log... View Article
If F X Plus Y X Y Equal Xy Then The Arithmetic Mean Of F X Y And F Y X Is (1) x (2) y (3) 0 (4) 1 Solution: f (x + y, x - y) = xy Let x+y = x …(i) x-y = y….(ii) Add (i) and (ii) 2x = x+y x = (x+y)/2... View Article
The Mean Of The Series A A Plus Nd A Plus 2nd Is (1) a + (n - 1) d (2) a + nd (3) a + (n + 1)d (4) None of these Solution: Mean of the series = (a+a+nd+a+2nd )/3 = (3a+3nd)/3 =... View Article
If A Be An Arithmetic Mean Between Two Numbers And S Be The Sum Of N Arithmetic Means Between The Same Numbers Then (1) S = nA (2) A = nS (3) A = S (4) None of these Solution: Let a and b be the two numbers Then arithmetic mean, A = (a+b)/2 Sum of n... View Article
