1) 7! x 6P3 2) 7! x 8P3 3) 7! x 3! 4) 10!/(3!.7!) Answer: (2) 7! x 8P3 Solution: Out of 10 there are three girls and 7 boys 7 boys can be... View Article
1) 500 2) 600 3) 620 4) 626 Answer: (4) 626 Solution: Given, the word MORADABAD Here we have 3A’s, 2D’s, and rest letter once Number of... View Article
1) 9(10!) 2) 2(10!) 3) 45(8!) 4) 10! Answer: (1) 9(10)! Solution: 12 persons can be arranged in a round table in 11! ways The arrangement... View Article
1) 2m+3C3 2) â…“ (m+1) (2m2+4m+1) 3) â…“ (m+1)(2m2+4m+3) 4) None of the above Answer: (3) â…“ (m+1)(2m2+4m+3) Solution: As per the given condition,... View Article
1) 360 2) 300 3) 240 4) 120 Answer: (3) 240 Solution: Given, the word BHARAT We have 6 letters here, in which letter A occur twice Total... View Article
Answer: (2) 246 Permutation and combination are the ways to represent a group of objects by selecting them in a set and forming subsets. It... View Article
1) 50 2) 100 3) 150 4) 200 Answer: (3) 150 Solution: five balls can be arranged in an order of (2,2,1) Thus, number of arrangements = 5C2... View Article
1) 16800 2) 16630 3) 1663200 4) None of these Answer: (1) 16800 Solution: The word INDEPENDENCE has 12 letters among which 5 are vowels... View Article
1) 21C7 2) 30C16 3) 21C14 4) None of these Answer: (3) 21C14 Solution: There are 8 questions which should be atleast of 2 marks. Thus total... View Article
1) 10!/6 2) 3! + 7! 3) 10P3.7! 4) None of these Answer: (1) 10!/6 Solution: A, B and C can speak among 10 persons in 10C3 ways 7 persons... View Article
1) 216 2) 240 3) 600 4) 3125 Answer: (1) 216 Solution: Given digits are 0,1,2,3,4,5. A five digit number divisible by 3 has to be formed... View Article
4) None of these Answer: (1) Solution: m men can be arranged in m! ways No two women can sit together, thus n women can be arranged in m+1... View Article
1) 64 2) 45 3) 46 4) None of these Answer: (1) 64 Solution: Selection of 3 balls out of 9 balls can be done in 9C3 ways = 84 Selection of... View Article