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Why Inductor Does Not Allow Sudden Change In Current

Inductors will not allow any sudden change in current, due to self-induced EMF within the circuit by the magnetic field. The voltage developed... View Article

What Are The Three Types Of Elasticity

Young’s modulus, Rigidity modulus and Bulk modulus are the three types of modulus of elasticity. Young’s modulus: Within the elastic limit, the... View Article

What Is Elastic Property

The ability of the objects to regain their original shape and size after the deforming force is removed is called elastic property. The maximum... View Article

If The Numbers A B C D E Form An Ap With A 1 Then A 4b Plus 6c 4d Plus E Equals

(1) 1 (2) 2 (3) 0 (4) 3 Solution: Given a, b, c, d, e form an A.P with a = 1 Let b = 1+D, c = 1+2D, d = 1+3D, e = 1+4D a - 4b + 6c - 4d + e... View Article

The Difference Between An Integer And Its Cube Is Divisible By

(1) 4 (2) 6 (3) 9 (4) None of these Solution: Let the integer is x and its cube is x3. The difference between them = x3 - x =... View Article

The Maximum Sum Of The Series 20 Plus 19 And 1 By 3 Plus 18 And 2 By 3 Plus Is

(1) 310 (2) 300 (3) 320 (4) none of these Solution: = 60/3 + 58/3 + 56/3 + ... Here d = -2/3, a = 60/3 an = a+(n-1)d = 0... View Article

If The First Term Of An Ap Be 10 The Last Is 50 And The Sum Of All The Terms Is 300 Then The Number Of Terms Are

(1) 5 (2) 8 (3) 10 (4) 15 Solution: Given first term = 10 Last term = 50 Sum of all terms = (n/2)(first term + last term) So... View Article

The Nth Term Of An Ap Is 3n 1 Choose From The Following The Sum Of Its First Five Terms

(1) 14 (2) 35 (3) 80 (4) 40 Solution: an = 3n-1 a1 = 3-1 = 2 a2 = 3×2 -1 = 6-1 = 5 Common difference, d = 5-2 = 3 Sum, Sn =... View Article

If The Sum Of N Terms Of An Ap Is 2n2 Plus 5n Then The Nth Term Will Be

(1) 4n + 3 (2) 4n + 5 (3) 4n + 6 (4) 4n + 7 Solution: Sn = 2n2 + 5n S1 = 2+5 = 7 First term = 7 S2 = 2×22 + 5×2 = 8+10 = 18... View Article

The Sum Of 1 Plus 3 Plus 5 Plus 7 Upto N Terms Is

(1) (n + 1)2 (2) (2n)2 (3) n2 (4) (n - 1)2 Solution: Sum of n odd number = 1+3+5+...2n-1 a = 1, d = 2 Sn = (n/2)(2a+(n-1)d) =... View Article

The Sum Of All Natural Numbers Between 1 And 100 Which Are Multiples Of 3 Is

(1) 1680 (2) 1683 (3) 1681 (4) 1682 Solution: Sum = 3 + 6 + 9 + ...99 Here a = 3 and d = 3 an = a+(n-1)d = 99 3+(n-1)3 = 99 3n... View Article

If The Sum Of The Series 2 Plus 5 Plus 8 Plus 11 Is 60100 Then The Number Of Terms Are

(1) 100 (2) 200 (3) 150 (4) 250 Solution: Here first term, a = 2 d = 5-2 = 3 Sn = (n/2)(2a+(n-1)d) 60100 = (n/2)(2×2+(n-1)3)... View Article

The Ratio Of The Sums Of First N Even Number And N Odd Number Will Be

(1) 1 : n (2) (n + 1) : 1 (3) (n + 1) : n (4) (n - 1) : 1 Solution: Sum of n even number = 2+4+6+...n a = 2, d = 2 Sn =... View Article

The First Term Of An Ap Is 2 And Common Difference Is 4 The Sum Of Its 40 Terms Will Be

(1) 3200 (2) 1600 (3) 200 (4) 2800 Solution: Given first term of AP, a = 2 Common difference, d = 4 Sum of n terms, Sn =... View Article

If P Times The Pth Term Of An Ap Is Equal To Q Times The Qth Term Of An Ap Then P Plus Q Th Term Is

(1) 0 (2) 1 (3) 2 (4) 3 Solution: Given p times the pth term of an A.P is equal to q times the qth term of an A.P ap = a+(p-1)d... View Article

If Twice The 11th Term Of An Ap Is Equal To 7 Times Of Its 21st Term Then Its 25th Term Is Equal To

(1) 24 (2) 120 (3) 0 (4) None of these Solution: For an AP, nth term = a+(n-1)d 11th term = a+10 d 21st term = a+20 d Twice... View Article

If A1 Equal A2 Equal 2 An Equal An 1 1 N Greater Than 2 Then A5 Is

(1) 1 (2) -1 (3) 0 (4) -2 Solution: Given a1 = a2 = 2 an = an-1 - 1 a3 = a3-1 - 1 = a2 - 1 = 2-1 = 1 a4 = a4-1 - 1 = a3 - 1... View Article

If Log3 2 Log3 2x 5 And Log3 2x 7 By 2 Are In Ap Then X Is Equal To

(1) 2 (2) 3 (3) 4 (4) 2, 3 Solution: Given log3 2, log3 (2x-5) and log3 (2x - 7/2) are in AP. So 2 log3 (2x-5) = log3 2 + log3(2x... View Article

If Nth Terms Of Two Aps Are 3n Plus 8 And 7n Plus 15 Then The Ratio Of Their 12th Terms Will Be

(1) 4/9 (2) 7/16 (3) 3/7 (4) 8/15 Solution: Let nth term of first AP = 3n+8…(i) First term, a = 3+8 = 11 (put n = 1 in (i))... View Article

If A B C Be In Ap Then A C2 By B2 Ac Equals

(1) 1 (2) 2 (3) 3 (4) 4 Solution: Since a,b,c be in A.P, So 2b = a+c b = (a+c)/2 (a-c)2/(b2-ac) = (a-c)2/((a+c)2/4)-ac) =... View Article