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What Is The Maximum Charge Of A Capacitor

The maximum charge that a capacitor can store depends on the voltage supplied to it. This is given by the equation: Q0 = CV0 The above... View Article

What Do You Mean By Zero Potential

An electric charge is said to possess zero potential when it is infinitely far away from other charges. In such cases, if the charge is moved... View Article

Which Is More Powerful Fission Or Fusion

A nuclear fusion occurs when two atoms bombard each other to form a heavier atom, as when two hydorgen atoms combine to form a helium atom. The... View Article

Does The Centre Of Mass Always Lie Within The Body

Not necessarily. The centre of mass of a circular ring, for example, lies at the ring where there is no contact of the ring.... View Article

What Happens When Dielectric Is Placed In An Electric Field

A dielectric is an insulator that conducts electric current poorly. When a dielectric material is placed in an electric field, no electric... View Article

What Is An Example Of Free Energy

Gibbs free energy is a thermodynamic potential that is used to calculate the maximum reversible work performed by a thermodynamic system at... View Article

What Is The Formula For Kepler Second Law

Kepler’s 2nd law sometimes referred to as the law of equal areas describes the speed at which any given planet will move while orbiting the sun.... View Article

Which Type Of Cell Can Be Recharged

Which of the following cells can be recharged? a) Edison Cell b) Lead Storage Cell c) Nickel Cadmium Cell d) All of the above Answer: d)... View Article

Let Vr Denote The Sum Of The First R Terms Of An Arithmetic Progression Ap Whose First Term Is R And The Common Difference Is 2r 1

Solution: Given a = r d = 2r-1 Sn = (n/2)(2a+(n-1)d) Vr = (r/2)(r+(r-1)(2r-1) = (½)(2r3-r2+r) V1+V2+V3+... = ∑Vr ∑Vr = ½ (2... View Article

If The Sum Of First 75 Terms Of An Ap Is 2625 Then The 38th Term Of An Ap

Solution: Sum of n terms of AP = (n/2)(2a+(n-1)d) The 38th term of AP = a+37d Sum of 75 terms => (75/2) (2a+74d) = 2625 (2a+74d) = 2625... View Article

Let X1 X2 Xn Be In An Ap X1 X4 X9 X11 Plus X20 X22 X27 Plus X30 272 Then X1 X30 Is Equal To

Solution: Let a be the first term and d be the common difference of AP. Given x1 + x4 + x9 + x11 + x20 + x22 + x27 + x30 = 272 ie... View Article

If 1 By B A Plus 1 By B C 1 A 1 By C Then A B C Are In

Solution: Assume a,b,c are in HP. Then 1/a, 1/b,1/c are in AP. (1/a)+(1/c) = 2/b …(i) Let d be the common difference of AP. (1/b) - (1/a)... View Article

The Sum Of The Infinite Series 1 Plus 1 By 2 Factorial Plus 1 3 4 Is Equal To

Solution: The nth term Tn = (1.3.5….(2n-1)/2n! )(2.4….2n)/(2.4….2n) = (2n)!/(2n)!2nn! = 1/2n(n)! S = 1+∑Tn = 1 + 1/2(1)! + 1/22(2)! +... View Article

The Sum Of The Infinite Series 2 2 By 2 Factorial 2 4 4 2 6 6 Factorial Is Equal To

Solution: We know ex = 1+x/1! + x2/2! + x3/3! + x4/4! +... Put x = 2 e2 = 1+ 2/1! + 22/2! + 23/3! + 24/4! +... Put x = -1 e-2 = 1- 2/1! +... View Article

The Value Of 2 By 3 Factorial Plus 4 By 5 Factorial Plus 6 7 Is

Solution: Let S be the sum of the series 2/3! + 4/5! + 6/7! +... Tn = 2n/(2n+1)! = (1/2n!) - (1/(2n+1)!) S = ∑Tn = ½! - ⅓! + ¼! - ⅕! + …... View Article

Sigma N 0 To Infinity N 2 Plus 4 By N Factorial Is Equal To

Solution: ∑n=0∞ (n2+4)/n! = ∑n=0∞ (n2/n!) + ∑n=0∞ (4/n!) = ∑n=1∞ [1/(n-2)! + 1/(n-1)!] + ∑n=0∞ 4/n! = e+e+4e (since e = 1+ 1/1! + ½! + ⅓!... View Article

1 Plus 1 By 2 Factorial Plus 2 By 3 Factorial Plus 2 2 By 4 Factorial 2 Is Equal To

Solution: Given series (1+ ½! + ⅔! + 22/4! + 23/5! + …)/(1+ 1/2! + 1/4! + 1/6!+..)...(i) We know ex = 1+x/1! + x2/2! + x3/3! + x4/4! +...... View Article

Sum Of The Series X Plus Y X Y 1 By 2 Factorial

Solution: Given series (x + y)(x - y)+(1/2!)(x+y)(x - y)(x2+y2)+(1/3!)(x + y) (x - y)(x4 + y4 + x2y2) + ... = (x2-y2)+(½!) (x4-y4) + (⅓!)... View Article

In The Expansion Of 2log E X Log E X 1 Log E X 1 The Coefficient Of X 4 Is

Solution: 2loge x - loge (x + 1) - loge (x - 1) = 2loge x -loge((1+1/x)x) - loge ((1-1/x)x) = 2loge x - [log (1+1/x) + log x] - [loge... View Article

1 By 2 1 By 2 2 Square 1 3 2 3 1 4 Square 4 Is Equal To

(1) ¼ (2) loge (¾) (3) loge (3/2) (4) loge (⅔) Solution: We use log (1+x) = x-x2/2 +x3/3 - x4/4+... Put x = ½ log (1+½ ) = ½ -... View Article

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