1) a . b = b . c = c . b = 0 2) a × b = b × c = c × a 3) a . b = b . c = c . a = 0 4) a × a + a × c + c × a = 0 Answer: 2) a × b = b × c = c... View Article
1) π/6 2) π/3 3) π/2 4) π/4 Answer: (2) π/3 Solution: As per the given question, if a and b are two vectors, then, |a x b| = √3|a.b|... View Article
Let a=a1i+a2j+a3k, b=b1i+b2j+b3k and c=c1i+c2j+c3k be three non-zero vectors such that c is a unit vector perpendicular to both a and b. If the... View Article
1) 4√6 units 2) 1/2 (√21) sq units 3) √6/2 sq units 4) √6 units Answer: Solution: Given, a=i+j+k,b=i+3j+5k and c=7i+9j+11k Suppose, a... View Article
1) √3/√2 2) √2/√3 3) 4/√3 4) 2√2/√3 Answer: (1) √3/√2 Solution: Suppose n is the normal vector perpendicular to the plane containing i+j+k... View Article
1) exactly two values of θ 2) more than two values of θ 3) no value of θ 4) exactly one value of θ Answer: (4) exactly one value of θ... View Article
1) Statement I is correct, Statement II is correct; Statement II is correct explanation for Statement I 2) Statement I is correct, Statement II... View Article
1) 0 2) 1 3) a × b 4) b × a Answer: (1) 0 Solution: Given, (2a + 3b) × (5a + 7b) + a × b = 2a x (5a+7b) + 3b x (5a + 7b) + a x b = 10 (a... View Article
1) a . b 2) 1 3) 0 4) ½ Answer: (4) ½ Solution: We can write; (a x b)2 = (a x b).(a x b) = (|a| |b| sin θ). (|a| |b| sin θ) = |a|2.|b|2... View Article
1) 5 2) 1 3) 6 4) 8 Answer: (3) 6 Solution: Suppose, A, B and C are the position vectors of vertices 0, a+b and a-b. As we know, Area of... View Article
1) 6 (b × c) 2) 3 (b × c) 3) 2 (b × c) 4) 0 Answer: (1) 6 (b × c) Solution: Given, (a + 2b + 3c) = 0 a x b + 2b x b + 3c x b = 0 a x b +... View Article
1) π/3 2) π/2 3) π/4 4) π/6 5) 0 Answer: (1) π/3 Solution: Given, projection of the vector a on b is |a × b| So, |a x b| = a.( b/|b|) And... View Article