For All X Y R The Value Of 1 X X2 1 Y Y2 Xy Eq (1) < 9 (2) ≤ 9 (3) >9 (4) ≥ 9 Solution: Let a = 1, b = x and c = x2 We know AM ≥ GM. So (a+b+c)/3 ≥ (abc)1/3... View Article
If Two Arithmetic Means A1 A2 Two Geometric Means G1 G2 And Two Harmonic Means H1 H2 Are Inserted Between Two Numbers P And Q Then If two arithmetic means A1, A2, two geometric means G1, G2 and two harmonic means H1, H2 are inserted between two numbers p and q then (1)... View Article
Find A B And C Between 2 And 18 Such That A B C 25 2 A B Are In Ap And B C 18 Are In Gp (1) 5, 8, 12 (2) 4, 8, 13 (3) 3, 9, 13 (4) 5, 9, 11 Solution: Given a + b + c = 25 …(i) Since 2,a,b are in A.P 2a = 2+b a =... View Article
If 100 Times The 100th Term Of An Ap With Non Zero Common Difference Equals The 50 Times Its 50th Term Then The 150th Term Of This Ap Is (1) –150 (2) 150 times its 50th terms (3) 150 (4) Zero Solution: Let a be the first term and d be the common difference of an AP.... View Article
If S1 A2 A4 A6 Upto 100 Terms And S2 A1 A3 A5 Upto 100 Terms Of A Certain Ap Then Its Common Difference Is (1) S1 – S2 (2) S2 – S1 (3) (S1 – S2)/2 (4) None of these Solution: Let d be the common difference of an AP. d = a2-a1 = a4-a3 =... View Article
If The Sum Of Three Consecutive Terms Of An Ap Is 51 And The Product Of Last And First Term Is 273 Then The Numbers (1) 21,17,13 (2) 20,16,12 (3) 22,18,14 (4) 24,20,16 Solution: Let a-d, a, a+d are the three numbers. Sum = 3a = 51 a = 51/3 = 17... View Article
If The Sum Of Three Numbers Of An Arithmetic Sequence Is 15 And The Sum Of Their Squares Is 83 Then The Numbers Are (1) 4,5,6 (2) 3,5,7 (3) 1,5,9 (4) 2,5,8 Solution: Let a-d, a, a+d are the three numbers. Then sum = a-d+a+a+d = 15 3a = 15 a =... View Article
After Inserting N Ams Between 2 And 38 The Sum Of The Resulting Progression Is 200 (1) 10 (2) 8 (3) 9 (4) None of these Solution: Given first term, a = 2 Last term, b = 38 If n terms are inserted between a and b... View Article
The Sum Of N Arithmetic Means Between A And B Is (1) n(a+b)/2 (2) n(a+b) (3) (n+1)(a+b)/2 (4) (n+1)(a+b) Solution: Let A1, A2, ...An be the arithmetic means between a and b. So... View Article
The Arithmetic Mean Of First N Natural Number (1) (n-1)/2 (2) (n+1)/2 (3) n/2 (4) n Solution: We know sum of first n natural numbers, (1+2+3+...n) = n(n+1)/2 Arithmetic mean... View Article
A Number Is The Reciprocal Of The Other If The Arithmetic Mean Of The Two Numbers Be 13 12 Then The Numbers Are (1) 1/4, 4/1 (2) 3/4, 4/3 (3) 2/5, 5/2 (4) 3/2, 2/3 Solution: Let x be the number. Then the reciprocal = 1/x AM = (x+ 1/x)/2 =... View Article
If An 1 B N 1 By An Bn Be The Am Of A And B Then N Eq (1) 1 (2) -1 (3) 0 (4) none of these Solution: Arithmetic mean of a and b, AM = (a+b)/2 Given AM = (an+bn)/(an-1 +bn-1) =>... View Article
If 3 5 7 N Terms 5 8 11 10 Terms 7 Then The Value Of N Is (1) 35 (2) 36 (3) 37 (4) 40 Solution: Given (3+5+7+... n tems)/(5+8+11+...10 terms) = 7 Consider (3+5+7+... n tems) This is an... View Article
The Sum Of The First Four Terms Of An Ap Is 56 The Sum Of The Last Four Terms Is 112 If Its First Term Is 11 The Number Of Terms Is (1) 10 (2) 11 (3) 12 (4) None of these Solution: Let a, a+d, a+2d, a+3d are the terms in AP. Given a = 11 Sum of the first four... View Article
The First Term Of An Ap Of Consecutive Integers Is P2 1 The Sum Of 2p 1 Terms Of This Series Can Be Expressed As (1) (P + 1)2 (2) (p + 1)3 (3) (2p + 1)(p + 1)2 (4) p3 + (p + 1)3 Solution: Given first term of AP, a = p2+1 Here d = 1, since... View Article
Let Sn Denotes The Sum Of N Terms Of An Ap If S2n Eq S3n Then Ratio (1) 4 (2) 6 (3) 8 (4) 10 Solution: Let a be the first term and d be the common difference of an AP. Sn = (n/2)(2a+(n-1)d) Given... View Article
If Sn Np 1 2 N N 1 D Where Sn Denotes The Sum Of The First N Terms Of An Ap Then The Common Difference Is (1) P+Q (2) 2Q (3) Q (4) 2P+3Q Solution: Let a be the first term and d be the common difference of an AP. Sn = (n/2)(2a+(n-1)d)... View Article
If Sk Denotes The Sum Of First K Terms Of An Arithmetic Progression Whose First Term And Common Difference Are A And B Respectively Then Skn Sn Be Independent Of N If (1) 2a – d = 0 (2) a – d = 0 (3) a – 2d = 0 (4) None of these Solution: The sum of n terms of an arithmetic progression, Sn =... View Article
The Solution Of Log Root 3 X Log4 Root 3 X Log16 Root 3 X Eq 36 Is The solution of (1) x = 3 (2) x = 4√3 (3) x= 9 (4) x = √3 Solution: We know loga b = log b/log a Also log ab = b log a... View Article
If Sn Denotes The Sum Of N Terms Of An Arithmetic Progression Then The Value Of S2n Sn Is Equal To 1) 2Sn 2) S3n 3) S3n/3 4) Sn/2 Solution: The sum of n terms of an arithmetic progression, Sn = (n/2)(2a+(n-1)d) S2n =... View Article