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Ncr N1cr Rcr

1) n+1Cr 2) n+1Cr+1 3) n+2Cr 4) 2n Answer: (2) n+1Cr+1 Solution: nCr+n-1Cr+...+rCr = nCr+n−1Cr+n−2Cr+.....+r+1Cr+rCr =... View Article