Archives

4 Plus 18 Plus 48 N Terms Equal

(1) n(n+1)(n+2)(3n+5)/12 (2) n(n+1)(n+2)(5n+3)/12 (3) n(n+1)(n+2)(7n+1)/12 (4) n(n+1)(n+2)(9n-1)/12 Solution: 4 + 18 + 48 + ... n... View Article

1 Plus 3 Plus 7 Plus 13 100 Terms Eq

(1) 1010000/2 (2) 1000200/3 (3) 1015050/3 (4) 1051050/3 Solution: Let Sn = 1 + 3 + 7 + 13 + ... an …(i) Sn = 1 + 3 + 7 + 13 + ...... View Article

If S1 S2 S3 Sn Are The Sums Of Infinite Gps Whose First Terms Ars 1 2 3 N And Whose Common Ratios Are

(1) n(n+3)/2 (2) n(n+4)/2 (3) n(n-3)/2 (4) n(n+1)/2 Solution: ∑i = 1nSi = ∑i = 1na/(1-r) S1 = 1/(1-½) = 2 S2 = 2/(1-1/3) = 3 S3... View Article

If M Plus 1 Th N Plus 1th And R Plus 1 Th Terms Of An Ap Are In Gp And M N R Are In Hp Then The Common Difference Of The Ap Is

(1) -a/n (2) -n/2a (3) 2a/n (4) -2a/n Solution: Given m, n, r are in HP. So 2/n = (r+m)/mr mr = n(m+r)/2 (m+r) = 2mr/n…(i)... View Article

Am Of The Three Numbers Which Are In Gp Is 14 By 3 If Adding 1

(1) 91 (2) 80 (3) 84 (4) 88 Solution: Let a, ar, ar2 be the numbers in GP. Given AM = 14/3 So (a+ar+ar2)/3 = 14/3 a+ar+ar2 = 14... View Article

If The Harmonic Mean And Geometric Mean Of Two Numbers A And B Are 4 And 3 Root 2 Respectively Then The Interval A B Equal

(1) [3, 6] (2) [2, 7] (3) [4, 5] (4) [1, 8] Solution: Given HM = 4 2ab/(a+b) = 4 …(i) GM = 3√ 2 √(ab) = 3√ 2 ab = 18... View Article

If The Am Of 2 Numbers A And B Is Equal To Root 10 Times Their Gm Then A B By A Plus B Equal

(1) √10/3 (2) 3√10 (3) 9/10 (4) 3/√10 Solution: Given AM = √10 GM (a+b)/2 = √10√(ab) (a+b)2/4 = 10ab (a+b)2 = 40 ab a2+2ab+b2... View Article

1 By 2 Plus 3 By 4 Plus 7 By 8 Plus 15 By 16 Plus 100 Terms Equal

(1) 2100+99 (2) 2-100+99 (3) 2-101+99 (4) 2-99+99 Solution: 1/2 + 3/4 + 7/8 + 15/16 +....100 terms = (1-½)+(1-¼) +(1-⅛) +....100... View Article

A Particle Begins At The Origin And Moves Successively In The Following Manner As

(1) 4/3, 2/3 (2) 4/3, 2/5 (3) 3/2, 2/3 (4) 2, 2/5 Solution: Consider x axis S = 1+¼ + 1/16+... This is an infinite GP with... View Article

If A B C Are Non Zero Real Numbers Such That 3 A2 B2 C2 1 Equal 2 A B C Ab Bc Ca Then A B C Are In

(1) AP (2) GP (3) AP ,GP, HP (4) AP as well as GP Solution: Given 3(a2+b2+c2+1) = 2(a+b+c+ab+bc+ca) 3a2+3b2+3c2+3-2a-2b-2c-2ab-2bc-2ac = 0... View Article

If X Y Z Are Real Numbers Satisfying The Expression 25 9×2 Y2 Plus 9z2 15 5xy Yz 3xz Equal 0 Then X Y Z Are In

(1) AP (2) GP (3) HP (4) AGP Solution: 25(9x2+y2)+9z2-15(5xy+yz+3xz) = 0 (15x)2+(5y)2+(3z)2 -15x(5y) - 5y(3z) -3z(15x) = 0... View Article

If A1 A2 A3 A4 A5 Are In Ap With Common Difference Not Equal 0 Then Find The Value Sigma I Equal 1 To 5ai When A3 Equal 2

(1) 10 (2) 5 (3) 20 (4) None of these Solution: a3 = 2 a+2d = 2 So a = 2-2d a2 = a+d = 2-d a4 = a+3d = 2-2d+3d = 2+d a5 =... View Article

M	T	W	T	F	S	S
				1	2	3
4	5	6	7	8	9	10
11	12	13	14	15	16	17
18	19	20	21	22	23	24
25	26	27	28	29	30	31

Archives

4 Plus 18 Plus 48 N Terms Equal

1 Plus 3 Plus 7 Plus 13 100 Terms Eq

If S1 S2 S3 Sn Are The Sums Of Infinite Gps Whose First Terms Ars 1 2 3 N And Whose Common Ratios Are

If M Plus 1 Th N Plus 1th And R Plus 1 Th Terms Of An Ap Are In Gp And M N R Are In Hp Then The Common Difference Of The Ap Is

Am Of The Three Numbers Which Are In Gp Is 14 By 3 If Adding 1

If The Harmonic Mean And Geometric Mean Of Two Numbers A And B Are 4 And 3 Root 2 Respectively Then The Interval A B Equal

If The Am Of 2 Numbers A And B Is Equal To Root 10 Times Their Gm Then A B By A Plus B Equal

1 By 2 Plus 3 By 4 Plus 7 By 8 Plus 15 By 16 Plus 100 Terms Equal

A Particle Begins At The Origin And Moves Successively In The Following Manner As

If A B C Are Non Zero Real Numbers Such That 3 A2 B2 C2 1 Equal 2 A B C Ab Bc Ca Then A B C Are In

If X Y Z Are Real Numbers Satisfying The Expression 25 9×2 Y2 Plus 9z2 15 5xy Yz 3xz Equal 0 Then X Y Z Are In

If A1 A2 A3 A4 A5 Are In Ap With Common Difference Not Equal 0 Then Find The Value Sigma I Equal 1 To 5ai When A3 Equal 2

The Number Of Common Terms Of The Sequence 17 21 25 417 And 16 21 26 466 Is

If First Fifth And Last Terms Of An Ap Is L M P Respectively And Sum Of The Ap Is L Plus P 4p M 5l By K M L Then K Is

If Sr Denotes The Sum Of R Terms Of An Ap And Sa By A2 Equal Sa By B2 Equal C Then Sc Is

Does Sodium Explode In Air

What Is Momentum And Its Importance

Are Metal Oxides Bases

How Do You Identify A Chemical Bond

Are Halogens Reactive With Water

FREE TEXTBOOK SOLUTIONS