1) {2-√2, 2√2} 2) {1 / 3, 3} 3) {1 / 4, 4} 4) None of these Solution: (1) {2-√2, 2√2} The given equation can be written as [log 2] / [log x]... View Article
1) - d / a 2) c / a 3) b / a 4) None of these Solution: (1) - d / a Since x2 + x + 1 is a factor of ax3 + bx2 + cx + d (ax3 + bx2 + cx + d)... View Article
1) x ∈ R 2) x ∈ N 3) x ∈ I 4) x ∈ Q Solution: (3) x ∈ I Let x = K + I, where K is an integer and I is a proper fraction. (x + 1) = (K + 1 +... View Article
1) x = 1 2) x = 2 3) x = 0 4) None of these Solution: (2) x = 2 Clearly x = 2 satisfies the given equation. (1 / 2)x + (√3 / 2)x = 1 (cos (π... View Article
1) a + b 2) a - b 3) (√a ± √b)2 4) None of these Solution: (3) (√a ± √b)2 p / 2x = a / (x + c) + b / (x - c) = [ax - ac + bx + bc] / [x2 -... View Article
1) 0 2) 4 3) 2 4) None of these Solution: (3) 2 (6 - x)4 + (8 - x)4 = 16 Put y = [6 - x + 8 - x] / 2 = 7 - x x = 7 - y The given equation... View Article
1) a, b, d 2) b, c, d 3) a, b, c 4) a + d, b + d, c + d Solution: (3) a, b, c Since ɑ, β, 𝛾 are the roots of (x - a) (x - b) (x - c) - d =... View Article
1) a ∈ (4, 5] 2) a ∈ (0, 4) 3) a ∈ (4, ∞) 4) None of these Solution: (1) a ∈ (4, 5] The given equation can be written as (2x)2 - (a - 3) 2x... View Article