1. Which of the following set represent correct formula for Malachite, Magnetite, Calamine & Cryolite?
a) CuCO3, Fe2O3, ZnO, Al2O3
b) CuCO3,Cu(OH), Fe3O4, ZnCO3, Na3 AlF6
c) CuCO3, Fe3O4, ZnCO3, Al2O3
d) CuCO3.Cu(OH), Fe2O3, ZnCO3, Na3AlF6
Malachite → CuCO3.Cu(OH)2
Magnetite → Fe3O4
Calamine → ZnCO3
Cryollite → Na3AlF6
Answer: (b)
Answer is (1)
By definition, λmα (1/√C)
Answer: (b)
a) Cr(BO2)3
b) Cr2O3
c) CrB
d) CrBO3
Answer: (a)
By definition,
Enthalpy of formation is defined as the Enthalpy change occurring when, a compound is formed from its constituent elements in standard state.
Answer: (B, C)
P + Cl–
P + Me3N
P + CuCl2
Then which of the following is/are correct.
a) Y contains co-ordinate bond
b) X is sp3 hybridised.
c) Oxidation state of Sn is X is +1.
d) X contain lone pair on central atom.
Answer: (a, b, d)
a) x1 is deflected toward negatively charged plate.
b) x2 is β-particle.
c) x3 is γ-radiation.
d) z is isotope of 238U
x1 -> α – decay
x2 -> β – decay
x3 -> β – decay
x4 -> α – decay
Answer: (a, b, d)
a) W & Z are coloured
b) W is diamagnetic and Z is paramagnetic
c) Both W & Z are tetrahedral in shape
d) Both W & Z involve pπ-dπ bonding for π bond
Answer: (a, c, d)
Answer: (1, 4)
a) Monosachharides can not be hydrolysed to give polyhydroxy aldehydes and ketones.
b) Hydrolysis of sucrose gives dextrorotatory glucose and laevorotatory fructose
c) Oxidation of glucose with bromine water gives glutamic acid.
d) The two six membered hemiacetal form of D(+) glucose are anomers.
Answer is: (a, b, d)
a) BF, O3, SF6, XeF6
b) BeCl2, CO2, BCl3, CHCl3
c) SO2, C6H5Cl, H2Se, BrF5
d) NO2, NH3, POCl3, CH3Cl
For Option c
Answer: (c, d)
a) Eav is doubled when its temperature is increased 4 times
b) Urms is inversely proportional to the square root of its molecular mass
c) Eav at a given temperature doesn’t depend on its molecular mass
d) Urms is doubled when its temperature is increased 4 times
Eav = (3/2)RT [independent of mass)
urms =
Answer: (b, c, d)
19
Distorted octahedral shape.
When equal volume of 0.06 M Fe+2 and 0.2 M S-2 solution are mixed, then equilibrium concentration of Fe+2 is found to be Y × 10-17 M. Y is:
|
Ini |
0.06 |
0.2 |
0 |
|
After mix |
0.03 |
0.1 |
|
|
At 0 q/m |
x |
0.07 |
15.Schemes 1 and 2 describe the conversion of P to Q and R to S, respectively. Scheme 3 describes the synthesis of T from Q and S. The total number of Br atoms in a molecule of T is _____
Total Br atoms = 4
16. Which of the following compounds contain bond between same type of atoms.
N2O4, B3 N3H6, H2S2O3, N2O, H2S2O8, B2H6
Answer: N2O4, H2S2O3, N2O, H2S2O8
When [A] = 0.15
[B] = 0.25 [C] = 0.15Rate of reaction is Y × 10-5 m/s. Find Y.
Let
From (1), (2) -> y = 0
(1), (3) -> z = 1
(1), (4) -> x = 1
Therefore, rate law becomes
From (2)
K = 3 x 10-3
When [A] = 0.15, [B] = 0.25, [C] = 0.15
r = 3 x 10-3 [0.15]1 [0.15]1
= 6.75 x 10-5 moll-1 s-1
So, y x 10-6
Hence, y = 6.75
Answer: (6.75)
Therefore, M = 64 g
Video Lessons – Paper 1 Chemistry
JEE Advanced 2019 Chemistry Paper 1 Solutions
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