JEE Advanced Question Paper 2019 Chemistry Paper 2 is available here. Students can easily download these solutions from here in PDF format to practice offline. Practising these solutions will help students to improve their speed and accuracy, and they have an idea of what type of questions are asked from each chapter. Solving previous year question papers is an important aid for the students to analyze their performance. Students are advised to solve last year’s papers to crack the JEE Advanced.
Paper 2 – Chemistry
1. With reference to aqua regia, choose the correct option(s):
a) Aqua regia is prepared by mixing conc. HCl and conc. HNO3 in 3: 1 molar ratio.
b) Reaction of gold with aqua regia produces an anion having Au in +3 oxidation state.
c) Reaction of gold with aqua regia produces NO2 in the absence of air
d) The yellow colour of aqua regia is due to the presence of NOCl & Cl2.

JEE Advanced Question Paper 2019 Chemistry Paper 2

a) Aqua regia is HCl & HNO3 (conc.) in a 3 : 1

b) Oxidation state of Au in [AuCl4]- is +3.

c) NOCl/NO is formed

d) NOCl is yellow in colour

Answer: (a, b, d)

2. Choose the correct option that gives aromatic compound as major product:
JEE Advanced Question Paper 2019 Paper 2 Chemistry


JEE Advanced Solved Question Paper 2019 Chemistry Paper 2

Answer: a, b

3. Which of the following reaction produce propane as major product?
Solved JEE Advanced Question Paper 2019 Chemistry Paper 2


Solved JEE Advanced Chemistry Paper 2 Question Paper 2019

Answer: c, d

4. Which of the following is/are correct
a) Teflon is formed by polymerization of tetrafluoroethene.
b) Natural rubber is the trans from of polyisoprene.
c) Cellulose contains only α-D-glucose linkage
d) Nylon-6 contains amide linkage.

a)Fact

b) Natural rubber is Cis form of polyisoprene

c) Cellulose contains B – 1, 4 – glycosidic linkage

d) Nylon 6 contains amide linkage.

Solution: (a, d)

5.Choose the correct option(s) for the following reaction sequence.

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 5

Consider Q, R and S as major products


JEE Advanced Question Paper 2019 Chemistry Paper 2 Solutions

Answer: a, b

6. Consider the following reaction(unbalanced)

Zn + Hot conc.JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 6

Zn + conc.JEE Advanced Question Paper 2019 Chemistry Paper 2 Solutions 6

JEE Advanced Question Paper 2019 Chemistry Paper 2 Answer 6(precipitate) X + Y

Choose the correct option(s)


a) R is a V-shaped molecule
b) Z is dirty white in colour
c) Bond order of Q is 1 in its ground state
d) The oxidation state of Zn in T is +1

Solution for JEE Advanced Question Paper 2019 Chemistry Paper 2 Question 6

a) SO2 is v shaped.

b) ZnS is dirty white in colour.

c) Bond order of H2 is 1.

d) Oxidation state of Zn in Na2ZnO2 is +2.

Answer: a, b, c

7. In the Mac. Arthur process of extraction
JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 7

a) R is [Au(CN4)](-)
b) Z is [Zn(CN)4]2-
c) Q is O2
d) Y is Zn

Answer: b, c, d

8. For He+ the electron is in orbit with energy equal to 3.4eV. The azimuthal quantum number for that orbit is 2 and magnetic quantum number is 0. Then which of the following is/are correct.
a) The subshell is 4d.
b) The number of angular nodes in it is 2.
c) The numbers of radial nodes in it is 3.
d) The nuclear charge experienced in n = 4 is 2e less than that in n = 1, where e is electric charge.

\(\begin{array}{l}E = E_0 \frac{z^2}{n^2}\end{array} \)

3.4 = 13.6 x 4/n2

n = 2

l = 2

a) Subshell is 4 d

b) Number of angular nodes is 2

c) Number of radial nodes is 1.

d) Nuclear charge would be the same.

Answer: a, b

9. Calculate the total number of cyclic ether (including stereo) having formula C4H8O.

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 9

Total 10

10. 1 mole of Rhombic sulphur is treated with conc. HNO3. Find the mass of H2O formed.

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 10

Balancing

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solutions 10

∴ Mass of H2O = 288

11. Mole fraction of urea in 900 gram water is 0.05. Density of Solution is 1.2 g/cm3. Find molarity of Solution.

Number of moles of H2O = 900/18 = 50

n1/(n1+50) = 0.05

(n1 is No. of moles of urea)

=> n1 = 2.63

Weight of urea = 2.63 × 60 = 157.8 g

Total weight = 157.8 + 900 = 1057.8g

Volume = 1057.8/1.2 = 881.5 cm3

Molarity = 2.63/0.8 = 2.99

12. Number of hydroxyl group in compound ‘Y’ is:

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 12

Total 6 – OH groups.

13. In following reaction the value of K is 5 × 10-4 S-1.
JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 13

Initial pressure was 1 atm, while the final pressure was 1.45 atm at time y × 103 sec calculate ‘y’.



JEE Advanced Question Paper 2019 Chemistry Paper 2 Solutions 13

t = 0

1

0

0

t = t

1 – P

P

P/2

t = ∞

0

1

0.5

P0 = 1 atm, Pt = 1.45 atm, P = 1 atm

\(\begin{array}{l}t = \frac{1}{2K}ln(\frac{P_{\infty} – P_0}{P_{\infty} – P_1})\end{array} \)

= 2.3 x 103

This implies, y = 2.3

14. Number of N-Mn-Cl bonds [N-Mn bonds is cis to Mn-Cl bond] in cis [Mn(en)2Cl2] are …….

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 14

This is the Cis form of [Mn(en)2Cl2]

Therefore, No. of N–Mn–Cl bonds = 6

15. Match the column
JEE Advanced Question Paper 2019 Chemistry Paper 2 Question 14

Which of the following is correct


a) P I
b) P II
c) P V
d) P III

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 15

Answer: (c)

16. Which of following is correct.
JEE Advanced Question Paper 2019 Chemistry Paper 2 Question 14

a) S IV
b) R I
c) R II
d) S III

K.E. directly proportional to Z2/n2

Answer: (c)

Answer the question no. 17 & 18 on the basis of information given in Column – I & Column – II. Match the reactant in column – I with the possible intermediates and products of Column – II.

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 16
17. Which of the following is correct?
a) P – II, III; S – II, III
b) P – II, IV; S – II, III
c) P – III, VI; S – II, III
d) P – I, III; S – IV, V

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 17

Answer: (a)

18. Which of the following is correct?
a) Q – I, IV, VI; R – II, III, V
b) Q – I, III, VI; R – II, IV, V
c) Q – I, II, VI; R – II, III, VI
d) Q – I, IV, V; R – III, I, V

JEE Advanced Question Paper 2019 Chemistry Paper 2 Solution 18

Answer: (a)

Video Lessons – Paper 2 Chemistry

JEE Advanced 2019 Chemistry Paper 2 Solutions

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