Class 10 Maths Chapter 13 Surface Areas and Volumes MCQs

Class 10 Maths Chapter 13 (Surface areas and volumes) MCQs are provided here online, along with their solutions, for students who are preparing for the board exams. These objective questions are presented here, chapter-wise, with detailed explanations, as per CBSE and NCERT curriculum, by which students can easily score good marks.

Class 10 Maths MCQs for Surface Areas and Volumes

1. The shape of an ice-cream cone is a combination of:

(a)Sphere+cylinder

(b)Sphere+cone

(c)Hemisphere+cylinder

(d)Hemisphere+cone

Answer: d

2. If a cone is cut parallel to the base of it by a plane in two parts, then the shape of the top of the cone will be a:

(a)Sphere

(b)Cube

(c)Cone itself

(d)Cylinder

Answer: c

Explanation: If we cut a cone into two parts parallel to the base, then the shape of the upper part remains the same.

3. If we cut a cone in two parts by a plane parallel to the base, then the bottom part left over is the:

(a)Cone

(b)Frustum of cone

(c)Sphere

(d)Cylinder

Answer: b

Explanation: See the figure below
Surface areas and volumes MCQs

4. If r is the radius of the sphere, then the surface area of the sphere is given by;

(a)4 π r2

(b)2 π r2

(c)π r2

(d)4/3 π r2

Answer: a

5. If we change the shape of an object from a sphere to a cylinder, then volume of cylinder will

(a)Increase

(b)Decrease

(c)Remains unchanged

(d)Doubles

Answer: c

Explanation: If we change the shape of a three dimensional object, the volume of the new shape will be same.

6. Fifteen solid spheres are made by melting a solid metallic cone of base diameter 2cm and height 15cm. The radius of each sphere is:

(a)½

(b)¼

(c)1/3√2

(d)1/3√4

Answer: d

Explanation: Volume of ten sphere = Volume of cone

15×4/3 π r3= ⅓ πr2h

5×4 π r3=⅓ π 12(15)

20r3=5

r3=5/20=¼

r=1/3√4

7. The radius of top and bottom of a slant height 35 cm are 25 cm and 8cm. The curved surface of the bucket is:

(a)4000 sq.cm

(b)3500 sq.cm

(c)3630 sq..cm

(d)3750 sq.cm

Answer: c

Explanation: Curved surface of bucket = π(R1+R2) x slant height (l)

Curved Surface = (22/7) x (25+8) x 35

C.S = 22 x 33 x 5 = 3630 sq. cm.

8. If a cylinder is covered by two hemisphere shaped lid of equal shape, then the total curved surface area of the new object will be

(a)4πrh+2πr2

(b)4πrh-2πr2

(c)2πrh+4πr2

(d)2πrh+4πr

Answer: c

Explanation: Curved surface area of cylinder = 2πrh

Curved surface area of hemisphere = 2πr2

Here, we have two hemisphere.

So, total curved surface area = 2πrh+2(2πr2) = 2πrh+4πr2

9. A tank is made of shape of cylinder with a hemispherical depression at one end. The height of cylinder is 1.45 m and radius is 30cm. The total surface area of tank is:

(a)30m

(b)3.3m

(c)30.3m

(d)3300m

Answer: b

Explanation: Total surface area of tank = CSA of cylinder + CSA of hemisphere

= 2πrh + 2πr2= 2π r(h + r)

= 2 x 22/7 x 30(145+30) cm2

=33000 cm2

= 3.3 m2

10. If we join two hemispheres of same radius along their bases, then we get a;

(a)Cone

(b)Cylinder

(c)Sphere

(d)Cuboid

Answer: c

2 Comments

  1. pacha bharath kumar

    i have to improve in chemistry so please help

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