**Class 8 Maths Chapter 5 Data Handling MCQs (Questions and Answers)** are available here online for students. These objective questions are prepared by our experts, as per the **CBSE syllabus (2021-2022) **and **NCERT** guidelines. The chapter-wise MCQs are provided at BYJU’S to make every student understand each concept and help them to score better marks in exams. Also, learn important questions for class 8 Maths here.

Practice more and test your skills on Class 8 Maths Chapter 5 Data Handling MCQs with the given PDF here.

Class 8 Maths Chapter 5 Data Handling MCQs Questions – Download PDF |

## MCQs on Class 8 Data Handling

Multiple Choice Questions (MCQs) are available for Class 8 Chapter 5 Data Handling chapter here. Each question contains four options, out of which one is the correct answer. Students have to observe the problem and choose the correct answer.

**1. Pictorial representation of data using symbols is known as:**

A. Bar graph

B. Pictograph

C. Pie chart

D. None of these

Answer: **B**

**2. Double bar graphs display ______ sets of data simultaneously.**

A. Four

B. Three

C. Two

D. No

Answer: **C**

**3. _________ gives the number of times a particular entry occurs.**

A. Organisation of data

B. Collection of Data

C. Representation of Data

D. Frequency distribution table

Answer: **D**

**4. In the grouped data, each of the group is called:**

A. Class interval

B. Collection of data

C. Frequency

D. Grouped frequency distribution

Answer: **A**

**5. If 20-30 is the class interval of grouped data, then the lower class limit is:**

A. 50

B. 30

C. 20

D. 10

Answer: **C**

**6. The difference between the upper-class limit and lower class limit of a class interval is called:**

A. Frequency

B. Width

C. Grouped data

D. Ungrouped data

Answer: **B**

**7. The width or size of the class interval 30-40 is:**

A. 10

B. 30

C. 40

D. 70

Answer: **A**

Explanation: Width of class interval = upper class limit-lower class limit

= 40 – 30

= 10

**8. If a coin is flipped in the air, what is the probability of getting a tail?**

A. 0

B. ½

C. 1

D. 2

Answer: **B**

Explanation: A coin has two sides, Head and tails.

Probability = Number of possible outcomes/Total number of outcomes

We know that the tail is present on one side of a coin and in total there could be two outcomes H & T.

Hence, the probability of getting a tail = ½

**9. A bag has 4 red balls and 4 green balls, what is the probability of getting a red ball randomly?**

A. 1/4

B. 1/8

C. 1/2

D. 0

Answer: **C**

Explanation: Total number of balls in bag = 4 + 4 = 8

Total number of red balls = 4

Probability of getting a red ball = 4/8 = ½

**10. If a die is thrown in the air, the probability of getting even numbers is:**

A. ½

B. ⅙

C. ⅓

D. ⅔

Answer: **A**

Explanation: A die has six sides each consisting numbers from 1 to 6, i.e. {1, 2, 3, 4, 5, 6}.

Total possible outcomes = 6

Number of even numbers on a die = 3

i.e. {2, 4, 6}

Probability = 3/6 = 1/2

**Check the given table, and give the correct answers to the following questions.**

Range of Marks Obtained | Number of students |

250 – 300 | 10 |

300 – 350 | 12 |

350 – 400 | 14 |

400 – 450 | 13 |

450 – 500 | 11 |

**11. What is the total number of students for all ranges?**

A. 12

B. 14

C. 50

D. 60

Answer: D. 60

Explanation: Total number of students = 10 + 14 + 12 + 13 + 11 = 60

**12. How many students secured marks between 250 – 300?**

A. 10

B. 11

C. 13

D. 14

Answer: A

**13. What is the upper limit in the given frequency distribution table?**

A. 350

B. 450

C. 500

D. 400

Answer: A. 500

Explanation: The last class has the upper limit of 500, which is the upper limit for the whole table.

**14. How many students come under the marks range of 300 – 400?**

A. 12

B. 26

C. 14

D. 25

Answer: B.24

Explanation:

Number of students from 300 – 350 = 12

Number of students from 350 – 400 = 14

Thus, the total number of students from 300 – 400 = 12 + 14 = 26

**15. What is the size of the class interval?**

A. 30

B. 40

C. 50

D. 55

Answer: C. 50

Explanation: For any class, we can determine the class interval, by subtracting the lower limit from upper limit.

500 – 450 = 50

450 – 400 = 50

**16. A die is thrown. What is the probability of getting even prime number?**

A. ⅙

B. ½

C. ⅓

D. ⅕

Answer: A. 1/6

Explanation: When a die is thrown,

Number of total possible outcomes = 6

Number of even prime numbers = 1 (2 is the only even prime number)

Thus, the probability of getting a even prime number,

P = 1/6

**17. When a coin is tossed, what are the possible outcomes?**

A. 1

B. 2

C. 3

D. 0

Answer: B

Explanation: The possible outcomes are Head and Tail.

**18. When two coins are tossed, then what is the probability of getting Tails for both the coins?**

A. ½

B. ¼

C. ⅓

D. None of these

Answer: B.¼

Explanation: When two coins are tossed, then the possible outcomes will be:

HH, HT, TH, TT

Thus, probability of getting tails for both the coins = ¼

**19. The number of times that a particular entry occurs is called:**

A. Frequency

B. Class-interval

C. Raw data

D. Range

Answer: A. Frequency

**20. What is the number of possible outcomes, when two dies are thrown, simultaneously?**

A. 6

B. 12

C. 36

D. None of these

Answer: C. 36

Explanation: Number of possible outcomes of each dies = 6

For two dies, number of possible outcomes = 6 x 6 = 36

Question 6.

Solve the given equation 3\frac { 1 }{ x } × 5\frac { 1 }{ 4 } = 17\frac { 1 }{ 2 }

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3\frac { 1 }{ x } × 5\frac { 1 }{ 4 } = 17\frac { 1 }{ 2 }

(3x+1)/x × 21/4 = 35/2

(3x+1)/x = 35/2 × 4/21 = 10/3

On cross multiplying;

3(3x+1) = 10 x

9x + 3 = 10 x

x = 3

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