Logarithms

Let us assume that, a logarithm is said to be an exponent when a base 2 is given with an exponent 3, then how will you calculate 23? As you know  23= 2 * 2* 2= 8,  suppose a base 2 is given with a power 8, and you are asked to find the exponent  2? = 8, hence the exponent that produces the value is called as Logarithm. Here 23= 8 so the exponent 3 is nothing but the logarithm of 8 with a base value of 2. In a logarithmic way, we write it as 3 = log28. In the same way 104 = 10,000, it can be written as log1010,000 = 4. In a general way, the logarithmic function can be written or denoted as

Logb x = n  or   bn = x

Table of contents:

Logarithms

History

John Napier introduced the concept of Logarithms in the 17th century. Later it was used by many scientists, navigators, engineers, etc for performing various calculations which made it simple. In simple words, Logarithms are the inverse process of the exponentiation. In this article, we are going to have a look at the definition, properties, and examples of logarithm in detail.

Logarithm Definition

A logarithm is defined as the power to which number must be raised to get some other values. It is the most convenient way to express large numbers. A logarithm has various important properties that prove multiplication and division of logarithms can also be written in the form of logarithm of addition and subtraction.

“The logarithm of a positive real number a with respect to base b, a positive real number not equal to 1[nb 1], is the exponent by which b must be raised to yield a”.

i.e by= a and it is read as “the logarithm of a to base b.”

Logarithm Properties

There are four basic rules of logarithms as given below:-

  1. Logb (mn)= logb m + logb n. In this rule, the multiplication of two logarithmic values is equal to the addition of their individual logarithms.

          For example- log3 ( 2y ) = log3 (2) + log3 (y)

  1. Logb (m/n)= logb m – logb This is called as division rule. Here the division of two logarithmic values is equal to the difference of each logarithm.

         For example, log3 ( 2/ y ) = log3 (2) -log3 (y)

  1. Logb (mn) = n logb m

         This is the exponential rule of logarithms. The logarithm of m with a rational exponent is equal to the exponent times its logarithm.

  1.  Logb m = loga m/ loga b    

Also check:

Logarithms Examples

Question 1: Solve log 2 (64) =?

Solution:

since 26= 2 ××××× 2 = 64, 6 is the exponent value and log 2 (64)= 6.

Question 2: What is the value of log10(100)?

Solution:

In this case, 10 2 yields you 100. So, 2 is the exponent value, and the value of log10(100)= 2

Question 3: Use of the property of logarithms, solve for the value of x for log3 x= log3 4+ log3 7

Solution:

By the addition rule, log3 4+ log3 7= log 3 (4 * 7 )

Log 3 ( 28 ). Thus, x= 28.

Question 4: Solve for x in log 2 x = 5

Solution:

This logarithmic function can be written In the exponential form as 2 5 = x

Therefore, 2 5= 2 ×××× 2 = 32, X= 32.

Logarithms Applications

Logarithms are nowadays widely used in the field of science and technology. We can even find logarithmic calculators which have made our calculations much easier. These find its applications in surveying and celestial navigation purposes. They are also used in calculations such as measuring the loudness (decibels), the intensity of the earthquake regarding Richter scale, in radioactive decay, to find the acidity (pH= -log10[H+]), etc.

Know more about the Basics of maths, formulas, calculators, solve maths puzzles and number of maths-related problems only on BYJU’S.

4 Comments

  1. log3^2*log2^81=4

    log5^3*log3^25=2

    asa sir i want solution of this

    1. 1) log32*log281=4
      Solution:-
      log32 = 0.63
      log281 = 6.34
      ⇒ 0.63*6.34 = 3.99= 4

      2) log53 * log325 = 2
      solution:-
      log53 = 0.68
      log325 = 2.93
      ⇒ 0.68*2.93= 1.99=2

    2. log3^2×log2^81=4
      1/log2^3×log2^81=4 (1/log2^3=log3^2)
      4log2^3/log2^3=4 (log2^81=4log2^3)
      4 = 4
      LHS = RHS PROVED

      log5^3×log3^25=2
      1/log3^5×log3^25=2 (1/log3^5=log5^3)
      2log3^5/log3^5=2 (log3^25=2log3^5)
      2 = 2
      LHS = RHS PROVED

  2. a power (log base b (log base b n)/log a base b)

Leave a Comment

Your email address will not be published. Required fields are marked *