Morera’s Theorem

Morera’s Theorem is regarded as the converse of Cauchy-Goursat Theorem, which states that if a function f(z) is analytic and single-valued inside and on a simple closed contour C, then

\(\begin{array}{l}\int _{C}f(z) dz = 0\end{array} \)
Morera’s theorem states sort of the opposite of this theorem.

Morera’s theorem was named after the Italian engineer and mathematician Giacinto Morera, known for his work in Linear Elasticity and the theory of functions in complex variables.

Statement of Morera’s Theorem

According to Morera’s theorem for integration of complex functions in a simply connected domain D, as follows –

Let f(z) be continuous in a simply connected domain D and let for every closed contour C in the domain D,

\(\begin{array}{l}{C}f(z) dz = 0\end{array} \)
, then f(z) is analytic in D.

A continuous function f(z) defined in a simply connected domain D, whose closed curve integration over every closed contour C in the domain D must vanish, for f to be analytic or holomorphic within D.

Proof of Morera’s Theorem

As per the statement of the theorem we have a continuous function f defined in a simply connected domain D and

\(\begin{array}{l}\int _{C}f(z) dz = 0\end{array} \)
, where C is a closed contour within D. We shall prove that f is analytic within D. Let z be any variable point in D any zo be any fixed point in D. Now we have

\(\begin{array}{l}F(z)=\int_{z_{o}}^{z}f(\zeta )d\zeta \end{array} \)
…….(1) is a line integral along the line joining points z and zo, where 𝜁 is any arbitrary point between z and zo. This integration is independent of the path joining z and zo and only depends on the choice of z.

Let z + h be any point in the neighbourhood of z, then we have

\(\begin{array}{l}F(z+h)=\int_{z_{o}}^{z+h}f(\zeta )d\zeta \end{array} \)
…(2)

Subtracting (2) from (1), we get

\(\begin{array}{l}F(z+h)- F(z) =\int_{z_{o}}^{z+h}f(\zeta )d\zeta – \int_{z_{o}}^{z}f(\zeta )d\zeta \end{array} \)

\(\begin{array}{l}=\int_{z_{o}}^{z+h}f(\zeta )d\zeta + \int_{z}^{z_{o}}f(\zeta )d\zeta \end{array} \)

\(\begin{array}{l}=\int_{z_{o}}^{z+h}f(\zeta )d\zeta \end{array} \)
………(3)

Since the integral in (3) is path-independent and without loss of generality, it may be taken along line segment joining points z and z + h. Now,

\(\begin{array}{l}\frac{F(z+h)-F(z)}{h}- f(z)=\frac{1}{h}\int_{z}^{z+h}f(\zeta )d\zeta – f(z) \end{array} \)

\(\begin{array}{l}=\frac{1}{h}\int_{z}^{z+h}f(\zeta )d\zeta – \frac{f(z)h}{h} \end{array} \)

\(\begin{array}{l}=\frac{1}{h}\left [ \int_{z}^{z+h}f(\zeta )d\zeta -\int_{z}^{z+h}f(z)d\zeta \right ] \end{array} \)

\(\begin{array}{l}=\frac{1}{h}\int_{z}^{z+h}\left [ f(\zeta ) – f(z) \right ] d\zeta\end{array} \)
……….(4)

Since f(𝜁) is continuous at z in D, by the definition of continuous function, for any given ε > 0, there exist a positive number δ such that

|f(𝜁) – f(z)| < ε for all 𝜁 satisfying |𝜁 – z| < δ ………..(5)

Now if 𝜁 = z + h then | z + h – z| < δ ⇒ |h| < δ. Then the inequality (5) is satisfied for every 𝜁 on the line segment joining the points z and z + h. Hence from (4) and (5) we have

\(\begin{array}{l}\left| \frac{F(z+h)-F(z)}{h}- f(z)\right|\leq \frac{1}{|h|}\int_{z}^{z+h}|f(\zeta)-f(z)||d\zeta|\end{array} \)

\(\begin{array}{l}<\frac{1}{|h|}\int_{z}^{z+h}\epsilon |d\zeta|= \frac{1}{|h|}.\epsilon |h| = \epsilon\end{array} \)
…………..(6)

Since ε is arbitrary, we have from (6)

\(\begin{array}{l}\displaystyle \lim_{h \to 0}\frac{F(z+h)-F(z)}{h}=f(z)\end{array} \)

Which means F(z) is differentiable, hence analytic with the derivative f(z). That is, F’(z) = f(z) for every z in D. Consequently F(z) is analytic within D. But the derivative of an analytic function is also analytic. It follows that f(z) is also analytic in D.

Important Facts on Morera’s Theorem

  • The given function f is continuous in the domain D.
  • f(z) exists for every z in D.
  • If C is any closed curve within domain D for which the given function converges within C then
    \(\begin{array}{l}\int _{C}f(z) dz = 0\end{array} \)
    .
  • Consequently, f is analytic within D.

Related Articles

Solved Example on Morera’s Theorem

Example :

Show that the function f defined by

\(\begin{array}{l}f(z)=\int_{0}^{\infty}\frac{|e^{zt}|}{t + 1}dt\end{array} \)
is analytic in the left half plane D: Re(z) < 0.

Solution:

This could be easily proved by applying Morera’s Theorem. We have a continuous function of two variables, by changing the order of integration we can easily apply Morera’s Theorem.

Now,

\(\begin{array}{l}f(z)=\int_{0}^{\infty}\frac{|e^{zt}|}{t + 1}dt < \int_{0}^{\infty}e^{xt}dt = -\frac{1}{x}\end{array} \)
for Re(z) = x < 0

That is, the integral is absolute convergent and |f(z)| < 1/|x|

Consider

\(\begin{array}{l}\int _{C}f(z) dz =\int _{C}\left ( \int_{0}^{\infty}\frac{e^{zt}}{t + 1}dt \right )dz \end{array} \)

where C is a closed contour in D.

Since, the given integral converges, we can have

\(\begin{array}{l}\int_{0}^{\infty}\left ( \int _{C}\frac{e^{zt}}{(t+1)}dz \right )dt = \int_{0}^{\infty} 0 dt = 0\end{array} \)

As ezt/(t + 1) is analytic inside C.

By Morera’s Theorem f is analytic within D.

Frequently Asked Questions on Morera’s Theorem

Q1

What is the result of Morera’s Theorem?

If f is a continuous function within a simply connected domain D, such the integral of f on a closed contour C within D vanishes then the function is analytic.

Q2

What is proved by using Morera’s Theorem?

Morera’s theorem is used to prove whether a given function is analytic in given domain.

Q3

What are the conditions of Morera’s Theorem?

The conditions of Morera’s theorem are that the given function must be continuous within the domain and the closed curve integral on every closed contour within the domain vanishes

Q4

Morera’s theorem is converse of which theorem?

Morera’s theorem is converse of Cauchy-Goursat’s theorem.

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