While solving the equation of the form \(ax^{2}+bx+c = 0\)

Two Distinct Real roots

Similar Root

No Real roots (Complex Roots)

The introduction of complex numbers in the 16th century made it possible to solve the equation \(x^{2}+1 = 0\)

We denote \(\sqrt{-1}\)

An equation of the form z= a+ib, where a and b are real numbers, is defined to be a complex number. The real part is denoted by Re z = a and the imaginary part is denoted by Im z = b.

Algebraic Operation on Complex numbers:

- Addition of two complex numbers
- Subtraction of two complex number
- Multiplication of two complex number
- Division of two complex number

## Power of Iota (i) –

Depending upon the power of i, it can take the following values

\(i^{4k+1} = i\)

\(i^{4k+2} = -1\)

\(i^{4k+3} = -i\)

\(i^{4k} = 1\)

where k can have any integral value (positive or negative).

Similarly we can find for the negative power of i, which are as follows

\(i^{-1}=\frac{1}{i}\)

Multiplying and dividing the above term with i, we have

\(i^{-1}=\frac{1}{i} \times \frac{i}{i}\)

\(i^{-1}=\frac{i}{i^{2}} = \frac{i}{-1} = -i\)

Note: \(\sqrt{-1}\times \sqrt{-1} = \sqrt{-1 \times -1} = \sqrt{1} = 1 \)

Therefore for an imaginary number, \(\sqrt{a}\times \sqrt{b} \neq \sqrt{ab}\)

## Identities:

(i) \(\left ( z_{1}+z_{2} \right )^{2} =z_{1}^{2}+z_{2}^{2}+2z_{1}z_{2}\)

(ii) \(\left ( z_{1}-z_{2} \right )^{2} =z_{1}^{2}+z_{2}^{2}-2z_{1}z_{2}\)

(iii) \(z_{1}^{2}-z_{2}^{2} = \left ( z_{1} + z_{2} \right )\left ( z_{1} – z_{2} \right )\)

(iv) \(\left ( z_{1}+z_{2} \right )^{3} = z_{1}^{3}+3z_{1}^{2}z_{2}+3z_{1}z_{2}^{2}+z_{2}^{3}\)

(v) \(\left ( z_{1}-z_{2} \right )^{3} = z_{1}^{3}-3z_{1}^{2}z_{2}+3z_{1}z_{2}^{2}-z_{2}^{3}\)

## Modulus and Conjugate of a Complex number:

Let z=a+ib be a complex number.

The Modulus of z is represented by \(\left | z \right |\)

Mathematically, \(\left | z \right |= \sqrt{a^{2}+b^{2}}\)

The conjugate of z is denoted by \(\bar{z}\)

Mathematically, \(\bar{z}= a – ib\)

Example- Express the following in a+ib form. \(\frac{5+ \sqrt{3}i}{1-\sqrt{3}i}\) And then find the Modulus and Conjugate of the complex number.] Solution- Given \(\frac{5+ \sqrt{3}i}{1-\sqrt{3}i}\) z= \(\frac{5+ \sqrt{3}i}{1-\sqrt{3}i} \times \frac{1+\sqrt{3}i}{1+\sqrt{3}i} = \frac{5-3+6\sqrt{3}i}{1+3}=\frac{1}{2} + \frac{3}{2}i\) Modulus, \(\bar{z} = \sqrt{\left ( \frac{1}{2}\right )^{2} + \left (\frac{3}{2}\right )^{2}}\) \(\bar{z} = \sqrt{\left ( \frac{10}{4}\right )}\) \(\bar{z} = \frac{\sqrt{10}}{2}\) Conjugate, \(\bar{z} = \frac{1}{2} – \frac{3}{2}i\) |

Argand Plane & Polar Representation of Complex Number:

Similar to the XY plane, the Argand(or complex) plane is a system of rectangular coordinates in which the complex number a+ib is represented by the point whose coordinates are a and b.

We find the real and complex components in terms of r and θ, where r is the length of the vector and θ is the angle made with the real axis.

## Quadratic Equation:

The Quadratic equation is of the form \(ax^{2}+bx+c=0\)

where the roots of the equation are given as

\(\large x= \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\)

or, \(\large x= \frac{-b \pm \sqrt{D}}{2a}\)

where Discriminant (D)\( = b^{2}-4ac\)

For an equation having complex roots, D<0

Example- Find the roots of the given quadratic equation \(27x^{2}-10x+1=0\) Solution- Given \(27x^{2}-10x+1=0\) The roots of the equation is given as \(\large x= \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\) \(\large x= \frac{-(-10)\pm \sqrt{(-10)^{2}-4\times 27 \times 1}}{2 \times 27}\) \(\large x= \frac{10\pm \sqrt{-8}}{54}\) \(\large x= \frac{5}{27} \pm \frac{\sqrt{2}i}{27}\) |

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