 # Surds

In Mathematics, Surds are an irrational number which cannot be represented accurately in the form of fractions or recurring decimals. So, it can be left as a square root. Surds are used in many real-time applications to make precise calculations. In this article, let us discuss the surds definition, types, six basic rules of surds, and example problems.

## Surds Definition

Surds are the square roots  (√) of numbers which cannot be simplified into a whole or rational number. It cannot be accurately represented in a fraction. In other words, a surd is a root of the whole number that has an irrational value. Consider an example, √2 ≈ 1.414213. It is more accurate if we leave it as a surd √2.

## Types of Surds

The different types of surds are as follows:

• Simple Surds – A surd that has only one term is called simple surd. Example: √2, √5, …
• Pure Surds – Surds which are completely irrational. Example: √3
• Similar Surds – The surds having the same common surds factor
• Mixed Surds – Surds that are not completely irrational and can be expressed as a product of a rational number and an irrational number
• Compound Surds – An expression which is the addition or subtraction of two or more surds
• Binomial Surds –  A surd that is made of two other surds

## Six Rules of Surds

Rule 1:

$\sqrt{a\times b}=\sqrt{a}\times \sqrt{b}$

Example:

To simplify √18

18 = 9 x 2 = 32 x 2, since 9 is the greatest perfect square factor of 18.

Therefore, √18 = √(32 x 2)

= √32 x √2

= 3 √2

Rule 2:

$\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$

Example:

√(12 / 121) = √12 / √121

=√(22 x 3) / 11

=√22 x √3 / 11

= 2√3 / 11

Rule 3:

$\frac{b}{\sqrt{a}}=\frac{b}{\sqrt{a}}\times \frac{\sqrt{a}}{\sqrt{a}}=b\frac{\sqrt{a}}{a}$

You can rationalize the denominator by multiplying the numerator and denominator by the denominator.

Example:

Rationalise

5/√7

Multiply numerator and denominator by √7

5/√7 = (5/√7) x (√7/√7)

= 5√7/7

Rule 4:

$a\sqrt{c}\pm b\sqrt{c}=(a\pm b)\sqrt{c}$

Example:

To simplify,

5√6 + 4√6

5√6 + 4√6 = (5 + 4) √6

by the rule

= 9√6

Rule 5:

$\frac{c}{a+b\sqrt{n}}$

Multiply top and bottom by a-b √n

This rule enables us to rationalise the denominator.

Example:

To Rationalise

$\frac{3}{2+\sqrt{2}}= \frac{3}{2+\sqrt{2}}\times \frac{2-\sqrt{2}}{2-\sqrt{2}}=\frac{6-3\sqrt{2}}{4-2}$ $=\frac{6-3\sqrt{2}}{2}$

Rule 6:

$\frac{c}{a-b\sqrt{n}}$

This rule enables you to rationalise the denominator.

Multiply top and bottom by a + b√n

Example:

To Rationalise

$\frac{3}{2-\sqrt{2}}= \frac{3}{2-\sqrt{2}}\times \frac{2+\sqrt{2}}{2+\sqrt{2}}=\frac{6+3\sqrt{2}}{4-2}$ $=\frac{6+3\sqrt{2}}{2}$

### How to Solve Surds?

You need to follow some rules to solve expressions that involve surds. One method is to rationalize the denominators, which helps to eject the surd in the denominator. Sometimes it may be mandatory to find the greatest perfect square factor to solve surds.

### Surds Problems

Example 1:

Write down the conjugate of 5√3 + √2

Solution:

The conjugate of  5√3 + √2 is 5√3 – √2.

Example 2:

Rationalize the denominator: 1/[(8√11 )- (7√5)]

Solution:

Given:  1/[(8√11 )- (7√5)]

It is known that the conjugate of (8√11 )- (7√5) is (8√11 )+(7√5)

To rationalize the denominator of the given fraction, multiply the conjugate of denominator on both numerator and denominator.

=[1/[(8√11 )- (7√5)]]× [[(8√11 )+ (7√5)]/[(8√11 )+(7√5)]]

=[(8√11 )+ (7√5)]/[(8√11 )2-(7√5)2]

=[(8√11 )+ (7√5)]/[704- 245]

= [(8√11 )+ (7√5)]/459

Now to start practising problems and examples of surd based on rules mentioned above, please visit BYJU’S – The Learning App.

1. Manjunath

is this surd or not : sqrt ( 3+ (sqrt 2) ) . Give proper reason.

1. lavanya

sqrt ( 3+ (sqrt 2) ) is a surd because it cannot be simplified into a whole or rational number.

2. Dpsnewtoneight

Hi mj
It is a surd
cuz it is an irrational number

2. Taiwo

Help me solve this problem √800+√200-2√32

1. lavanya

√800+√200-2√32
√800+√200-2√32
800 = 2x2x2x2x2x5x5
200 = 2x2x2x5x5
32 = 2x2x2x2x2
Therefore, taking out the terms, under the root, that are in pair of two, we get:
= 20√2 + 10√2 – (2 x 4√2)
= 20√2 + 10√2 – 8√2
= 22√2

3. Deborah