Two figures are said to be similar figures if they have same shape irrespective of its dimensions. For example, Different sized photographs of a person i.e. stamp size, passport size etc. depicts the similar objects but are not congruent. Certain geometrical shapes or figures are always similar in nature. Take an example of circle; the shape remains same irrespective of the change in its radius. Therefore, it can be said that all the circles with different radii are similar to each other. Similarly, all squares are always similar to each other since the lengths of sides get altered but the shape is always similar. In case of similarity of triangles, the following set of conditions needs to be true for two or more triangles to be similar:
- Corresponding angles of both the triangles are equal and
- Corresponding sides of both the triangles are in proportion to each other.
In other words two triangles ΔABC and ΔPQR are similar if,
Let us now discuss a very important theorem related to triangles known as the triangle proportionality theorem
Triangle Proportionality Theorem:
If a line is drawn parallel to any one side of a triangle in such a way that it intersects the other two sides in two distinct points then the other two sides of the triangle is divided in the same ratio.
Consider a triangle ΔABC as shown in the figure given above. In this triangle if we draw a line PQ parallel to the side BC of ΔABC as shown then according to triangle proportionality theorem, ratio of AP to PB is equal to ratio of AQ to QC i.e.;
Let us now try to prove this theorem;
Given: ΔABC with line segment PQ drawn parallel to the side BC of ΔABC
Construction: Join the vertex B of ΔABC to Q and the vertex C to P to form the lines BQ and CP. Draw QN⊥ AB and PM⊥AC as shown in the given figure.
Hence the triangle proportionality theorem is proved. Also ∆ABC and ∆APQ satisfy the required conditions for similar triangles as stated above. Therefore, it can be concluded that ∆ABC ~∆APQ.
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