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[15(2-y)-5(y+6)=10]/1-3y. Solve.

[15(2-y)-5(y+6)=10]/1-3y 15(2−y)−5(y+6)=10(1−3y) 30−15y−5y−30=10−30y −15y−5y+30y=10−30+30 10y=10 y=10/10 = 1

(2-7x)/(1-5x)=(3+7x)/(4+5x). Solve for x.

(2-7x)/(1-5x)=(3+7x)/(4+5x) By applying alternendo, \(\begin{array}{l}\frac{2-7 x}{3+7 x}=\frac{1-5 x}{4+5 x}\end{array} \) Now applying Componendo and Dividendo, \(\begin{array}{l}\begin{array}{l} \frac{(2-7 x)+(3+7 x)}{(2-7 x)-(3+7... View Article