Question

$\left[15\right(2-y)-5(y+6\left)\right]=10\left(1-3y\right)$ $,$Solve for $y.$

Answer 1

The given algebraic equation is $\left[15\right(2-y)-5(y+6\left)\right]=10\left(1-3y\right)$

$15(2-y)-5(y+6)=10(1-3y)$

$30-15y-5y-30=10-30y$

$-15y-5y+30y=10-30+30$

$10y=10$

$y=\frac{10}{10}$

$y=1$

Hence$,$ the value of $y$ is $1$