[15(2-y)-5(y+6)=10]/1-3y. Solve.

[15(2-y)-5(y+6)=10]/1-3y

15(2−y)−5(y+6)=10(1−3y)

30−15y−5y−30=10−30y

−15y−5y+30y=10−30+30

10y=10

y=10/10 = 1

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