1) (1, –1) 2) (1, 1) 3) (2, 1) 4) (2, 2) Solution: Let the variable line be ax + by + c = 0 …(i) We know that the perpendicular distance... View Article
1) 2 2) 0 3) 4 4) 1 Solution: Given 3x + 4y = 9 …(i) y = mx + 1 …(ii) By solving (i) and (ii) we get the point of intersection of the two... View Article
1) 1 : 2 2) 2 : 1 3) 2 : 3 4) 3 : 4 Solution: Let the line y - x + 2 = 0 divide the line joining the points A(3, -1) and B(8, 9) in the... View Article
1) AP 2) GP 3) HP 4) None of these Solution: We know that the perpendicular distance of a line ax + by + c = 0 from the point (x1, y1) is... View Article
1) 6 2) 7 3) 5 4) 8 Solution: Given line is 4x + 3y + 20 = 0 The point is (3,1). We know that the perpendicular distance to a line ax + by +... View Article
1) k 2) 2k 3) k2 4) 2k2 Solution: Given x sec α + y cosec α = k…(i) The distance of the above line from the origin (0, 0) is given by p =... View Article
1) x + y + 2 = 0 2) x + y = 0 3) x + y = 2 4) None of these Solution: Consider the x-axis and y-axis as the two perpendicular lines. Let... View Article
1) sin 2α 2) cos 2α 3) 2 sin 2α 4) 2 cos 2α Solution: Given x sin α + y cos α = sin 2α Divide both sides by sin 2α x/2 cos α + y/2 sin α = 1... View Article
1) 9 2) 9/2 3) 2 4) 2/9 Solution: The slope of line x - y = 2 is 1. This line makes an angle 450 with the positive x-axis. Let m1 and m2 be... View Article
1) The incentre 2) The centroid 3) The circumcentre 4) The orthocentre of the triangle Solution: Let line L1: x - 3y = 0 …(i) L2: 4x + 3y =... View Article
March 17th, 2021, PIB:- Download PDF Here TABLE OF CONTENTS 1. International Conference on Disaster Resilient Infrastructure 2. Har Medh Par... View Article