Archives

What does 50 UF mean on a capacitor

The SI unit of a capacitor is Farad. One farad is a very large value for normal household capacitors. Therefore, household capacitors are marked... View Article

Can I use AC capacitor for DC

AC capacitors can be used for DC but DC capacitors cannot be used for AC.... View Article

Real part of cos h (ɑ + iβ) is

1) cos h ɑ cos β 2) cos ɑ cos β 3) cos ɑ cos hβ 4) sin ɑ sin hβ Solution: (1) cos h ɑ cos β The real part of cos h (ɑ + iβ) is cos h (ɑ +... View Article

Imaginary part of cos h (ɑ + iβ) – cos h (ɑ – iβ) =

1) 2 sin hɑ sin hβ 2) 2 sin hɑ sin β 3) cos hɑ cos hβ 4) 2 cos ɑ cos β Solution: (2) 2 sin hɑ sin β cos h (ɑ + iβ) - cos h (ɑ - iβ) = 2 sin... View Article

The general value of cos h^-1 x is

1) 2πri = log [x + √x2 + 1] 2) 2πri + log [x + √x2 - 1] 3) πri + (- 1)r log [x + √x2 + 1] 4) 2πri + (- 1)r log [x + √x2 - 1] Solution: (2)... View Article

cos (i⁵ x) =

1) i cos hx 2) - i cos hx 3) cos hx 4) - cos hx Solution: (3) cos hx cos (i5 x) = cos (ix) = cos hx... View Article

sin h [x + (πi / 2)] =

1) i cos hx 2) - i cos hx 3) cos x 4) - cos x Solution: (1) i cos hx sin h [x + (πi / 2)] = - i sin [ix - (π / 2)] = i sin [(π / 2) - ix] =... View Article

sin h^-1 (sin h^-1 θ) =

1) iθ 2) θ 3) - iθ 4) π + iθ Solution: (2) θ sin h-1 (sin h-1 θ) = - i sin (i (sin h-1 θ)) = - i sin [i (- i sin-1 (iθ))] = - i . iθ = - i2 θ = θ... View Article

If cos ɑ cos h β = 1, then β =

1) log sec (ɑ / 2) 2) log tan ɑ 3) log (sec ɑ + tan ɑ) 4) log sin (ɑ / 2) Solution: (3) log (sec ɑ + tan ɑ) cos ɑ cos h β = 1 cos h β = sec... View Article

The value of sin h^-1 [x / (√1 – x²)] is

1) tan h-1 x 2) cot h-1 x 3) sin h-1 2x 4) cos h-1 2x Solution: (1) tan h-1 x Let x = tan hy, then x / (√1 - x2) = [tan hy] / [sec hy] = sin... View Article

The value of cos h^-1 (sec x) is

1) log [1 + sin x] / cos x 2) log [1 - sin x] / cos x 3) log [1 + cos x] / sin x 4) log [1 - cos x] / sin x Solution: (1) log [1 + sin x] /... View Article

If – π / 2 < x < π / 2, then the value of log sec x is

1) 2 cot h-1 (cosec2 (x / 2) - 1) 2) 2 cos h-1 (cosec2 (x / 2) - 1) 3) 2 cosec h-1 (cot2 (x / 2) - 1) 4) 2 cosec h-1 (cot2 (x / 2) + 1)... View Article

sin h^-1 (2^3/2) is

1) log (2 + √18) 2) log (3 + √8) 3) log (3 - √8) 4) log (√8 + √27) Solution: (2) log (3 + √8) sin h-1 (23/2) = log (23/2 + √(23/2)2 + 1 =... View Article

sec h^-1 (1 / 2) is

1) log (√3 + √2) 2) log (√3 + 1) 3) log (2 + √3) 4) None of these Solution: (3) log (2 + √3) sec h-1 (1 / 2) = cos h-1 (2) = log (2 + √22 -... View Article

log (3 + 2 √2) =

1) sin h-1 3 2) cos h-1 3 3) tan h-1 3 4) cot h-1 3 Solution: (2) cos h-1 3 log (3 + 2 √2) = log (3 + √8) = log (3 + √9 - 1) = log (3 + √32... View Article

If cos h^-1 x = log (2 + √3), then x =

1) 2 2) 1 3) 3 4) 5 Solution: (1) 2 cos h-1 x = log (2 + √3) cos h-1 x = log (x + √x2 - 1) = log (2 + √3) x = 2... View Article

If x = log (y + √y² + 1), then y =

1) tan h x 2) cot h x 3) sin h x 4) cos h x Solution: (3) sin h x x = log (y + √y2 + 1) = sin h-1 y y = sin h x... View Article

The period of sin h (x / 2) is

1) 2πi 2) cot h x 3) 4πi 4) cos h x Solution: (3) 4πi The period of sin h x is 2πi, hence, the period of sin h (x / 2) is 4πi.... View Article

The period of cos h (θ / 3) is

1) 6πi 2) 2πi 3) πi 4) 9πi Solution: (1) 6πi Since the period of coshθ is 2πi, the period of cos h (θ / 3) is 3 * 2πi = 6πi.... View Article

sec h (πi) + cosec h [(π / 2)i] =

1) 1 - i 2) - 1 + i 3) - 1 - i 4) 1 + i Solution: (3) - 1 - i sec h (πi) + cosec h [(π / 2)i] = sec π - i cosec (π / 2) = - 1 - i... View Article

M	T	W	T	F	S	S
					1	2
3	4	5	6	7	8	9
10	11	12	13	14	15	16
17	18	19	20	21	22	23
24	25	26	27	28	29	30
31