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Let [latex]A=\begin{bmatrix} a_{1}\\ a_{2} \end{bmatrix}[/latex] and [latex]B=\begin{bmatrix} b_{1}\\ b_{2} \end{bmatrix}[/latex] be two 2 × 1 matrices with real entries such that A = XB, where X =[latex]\frac{1}{\sqrt3}\begin{bmatrix} 1 &-1 \\ 1&k \end{bmatrix}[/latex], and k ∈ R. If (a12 + a22) = (2 / 3) (b12 + b22) and (k2 + 1) b22 ≠ – 2b1b2, then the value of k is

Answer: (1) XB = A (1 / √3) b1 - b2 = √3a1 3a12 = b12 + b22 - 2b1b2 b1 + kb2 = √3a2 3a22 = b12 + k2b22 + 2kb1b2 Adding both... View Article

Let f : R → R and g : R → R be defined as f (x) = [latex]left{begin{matrix} x+a, &x<0 \ |x-1|, &xgeq 0 end{matrix}right.[/latex] and g (x) = [latex]left{begin{matrix} x+1, &x<0 \ (x-1)^2+b, &xgeq 0 end{matrix}right.[/latex] where a, b are non-negative real numbers. If (gof) (x) is continuous for all x ∈ R, then a + b is equal to

Given (gof) (x) is continuous for all x ∈ R Answer: (1) Given g(f(x)) is continuous. So, at x = –a & at x = 0 1 = b + 1 &... View Article

Let α ∈ R be such that the function [latex]f(x) = \left\{\begin{matrix} \frac{cos^{-1}(1-\left \{ x \right \}^{2})sin^{-1}(1-\left \{ x \right \})}{\left \{ x \right \}-\left \{ x \right \}^{3}} & x\neq 0\\ \alpha & x=0 \end{matrix}\right.[/latex] is continuous at x = 0, where {x} = x – [x], [x] is the greatest integer less than or equal to x. Then:

1) α = π/4 2) No such α exists 3) α = 0 4) α = π/√2 Solution: RHL = = = (L'Hospital's rule) = LHL =... View Article