(A) Assertion is true, but the reason is false. (B) Both assertion and reason are false. (C) Both assertion and reason are true. The reason is... View Article
Solution: The molecular formula of hydrocarbons is C5H10, which satisfies the general formula CnH2n. This suggests that the hydrocarbon can... View Article
i) △DAP≅△EBP Given that, ∠EPA=∠DPB Now, ∠EPA+∠DPE=∠DPB+∠DPE Hence, ∠DPA=∠EPB Now, by using the triangles EBP and DAP, ∠EBP=∠DAP (given)... View Article
Consider ABCD is a square lawn whose side is 58m. Also, AED and BFC are the two circular ends Therefore, the diagonal of the lawn = 58√2 m... View Article
(i) ∠DAC=∠BCA Since, ABC is an isosceles triangle, Let, ∠ABC=∠BCA=y Also, given that ∠QAD=∠DAC = x (Let) By using the alternate interior... View Article
Varun preferred Heron’s formula to find the area of a farm for the following reason: Since all the side lengths of a scalene triangle are given,... View Article
To find the least number which when divided by 6, 9, 12, 15, 18 leaves the same remainder 5 in each case, we have to find the LCM of 6, 9, 12,... View Article
As we know, resultant vector, R2 = A2 + B2 + 2ABCos θ Thus, from the given value, We can write (√7b)2 = a2+b2+2ab Cos60° 7b2 = a2+b2+2ab(½)... View Article
Let α and α2 be the two roots of the equation x2+ px+q = 0. Thus, α + α2 = -p α(1+α) = -p, and α3 = q Now, (α(1+α)3 = (-p)3 α3(1+α)3 = -p3... View Article
(a) f(x) is continuous at x = 0 and x = 1 (b) f(x) is continuous at x = 0, but not x = 1 (c) f(x) is continuous at x = 1, but not x = 0 (d)... View Article
If the adjacent sides of a parallelogram are represented by a vector, then the formula to calculate the area of a parallelogram is |Vector A... View Article
Given that AEDB is a quadrilateral. We know that the sum of the interior angles of a quadrilateral is 360°. From the given figure, it is... View Article
Time period of fractional part of x, {x} = 1 But in the given question, we have, {x/5} Thus, the time period will be 5. To plot the graph for... View Article
Now, consider the figure as given below, Now, join AN, and hence ∠ANB = 90° In triangle, ANB, Cos θ = BN/2r BN = 2r cos θ Thus, BD = 2BN =... View Article