Hybridization of BrF3 (Bromine Trifluoride)

The hybridization that takes place in BrF3 is sp3d. We will understand how hybridization of BrF3 occurs in the molecules as well as its molecular geometry and the bond angles below.

Name of the Molecule Bromine Trifluoride
Molecular Formula BrF3
Hybridization Type sp3d
Bond Angle 86.20
Geometry T-shaped or Trigonal Bipyramidal

What is the Hybridization of Bromine Trifluoride?

To determine the hybridization of bromine trifluoride we will first take the bromine atom which is the central atom and look at its electron configuration. It is represented as;

1s2 2s22p6 3s23p63d104s24p5. However, in order to form bonds with the fluorine atom some electrons in Bromine are shifted to 4d-orbitals. Besides, fluorine has a higher oxidative capacity and therefore it forces bromine to promote electrons to the said level. Now, bromine can use the d-orbitals for hybridization.

Hybridization Of BrF3

BrF3 will consist of seven electrons in its outermost shell. After the bond formation, it will further have 2 lone pairs and 3 Br—F covalent bonds. As the hybridization value or the electron pair is equal to 5 it gives rise to sp3d hybrid orbitals.

Important Points To Remember

  • The central atom bromine uses the d-orbitals for hybridization.
  • In BrF3, it will have 2 lone pairs and 3 Br—F covalent bonds.
  • Lone pairs take part in hybridization.

BrF3 Molecular Geometry And Bond Angles

BrF3 molecular geometry is said to be T-shaped or Trigonal Bipyramidal with a bond angle of 86.2o which is slightly smaller than the usual 90°.

BrF3 Molecular Geometry

This angle formed due to the repulsion generated by the electron pairs which is greater than that of the Br-F bonds.

Read More About Hybridization of Other Chemical Compounds

Frequently Asked Questions – FAQs

What is the hybridization of BrF3?

The hybridization of BrF3 is sp3d.

What is the geometry of BrF3?

The geometry of BrF3 is Trigonal bipyramidal.

What is the bond angle of BrF3?

The bond angle of BrF3 is 86.2°.
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