In Mathematics, an equation is a mathematical statement in which two things should be equal to each other. An equation consists of two expressions on each side of an equal sign (=). It consists of two or more variables. In short, the L.H.S value should be equal to R.H.S value. While substituting the values of the variables in an equation, it should prove its equality. There are different types of equations in Maths, such as:
and so on. In this article, we are going to discuss the simultaneous equations which involve two variables along with different methods to solve.
What are Simultaneous Equations?
The simultaneous equation is an equation which involves two or more quantities that are related using two or more equations. It includes a set of few independent equations. The simultaneous equations are also known as the system of equations, in which it consists of a finite set of equations for which the common solution is sought. To solve the equations, we need to find the values of the variables included in these equations.
A simultaneous equation has a general form which is written as
ax +by = c
dx + ey = f
Methods for Solving Simultaneous Equations
The Simultaneous equations can be solved using various methods. There are three different approaches to solve the simultaneous equations such as substitution, elimination, and augmented matrix method. Among these three methods, the two simplest methods that will effectively solve the simultaneous equations to get accurate solutions. Here we are going to discuss the two important methods, such as:
Simultaneous Equation Example
Let us now understand how to solve simultaneous equations through the above-mentioned methods. We will get the value of a and b to find the solution for the same. x and y are the two variables in these equations. Go through the following problems which use substitution and elimination method to solve the simultaneous equations.
Try Out: Simultaneous Equation Solver
Solving Simultaneous Equations Using Elimination Method
Solve the two pairs of simultaneous equations by the elimination method.
4a + 5b = 12,
3a – 5b = 9
The two given equations are
4a + 5b = 12 …….(1)
3a – 5b = 9……….(2)
Step 1: The coefficient of variable ’b’ is equal and has the opposite sign to the other equation. Add the equations 1 and 2 to eliminate the variable ‘b’.
Step 2: The like terms will be added.
(4a+3a) +(5b – 5b) = 12 + 9
7a = 21
Step 3: Bring the coefficient of a to the R.H.S of the equation
a = 21/ 7
Step 4: Dividing the R.H. S of the equation, we get a = 3
Step 5: Now, substitute the value a=3 in the equation (1), it becomes
4(3) + 5b = 12,
12 + 5b = 12
5b = 12-12
b = 0/5 = 0
Step 6: Hence, the solution for the given simultaneous equations is a = 3 and b = 0.
Solving Simultaneous Equations Using Substitution Method
Solve the two pairs of simultaneous equations using the substitution method.
b= a + 2
a + b = 4.
The two given equations are
b = a + 2 ————–(1)
a + b = 4 ————–(2)
We will solve it step-wise:
Step 1: Substitute the value of b into the second equation. We will get,
a + (a + 2) = 4
Step 2: Solve for a
a +a + 2 = 4
2a + 2 = 4
2a = 4 – 2
a = 2/2 = 1
Step 3: Substitute this value of a in equation 1
b = a + 2
b = 1 + 2
b = 3
step 4: Hence, the solution for the given simultaneous equations is: a =1 and b = 3
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