**Solving linear inequalities** by the graphical method is the easy way to find the solutions for linear equations. To solve a linear equation in one variable is simple, where we need to plot the value in a number line. But for two-variable cases, we have to plot the graph in an x-y plane. In **linear inequality**, a linear function is involved. A mathematical expression containing equal-to Â (=) symbol is known as an equation. The equality symbol signifies that the right-hand side of the expression is equal to the left-hand side of the expression. If two mathematical expressions contain symbols like â€˜<â€™(less than), â€˜>â€™ (greater than), â€˜â‰¤â€™(less than or equal to) or â€˜â‰¥â€™ (greater than or equal to), they are called inequalities.

**For example, **

**Statement 1 –** Neeta is 15 years old.

The equality symbol can be mathematically expressed as x = 15.

**Statement 2 – **Now if I say Neetaâ€™s age is at least 15 years, then this can be expressed as xâ‰¥15.

Thus Statement 1 is equation and Statement 2 is an inequality.

Let’s learn about solving inequalities in two variables.

**Solving Linear Inequalities**

Let us now discuss the method of solving inequalities graphically. The graph of a linear equation is a straight line and any point in the Cartesian plane with respect to that will lie on either side of the line. Let us consider the expression ax + by for linear equation in two variables. The following inequalities can be framed using this expression.

**1. ax + by < c**

**2. ax + by â‰¤ c**

**3. ax + by > c**

**4. ax + by â‰¥ c**

For solving these inequalities consider the line ax + by = c, aâ‰ 0 and b â‰ 0. The graph of this line is as shown below.

The graph of the line divides the Cartesian plane into two halves. All the points (x, y) lying on the line ax + by = c satisfy the equation i.e., both sides of the equation is balanced. The point (Î±, Î²) lying on the line ax + by = c represent a solution to the line. Thus, aÎ± + bÎ² = c.

Now consider a point N (Î±, Ï’) lying in the upper half of the plane. It is pretty obvious from the graph that Ï’ >Î². Also, since the graph is represented by a straight line, it implies b>0 or else the equation ax + by = c would merely represent a point.

â‡’bÏ’> bÎ²

â‡’aÎ± + bÏ’ > aÎ± + bÎ² (Adding aÎ± on both sides)

â‡’aÎ± + bÏ’> c

This inequality signifies that any point Q(Î±, Ï’) lying above or in the upper half of the plane or the region indicated by I formed by the line ax + by = c would satisfy the inequality ax + by > c.

## Linear Inequalities Graphing

For solving inequalities mentioned above, we graph the linear expression and make the following conclusions about the inequality.

### Â ax + by < c

The region lying below the line ax + by = c or the region marked II consists of all those points that would satisfy the inequality ax + by < c. Region II is, therefore, the solution region for the inequality of the type ax + by < c. Since the solution region excludes the line ax + by = c, therefore the line is dotted.

** Â ax + by â‰¤ c**

The region lying below and including the line ax + by = c or the region marked II consists of all those points that would satisfy the inequality ax + by â‰¤ c. Region II is, therefore, the solution region for the inequality of the type ax + by â‰¤ c.

### Â ax + by > c

The region lying in the upper half the line ax + by = c or the region marked I consist of all those points that would satisfy the inequality ax + by > c. Region I is, therefore, the solution region for the inequality of the type ax + by > c. Since the solution region excludes the line ax + by = c, therefore the line is dotted.

### Â ax + by â‰¥ c

The region lying below and including the line ax + by = c or the region marked I consist of all those points that would satisfy the inequality ax + by â‰¥ c. Region I is, therefore, the solution region for the inequality of the type ax + by â‰¥ c.

### Solving Linear Inequalities Example

**Example: Solve -2(x+3)<10**

Solution: Given,Â 2(x+3)<10

Divide both the sides by 2, we get;

-(x+3)<5

-x-3<5

Add 3 both the sides

-x-3+3 < 5+3

-x < 8

Divide by -1 both the sides

-x/-1 < 8/-1

x>-8

Hence, the solution.

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