NCERT Solutions for Class 8 Maths Exercise 16.1 Chapter 16 Playing With Number

NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers, contains solutions for all exercise questions. While solving the exercise questions, students often face some doubts and eventually pile them up. To help the students clear all their doubts instantly, the NCERT class 8 maths solutions for chapter 16 are provided here. Download Class 8 Mathematics NCERT Solutions and strengthen your basics.

Download PDF of NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Exercise 16.1

 

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Access Other Exercise Solutions of Class 8 Maths Chapter 16 Playing with Numbers

Exercise 16.2 Solutions : 4 Questions (Short answer type)

Access Answers to NCERT Class 8 Maths Chapter 16 Playing with Numbers Exercise 16.1

Find the values of the letters in each of the following and give reasons for the steps involved.

1.

Ncert solutions class 8 chapter 16-1

Solution:

Say, A = 7 and we get,

7+5 = 12

In which one’s place is 2.

Therefore, A = 7

And putting 2 and carry over 1, we get

B = 6

Hence A = 7 and B = 6

2.

Ncert solutions class 8 chapter 16-2

Solution:

If A = 5 and we get,

8+5 = 13 in which ones place is 3.

Therefore, A = 5 and carry over 1 then

B = 4 and C = 1

Hence, A = 5, B = 4 and C = 1

3.

Ncert solutions class 8 chapter 16-3

Solution:

On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get,

AxA = 6×6 = 36 in which ones place is 6.

Therefore, A = 6

4.

Ncert solutions class 8 chapter 16-4

Solution:

Here, we observe that B = 5 so that 7+5 =12

Putting 2 at ones place and carry over 1 and A = 2, we get

2+3+1 =6

Hence A = 2 and B =5

5.

Ncert solutions class 8 chapter 16-5

Solution:

Here on putting B = 0, we get 0x3 = 0.

And A = 5, then 5×3 =15

A = 5 and C=1

Hence A = 5, B = 0 and C = 1

6.

Ncert solutions class 8 chapter 16-6

Solution:

On putting B = 0, we get 0x5 = 0 and A = 5, then 5×5 =25

A = 5, C = 2

Hence A = 5, B = 0 and C =2

7.

Ncert solutions class 8 chapter 16-7

Solution:

Here product of B and 6 must be same as ones place digit as B.

6×1 = 6, 6×2 = 12, 6×3 = 18, 6×4 =24

On putting B = 4, we get the ones digit 4 and remaining two B’s value should be44.

Therefore, for 6×7 = 42+2 =44

Hence A = 7 and B = 4

8.

Ncert solutions class 8 chapter 16-8

Solution:

On putting B = 9, we get 9+1 = 10

Putting 0 at ones place and carry over 1, we get for A = 7

7+1+1 =9

Hence, A = 7 and B = 9

9.

Ncert solutions class 8 chapter 16-9

Solution:

On putting B = 7, we get 7+1 =8

Now A = 4, then 4+7 =11

Putting 1 at tens place and carry over 1, we get

2+4+1 =7

Hence, A = 4 and B = 7

10.

Ncert solutions class 8 chapter 16-10

Solution:

Putting A = 8 and B = 1, we get

8+1 =9

Now, again we add2 + 8 =10

Tens place digit is ‘0’ and carry over 1. Now 1+6+1 = 8 =A

Hence A = 8 and B =1


NCERT Class 8 Maths Chapter 16 Playing with Numbers Exercise 16.1, based on the topics: Numbers in General Form, Games with Numbers, and Letters for Digits. The problems are to find out which letter represents which digit. At the end of this section, students will be able to crack the puzzles in which letters take the place of digits in an arithmetic ‘sum’ and many more.

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