NCERT Solutions for Class 9 Maths Exercise 11.2 Chapter 11 Construction

Construction of various shapes, especially in Geometry, is important as we learn various concepts through this topic. It is helpful as it has significance in other fields of study too. Moreover, this particular concept is important from an academic perspective as it carries a significant number of marks (28 marks from Unit 4, to be precise). Therefore, it is important to learn this concept for exams, and one of the best guides to use for the same is the NCERT Solutions for Class 9 Maths Chapter 11 Constructions Exercise 11.2 and 11.1. Also, NCERT Solutions is held in high regards by many students due to its ease-of-use and versatile content. Consequently, NCERT Solutions is one of the best guides for studies. We have ensured that the conceptual aspects are well-articulated in the chapter. Problems are explained with easy examples and a step-by-step guide for tougher questions. Besides our detailed guide, content is regularly refreshed with immediate changes with respect to CBSE guidelines (if any).

Download PDF of NCERT Solutions for Class 9 Maths Chapter 11 – Constructions Exercise 11.2

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Access Another Exercise Solutions of Class 9 Chapter 11 – Constructions

Access Answers to NCERT Class 9 Maths Chapter 11 – Constructions Exercise 11.2

1. Construct a triangle ABC in which BC = 7cm, ∠B = 75° and AB+AC = 13 cm.

Construction Procedure:

The steps to draw the triangle of given measurement is as follows:

1. Draw a line segment of base BC = 7 cm

2. Measure and draw ∠B = 75° and draw the ray BX

3. Take a compass and measure AB+AC = 13 cm.

4. With B as centre and draw an arc at the point be D

5. Join DC

6. Now draw the perpendicular bisector of the line DC and the intersection point is taken as A.

7. Now join AC

8. Therefore, ABC is the required triangle.

Ncert solutions class 9 chapter 11-13

2. Construct a triangle ABC in which BC = 8cm, ∠B = 45° and AB–AC = 3.5 cm.

Construction Procedure:

The steps to draw the triangle of given measurement is as follows:

1. Draw a line segment of base BC = 8 cm

2. Measure and draw ∠B = 45° and draw the ray BX

3. Take a compass and measure AB-AC = 3.5 cm.

4. With B as centre and draw an arc at the point be D on the ray BX

5. Join DC

6. Now draw the perpendicular bisector of the line CD and the intersection point is taken as A.

7. Now join AC

8. Therefore, ABC is the required triangle.

Ncert solutions class 9 chapter 11-14

3. Construct a triangle PQR in which QR = 6cm, ∠Q = 60° and PR–PQ = 2cm.

Construction Procedure:

The steps to draw the triangle of given measurement is as follows:

1. Draw a line segment of base QR = 6 cm

2. Measure and draw ∠Q = 60° and let the ray be QX

3. Take a compass and measure PR–PQ = 2cm.

4. Since PR–PQ is negative, QD will be below the line QR.

5. With Q as centre and draw an arc at the point be D on the ray QX

6. Join DR

7. Now draw the perpendicular bisector of the line DR and the intersection point is taken as P.

8. Now join PR

9. Therefore, PQR is the required triangle.

Ncert solutions class 9 chapter 11-15

4. Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY+YZ+ZX = 11 cm.

Construction Procedure:

The steps to draw the triangle of given measurement is as follows:

1. Draw a line segment AB which is equal to XY+YZ+ZX = 11 cm.

2. Make an angle ∠LAB = 30° from the point A.

3. Make an angle ∠MBA = 90° from the point B.

4. Bisect ∠LAB and ∠MBA at the point X.

5. Now take the perpendicular bisector of the line XA and XB and the intersection point be Y and Z respectively.

6. Join XY and XZ

7. Therefore, XYZ is the required triangle

Ncert solutions class 9 chapter 11-16

5. Construct a right triangle whose base is 12cm and sum of its hypotenuse and other side is 18 cm.

Construction Procedure:

The steps to draw the triangle of given measurement is as follows:

1. Draw a line segment of base BC = 12 cm

2. Measure and draw ∠B = 90° and draw the ray BX

3. Take a compass and measure AB+AC = 18 cm.

4. With B as centre and draw an arc at the point be D on the ray BX

5. Join DC

6. Now draw the perpendicular bisector of the line CD and the intersection point is taken as A.

7. Now join AC

8. Therefore, ABC is the required triangle.

Ncert solutions class 9 chapter 11-17


Constructions Exercise 11.2 includes 5 practical questions that are based on the concept of geometrical shapes and their process of construction. These exercise questions are crucial from an examination perspective as it helps the students to understand and solve the various questions that might arise from the topic. It also helps students to realize a particular concept’s real-world applications and its significance. Discover various concepts such as a bisector, perpendicular bisector and more, only on NCERT Solutions For Class 9 Maths.

Key Features of NCERT Solutions for Class 9 Maths Chapter 11 – Constructions Exercise 11.2

  1. Well-articulated content
  2. Topics presented in a structured format
  3. Important formulas are explained
  4. Comprehensive content
  5. Content created by experienced teachers

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