If the dissociation constant of [Cu(NH3)4]2+ is X × 1012. Determine X.
Cu2+ + NH3 ⇌ [Cu(NH3)]2+ K1 = 104 [Cu(NH3)]2+ + NH3 ⇌ [Cu(NH3)]2+ K2 = 1.58 × 103 [Cu(NH3)2]2+ +... View Article
Cu2+ + NH3 ⇌ [Cu(NH3)]2+ K1 = 104 [Cu(NH3)]2+ + NH3 ⇌ [Cu(NH3)]2+ K2 = 1.58 × 103 [Cu(NH3)2]2+ +... View Article
Answer: 1382 Given: Keq= 100 at 300K and ΔGo = –xR Joule ΔGo = -RTln(Keq) = -2.303RTlog(Keq) = -1381.8R Therefore,... View Article
Answer: 1518 \(\begin{array}{l}t = \frac{1}{k}ln\frac{[A_{o}]}{[A]} = \frac{1\times 2.303}{3.33\times 10^{-4}}log\frac{[5]}{[3]} = \frac{1\times 2.303}{3.33\times 10^{-4}}\times 0.22\end{array} \) = 30 x 103 x... View Article
Answer: 4 Let us look at the half reactions i.e. oxidation and reduction separately. Oxidation: S8 → S2O2-3 S8 +... View Article
Cl2(g) ⇌ 2Cl(g) Answer: 5 According to the question: Cl2 ⇌ 2Cl [Ptotal = 1 atm]. Moles of Cl2 =... View Article
Answer: P > S > Si > Mg > Al In the third period of the periodic table, Element Valence... View Article
a. Cu, Zn, Sn b. Al, Mg, Mn, Cu c. Cu, Ni, Fe d. Cu, Sn, Fe Answer: (a) The... View Article
a. 1/n (0 to 1) b. 1/n (0.1 to 0.5) c. log n d. log (1/n) Answer: (a) According to... View Article
\(\begin{array}{l}Al + NaOH \rightarrow X\overset{Y(g)}{\rightarrow}Z\end{array} \) a. X = Na[Al(OH)4] ; Y = CO2 ; Z = Al2O3.xH2O b. X... View Article
a. Cu b. Zn c. Cr d. Co Answer: (a) According to the electrochemical series, elements present above H have... View Article
1) I2 + H2O2 + 2OH– → 2I– + 2H2O + O2 2) H2O2 + HOCl → Cl– + H3O+... View Article
a. S-1 is true and S-2 is false b. S-1 is false and S-2 is true c. Both are false... View Article
a. Sphalerite b. Malachite c. Calamine d. Siderite Answer: (a) Cyanide acts as a depressant and is therefore used to... View Article
a) TiCl4, SiCl4 b) SO2-3, CrO2-3 c) NH3, NO–3 d) ClF3, BCl3 a. A, B b. A, C c. B,... View Article
Answer: (c)
a. Cu / ∆ / high pressure b. Molybdenum Oxide c. Manganese Acetate d. Potassium Permanganate Answer: (b) Molybdenum Oxide... View Article
Answer: (a) Alkenes reacting with cold, dilute KMnO4 will give 1,2-diols (vicinal diols). This is called syn- dihydroxylation. CrO3 cannot... View Article
Answer: (b)
Rajya Sabha TV programs and discussions are very insightful and informative from a UPSC perspective. In this article, we provide... View Article
Answer: (c) Since HI is an acid, the pi bond attacks H+ and a carbocation intermediate is formed. Since this... View Article