The PDF of RD Sharma Solutions for Exercise 3.3 of Class 7 Maths Chapter 3 Decimals is provided here. The questions present have been solved by BYJU’S subject experts in Maths, and will help students solve the problems without any difficulties. This exercise contains ten questions with many sub-questions. By practising sincerely, the students can obtain excellent results in the Class 7 annual exam by using RD Sharma Solutions. By practising the RD Sharma Solutions for Class 7, students will be thorough about their concepts. This exercise deals with the division of decimals.
RD Sharma Solutions for Class 7 Maths Chapter 3 – Decimals Exercise 3.3
Access answers to Maths RD Sharma Solutions for Class 7 Chapter 3 – Decimals Exercise 3.3
1. Divide:
(i) 142.45 by 10
(ii) 54.25 by 10
(iii) 3.45 by 10
(iv) 0.57 by 10
(v) 0.0043 by 10
(vi) 0.004 by 10
Solution:
(i) Given 142.45 by 10
Now shifting the decimal point by one place to the left we can get the result
142.45/10 = 14.245
(ii) Given 54.25 by 10
Now shifting the decimal point by one place to the left we can get the result
54.25/10 = 5.425
(iii) Given 3.45 by 10
Now shifting the decimal point by one place to the left we can get the result
3.45/10 = 0.345
(iv) Given 0.57 by 10
Now shifting the decimal point by one place to the left we can get the result
0.57/10 = 0.057
(v) Given 0.0043 by 10
Now shifting the decimal point by one place to the left we can get the result
0.0043/10 = 0.0043
(vi) Given 0.004 by 10
Now shifting the decimal point by one place to the left we can get the result
0.004/10 = 0.0004
2. Divide:
(i) 459.5 by 100
(ii) 74.3 by 100
(iii) 5.8 by 100
(iv) 0.7 by 100
(v) 0.48 by 100
(vi) 0.03 by 100
Solution:
(i) Given 459.5 by 100
Now shifting the decimal point by two places to the left we can get the result
459.5/100 = 4.595
(ii) Given 74.3 by 100
Now shifting the decimal point by two places to the left we can get the result
74.3/100 = 0.743
(iii) Given 5.8 by 100
Now shifting the decimal point by two places to the left we can get the result
5.8/100 = 0.058
(iv) Given 0.7 by 100
Now shifting the decimal point by two places to the left we can get the result
0.7/100 = 0.007
(v) Given 0.48 by 100
Now shifting the decimal point by two places to the left we can get the result
0.48/100 = 0.0048
(vi) Given 0.03 by 100
Now shifting the decimal point by two places to the left we can get the result
0.03 / 100 = 0.0003
3. Divide:
(i) 235. 41 by 1000
(ii) 29.5 by 1000
(iii) 3.8 by 1000
(iv) 0.7 by 1000
Solution:
(i) Given 235. 41 by 1000
Now shifting the decimal point by three places to the left we can get the result
235. 41/1000 = 0.23541
(ii) Given 29.5 by 1000
Now shifting the decimal point by three places to the left we can get the result
29.5/1000 = 0.0295
(iii) Given 3.8 by 1000
Now shifting the decimal point by three places to the left we can get the result
3.8 /1000 = 0.0038
(iv) Given 0.7 by 1000
Now shifting the decimal point by three places to the left we can get the result
0.7 /1000 = 0.0007
4. Divide:
(i) 0.45 by 9
(ii) 217.44 by 18
(iii) 319.2 by 2.28
(iv) 40.32 by 9.6
(v) 0.765 by 0.9
(vi) 0.768 by 1.6
Solution:
(i) Given 0.45 by 9
0.45 by 9 = 0.05
(ii) Given 217.44 by 18
217.44 by 18 = 12.08
3. Given 319.2 by 2.28
319.2 by 2.28 = 140
(iv) Given 40.32 by 9.6
40.32 by 9.6 = 4.2
(v) Given 0.765 by 0.9
0.765 by 0.9 = 0.85
(vi) Given 0.768 by 1.6
0.768 by 1.6 = 0.48
5. Divide:
(i) 16.64 by 20
(ii) 0.192 by 12
(iii) 163.44 by 24
(iv) 403.2 by 96
(v) 16.344 by 12
(vi) 31.92 by 228
Solution:
(i) Given 16.64 by 20
16.64 by 20 = 0.832
(ii) Given 0.192 by 12
0.192 by 12 = 0.016
(iii) Given 163.44 by 24
163.44 by 24 = 6.81
(iv) Given 403.2 by 96
403.2 by 96 = 4.2
(v) Given 16.344 by 12
16.344 by 12 = 1.362
(vi) Given 31.92 by 228
31.92 by 228 = 0.14
6. Divide:
(i) 15.68 by 20
(ii) 164.6 by 200
(iii) 403.80 by 30
Solution:
(i) Given 15.68 by 20
15.68 by 20 = 0.784
(ii) Given 164.6 by 200
164.6 by 200 = 0.823
(iii) Given 403.80 by 30
403.80 by 30 = 13.46
7. Divide:
(i) 76 by 0.019
(ii) 88 by 0.08
(iii) 148 by 0.074
(iv) 7 by 0.014
Solution:
(i) Given 76 by 0.019
Multiply both numerator and denominator by 1000 then divide
= 76000/19
76 by 0.019 = 4000
(ii) Given 88 by 0.08
Multiply both numerator and denominator by 100 then divide
= 8800/8
88 by 0.08 = 1100
(iii) Given 148 by 0.074
Multiply both numerator and denominator by 1000 then divide
= 14800/74
148 by 0.074 = 2000
(iv) Given 7 by 0.014
Multiply both numerator and denominator by 1000 then divide
= 7000/14
7 by 0.014 = 500
8. Divide:
(i) 20 by 50
(ii) 8 by 100
(iii) 72 by 576
(iv) 144 by 15
Solution:
(i) Given 20 by 50
20 by 50 = 0.4
(ii) Given 8 by 100
8 by 100 = 0.08
(iii) Given 72 by 576
72 by 576 = 0.125
(iv) Given 144 by 15
144 by 15 = 9.6
9. A vehicle covers a distance 0f 43.2 km in 2.4 litres of petrol. How much distance will travel in 1 litre of petrol?
Solution:
Given distance covered by vehicle in 2.4 litres of petrol is = 43.2 km
Distance travel by vehicle in 1 litre of petrol = 43.2/2.4
Multiply both numerator and denominator by 10 then we get 432/24
On dividing
Therefore 18km can travel in 1litre of petrol.
10. The total weight of some bags of wheat is 1743 kg. If each bag weighs 49.8 kg, how many bags are there?
Solution:
Given total weight of total bags = 1743 kg
Each bag weighs = 49.8 kg
Number of bags = 1743/49.8
Multiply both numerator and denominator by 10 then we get 17430/498
On dividing
Therefore number of bags are 35
11. Shikha cuts 50 m of cloth into pieces 0f 1.25 m each. How many pieces does she get?
Solution:
Given that total length of cloth = 50 m
Length of each piece = 1.25 m
Number of cloth piece = 50/1.25
Multiply both numerator and denominator by 100 then we get 5000/125
On dividing
Number of cloth piece = 40
12. Each side of a rectangular polygon is 2.5cm in length. The perimeter of the polygon is 12.5 cm. How many sides does the polygon have?
Solution:
Given that length of each side of polygon is = 2.5 cm
Perimeter of polygon = 12.5 cm
Number of sides = 12.5/2.5
Multiply both numerator and denominator by 10 then we get 125/25
On dividing
Number of sides of polygon is 5
13. The product of two decimals is 42.987. If one of them is 12.46, find the other.
Solution:
Given that product of two decimals = 42.987
One of the number is = 12.46
Another number is = 42.987/12.46
Multiply both numerator and denominator by 1000 then we get 42987/12460
On dividing
Another number is 3.45
14. The weight of 34 bags of sugar is 3483.3 kg. If all bags weigh equally, find the weight of each bag.
Solution:
Given that weight of 34 bags of sugar is = 3483.3 kg
Weight of each bag = 3483.3/34
Multiply both numerator and denominator by 10 then we get 34833/34
On dividing
Weight of each bag = 102.45 kg
15. How many buckets of equal capacity can be filled from 586.5 litres of water, if each has capacity of 8.5 litres?
Solution:
Given that capacity of each bucket = 8.5 litres
Total water available = 586.5 litres
Number of buckets = 586.5/8.5
Multiply both numerator and denominator by 10 then we get 5865/85
On dividing
Number of buckets = 69
RD Sharma Solutions for Class 7 Maths Chapter – 3 Decimals Exercise 3.3
RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals Exercise 3.3 have problems which are based on the division of decimals. Some of the topics focused on prior to this exercise are listed below.
- Dividing a decimal by 10, 100, 1000
- Dividing a decimal by the whole number
- Dividing a decimal by a decimal
The solutions to all questions in the RD Sharma books are given here in a detailed and step-by-step way to help students understand the concepts more effectively.
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