The PDF of RD Sharma Solutions for Class 7 Maths Chapter 10 Unitary Method is provided here. Students can easily download the PDF for free. RD Sharma Solutions help students to understand the topics better and make them thorough with the concepts. In order to help the students, our experts in Maths have solved all questions accurately. RD Sharma Solutions for Class 7, given here, contain the solutions to all the problems present in these exercises. The solutions PDF help students to get good score in the final examination while also providing extensive knowledge about the subject, as Class 7 builds a foundation for higher grades. Let us have a look at some of the concepts that are being discussed in this chapter.
- Definition of the unitary method – In this method, we first find the value of one unit from the value of the given number of articles, and then, we use it to find the value of the required number of articles.
RD Sharma for Class 7 Maths Chapter 10 Unitary Method
Access answers to Maths RD Sharma Solutions for Class 7 Chapter 10 – Unitary Method
Exercise 10.1 Page No: 10.2
1. 20 chocolates cost Rs 320. Find the cost of 35 such chocolates.
Solution:
Given cost of 20 chocolates = Rs 320
Cost of 1 chocolate = (320/20)
Therefore, the cost of 35 chocolates = (320/20) × 35
= Rs 560
2. The cost of 40 meters of cloth is Rs 200. Find the cost of 50 meters of cloth.
Solution:
Given cost of 40 meters of cloth = Rs 200
Cost of 1 meter of cloth = (200/40)
Therefore, the cost of 50 chocolates = (200/40) × 50
= Rs 250
3. A car can cover a distance of 522 km on 36 litres of petrol. How far can it travel on 14 litres of petrol?
Solution:
Given that number of kilometres a car can cover by using 36 litres of petrol = 522 km
Number of kilometres a car can cover by using 1 litre of petrol = 522/36
Hence, the number of kilometres a car can cover by using 14 litres = (522/36) × 14
= 203 km
4. Travelling 900 km by rail costs Rs 280. What would be the fare for a journey of 360 km when a person travels by the same class?
Solution:
Given that cost of travelling 900 km by rail = Rs 280
Therefore cost of travelling 1 km by rail = (280/900)
Hence, Cost of travelling 360 km by rail = (280/900) × 360
= Rs 112
5. If 6 oil tankers can be filled by a pipe in 4(1/2) hours, how long does the pipe take to fill 4 such oil tankers?
Solution:
Given that time taken by 6 oil tankers to be filled by a pipe = 4 (1/2) hours = (9/2) hours
Time taken by 1 oil tanker to be filled by a pipe = (9/2)/6 hours = 9/ (2 x 6) = 9/12 hours
Hence time taken by 4 oil tankers to be filled by a pipe = (9/12) × 4
= 3 hours
6. 3/4 of the salary per month is Rs 600. What is the salary per month?
Solution:
Given that 3/4 of the salary per month = 600
Let the salary of the month be x
Therefore ¾ × x = 600
x = 600 × (4/3)
x = 800
Therefore salary per month is Rs 800
7. The cost of 32 tables is Rs 23520. Find the number of such tables that can be purchased for Rs 51450.
Solution:
Given that number of tables bought for Rs 23520 = 32
Number of tables bought for Rs 1 = 32/23520
Hence, number of tables bought for Rs 51450 = (32/23520) × 51450 = 70
8. The yield of wheat from 6 hectares is 280 quintals. Find the number of hectares required for a yield of 225 quintals.
Solution:
Given number of hectares required for a yield of 280 quintals = 6 hectares
Number of hectares required for a yield of 1 quintal = 6/280 hectares
Hence, the number of hectares required for a yield of 225 quintals = 6/280 × 225
= 4 23/28 hectares
9. Fifteen postcards cost Rs 2.25. What will be the cost of 36 postcards? How many postcards can we buy in Rs 45?
Solution:
Given cost of 15 postcards = Rs 2.25
Cost of 1 postcard is = 2.25/15
Hence, the cost of 36 postcards = (2.25/15) × 36
= Rs 5.40
Number of postcards bought for Rs 2.25 = 15
Numbers of postcards bought for Rs 1 = 15/2.25
Hence number of postcards bought for Rs 45 = (15/2.25) × 45
= 300
10. A rail journey of 75 km costs Rs 215. How much will a journey of 120 km cost?
Solution:
Given cost of a rail journey of 75 km = Rs 215
Cost of a rail journey of 1 km = 215/75
Hence, cost of a rail journey of 120 km = (215/75) × 120
= Rs 344
11. If the sales tax on a purchase worth Rs 60 is Rs 4.20. What will be the sales tax on the purchase worth of Rs 150?
Solution:
Given sales tax on the purchase worth of Rs 60 = Rs 4.20
Sales tax on the purchase worth of Rs 1 = Rs 4.2060
Hence, sales tax on the purchase worth of Rs 150 = (4.20/60) × 150
= Rs 10.50
12. 52 packets of 12 pencils each, cost Rs 499.20. Find the cost of 65 packets of 10 pencils each.
Solution:
Given total number of pencils in 52 packets of 12 pencils each = 52 × 12
= 624 pencils
Also, given that cost of 624 pencils = Rs 499.20
Cost of 1 pencil = (499.20/624)
Number of pencils in 65 packets of 10 pencils each = 65 x 10
= 650 pencils
Therefore, cost of 650 pencils = (499.20/624) × 650
= Rs 520.
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