**According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 14 in NCERT Class 10 Maths Textbook.**

**CBSE Class 10 Maths Chapter 15 Probability Objective Questions** cover Unit 6 – Statistics and Probability. Probability is one of the chapters in Class 10 Maths that contains the concepts which are most likely to be used in daily life. Some of the key concepts discussed in this chapter include the difference between experimental probability and theoretical probability, how the probability of an impossible event is 0, complementary events, finding the probability of different events, and much more. Keeping in mind the recent modification of the exam pattern, CBSE students have to be more thorough with answering the Class 10 Maths Chapter 15 Probability Objective Questions and MCQs.

Students should be thorough with these CBSE Class 10 Maths Objective Questions, which will help them score well in the board exams because MCQs make up a major part of the exam questions, amounting to good scores.

## Download CBSE Class 10 Maths Chapter 15 – Probability Objective Questions Free PDF

### Sub-topics Covered in Chapter 15 – Probability

Students will explore concepts like the multiplication rule of probability, Bayesâ€™ theorem, and the independence of events in this chapter. Find below the list of topics that are covered in the objective questions from this chapter:

15.1 Introduction to Probability (1 MCQ)

15.2 Complementary Events (4 MCQs)

15.3 Experimental Probability (4 MCQs)

15.4 Theoretical Probability (9 MCQs)

### Introduction to Probability

**1. What is the probability that the minute and hour hands of a clock will form an acute angle at any given time?**

**A. PÂ >Â 0.5**

**B. PÂ =Â 0.5**

**C. PÂ <Â 0.5**

**D. PÂ â‰¤Â 0.25**

**Answer:** (C) PÂ <Â 0.5

**Solution:** The amount of time in a period of 12 hours when the hands will form an acute angle will be the same as that for an obtuse angle. So, you would think that the probability is 12. But if you take into account the small amounts of time when the hands are aligned (0^{âˆ˜}), hands are at right angles, and hands are facing in opposite directions (180^{âˆ˜}), then the probability would be slightly less than 0.5.

### Complementary Events

**2. Two dice are thrown at the same time. Find the probability of getting different values on both.**

**A. 5/6**

**B. Â½**

**C. 1/6**

**D. 1/36**

** Answer: **(A) 5/6

**Solution: **Let E be the event of getting different values on both dice. The complementary event is getting the same value on both, for which there are 6 favourable outcomes: (1,1), (2,2), (3,3), (4,4), (5,5) and (6,6). Thus, P (not E) = 1/6

Thus, P (E) = 1 – P (not E) = 1 â€“ (1/6) = 5/6.

**3. If P (A) and P (not A) are complementary events, and P (A) = 0.15, then P (not A) =?**

**A. 0.35**

**B. Cannot be determined**

**C. 0.85**

**D. 0.3**

**Answer:** (C) 0.85

**Solution: **Given, P (A) = 0.15

As P (A) and P (not A) are complementary events, P (A) + P (not A) = 1

P (not A) = 1 â€“ P (A) = 1 â€“ 0.15 = 0.85.

**4. What is the probability of not picking a king if you choose randomly from a pack of 52 cards?**

**A. 1/13**

**B. 12/13**

**C. 51/52**

**D. 1/52**

** Answer:** (B) 12/13

**Solution:** Since there are 4 kings in a deck of 52, the probability of drawing a king isÂ 4/52Â =Â 1/13.

Hence, the probability of not picking a king is 1 â€“Â 1/13Â =Â 12/13.

**5. What is the probability of not picking a face card when you draw a card at randomÂ from a pack of 52 cards?**

**A. 1/13**

**B. 4/13**

**C. 10/13**

**D. 12/13**

** Answer:** (C) 10/13

**Solution:** Since there are 12 face cards in a deck of 52 cards, the probability of drawing a face card is 12/52 = 3/13

Hence, the probability of not picking a face card = 1 â€“ 3/13 = 10/13

### Experimental Probability

**6. 24 cards numbered 1, 2, 3, …., 23, 24 are put in a box and mixed thoroughly. One person draws a card from the box. The probability that the number on the card is divisible by 2 or 3, or both is**

**A. 5/6**

**B. 2/3**

**C. 1/3**

**D. 1/6**

**Answer:** (B) 2/3

**Solution: **The total possible outcomes = 24

Numbers divisible by only 2 are 2, 4, 8, 10, 14, 16, 20, 22 (8 numbers) ——— (1)

Numbers divisible only by 3 are 3, 9, 15, 21 (4 numbers) ——— (2)

Numbers divisible by both 2 and 3 are 6, 12, 18, and 24 (4 numbers) ——— (3)

From (1), (2) and (3), we see that the number of favourable outcomesÂ is 16 (i.e., 8 + 4 + 4).

We know that the probability of an event E, P (E) = number of favourable outcomes/ total number of outcomes

= 16/24

= 2/3

Hence, the probability that the number on the card is divisible by 2 or 3, or both is 2/3.

**7. A bag contains 6 black, 7 red, and 2 white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is black or white.**

**A. 8/15**

**B. 3/5**

**C. 2/3**

**D. 1/5**

** Answer:** (A) 8/15

**Solution:** Total number of balls = 15

Number of balls that are either black or white = 8

Hence, the number of favourable outcomes of the ball drawn being black or white is 8.

We know that the probability of an event E, P (E) =number of favourable outcomes/total number of outcomes.

So, the required probability isÂ 8/15.

**8. A card is drawn from a well-shuffled deck of playing cards. Find the probability of drawing a black card which is neither a face card nor an ace.**

**A. 10/13**

**B. 9/13**

**C. 9/26**

**D. 9/52**

**Answer:** (C) 9/26

**Solution:** In each suit, there are 9 cards that are not face cards or ace cards.

Hence, there will be a total of 18 cards in a deck that are black and are not face cards or ace cards.

We know that, Probability of an event E, P (E) = number of favourable outcomes/total number of outcomes.

Hence, the required probability is 18/52 = 9/26.

**9. Each of the letters of the word PILOTS is on separate cards, face down on the table. If you pick a card at random, what is the probability that the letter will be a T or an L?Â **

**A. 1/6**

**B. 1/3**

**C. 1/2**

**D. 2/3**

**Answer:** (B) 1/3

**Solution:** There are 6 outcomes, out of which 2 are favourable (which are getting T or L).

Probability of an event E, P (E) = number of favourable outcomes/ total number of outcomes

The required probability = 2/6 = 1/3.

### Theoretical Probability

**10. A single die is rolled. The probability of getting 1 or an even number is**

**A. 1/6**

**B. 4/6**

**C. 5/6**

**D. 3/6**

**Answer:** (B) 4/6

**Solution:** The favourable outcomes are 1, 2, 4 and 6.

We have 4 favourable outcomes out of the total outcomes of 6.

Thus, the required probability = 4/6.

**11. A bucket contains 10 brown balls, 8 green balls, and 12 red balls, and you pick one randomly without looking. What is the probability that the ball will be brown?Â **

**A. 0.33**

**B. 0.61**

**C. 1/3**

**D. 4/15**

**Answer: **(C) 1/3

**Solution: **There are a total of 10 + 8 + 12 = 30 balls, out of which 10 are brown.

Thus, the required probability is 10/30 = 1/3.

**12. A number is chosen randomly among the first 100 natural numbers. Find the probability that the number chosen is prime.**

**A. 1/4**

**B. 3/10**

**C. 29/100**

**D. 27/100**

** Answer:** (A) 1/4

**Solution: **There are 25 prime numbers in the set of the first 100 natural numbers, and they are as follows:

**2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
**

We know that the Probability of an event is E, P (E) =number of favourable outcomes/total number of outcomes.

Hence, the required probability =Â 25/100Â =Â 1/4.

**13. From a well-shuffled pack of 52 cards, a card is drawn at random; find the probability that it is a spade.**

**A. 1/2**

**B. 1/4**

**C. 1/51**

**D. 1/52**

** Answer:** (B) Â¼

**Solution:** There are 13 spades in a deck of 52.

Hence, the probability of drawing a spade is 13/52 = Â¼.

**14. A die is thrown once; the probability of getting a composite number on the die is**

**A. 1/3**

**B. 1/2**

**C. 2/3**

**D. 1/6**

**Answer:** (A) 1/3

**Solution:** The composite numbers among the numbers on a die are 4 and 6. Thus, we have 2 favourable outcomes out of a total of 6 outcomes. Hence, the required probability isÂ 2/6Â =Â 1/3.

**15. The probability of an event of a trial**

**A. is greater than 1**

**B. 0**

**C. lies between 0 and 1 (both inclusive)**

**D. 1**

**Answer:** (C) lies between 0 and 1 (both inclusive)

** Solution:** The probability of any event will lie between 0 and 1, both included

**16. What is the probability of getting all heads or all tails when three coins are tossed simultaneously?**

**A. 3/4**

**B. 1/2**

**C. 1/4**

**D. 1/8**

**Answer:** (C) 1/4

**Solution:** When three coins are tossed simultaneously, there are 8 possible outcomes, which are (HHH), (HHT), (HTH), (THH), (HTT), (THT), (TTH), (TTT), where H represents the head, and T represents the tail.

The favourable outcomes of getting all heads or all tails are HHH and TTT.

We know that the probability of an event E, P (E) = Number of favourable outcomes /Total number of outcomes.

Hence, the required probability =Â 2/8Â =Â 1/4

**17. There are 5 green, 6 black, and 7 white balls in a bag. A ball is drawn at random from the bag. Find the probability that it is not white.**

**A. 5/18**

**B. 2/13**

**C. 7/18**

**D. 11/18**

**Answer:** (D) 11/18

**Solution: **Given,

Number of green balls = 5

Number of black balls = 6

Number of white balls = 7

Total numberÂ of outcomes = 5 + 6Â + 7 = 18

There are 18 balls, out of which 11 are not white.

â‡’Â Number of favourable outcomes = 11

Probability of an event, P (E) = Number of favourable outcomes / Total number of outcomes

â‡’Â P (ballÂ drawn isÂ notÂ white) =Â 11/18

Therefore, the probability that the ball drawn is not white is 11/18.

Alternate Method:

P (ballÂ drawn is white) =Â 7/18

We know that,

P (ballÂ drawn is white) +Â P (ballÂ drawn is not white) = 1

Because the sum of the probability of an event and its complementary event is always 1,

â‡’Â P (ballÂ drawn is not white) = 1 – P (ballÂ drawn is white) =Â 1âˆ’7/18Â =Â 11/18

**18. From a set of 17 cards, numbered 1, 2, …. 17, one card is drawn. What is the probability that the number is a multiple of 3 or 7?**

**A. 5/17**

**B. 7/17**

**C. 8/17**

**D. 6/17**

**Answer: **(B) 7/17

**Solution: **The total number of possibleÂ outcomes is 17

The number of favourable outcomes is 3, 6, 7, 9, 12, 14 and 15

= 7

Thus, the required probability = number of favourable outcomes/total number of outcomes

=Â 7/17.

Solving these CBSE Class 10 Maths Chapter 15 – Probability Objective Questions gives an idea to the students about the MCQs asked in the board exam from this chapter. This will help them prepare well for the board exams and score good marks.

Also, find below the extra MCQs from the CBSE Class 10 Maths Chapter 15 for the students to practise.

### CBSE Class 10 Maths Chapter 15 Extra Questions

**1.Â Â When a dice is thrown, what is the probability of getting an even number?**

(a) 5/6

(b) 1

(c) 2/3

(d) 1/2

2. A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, then how many blue balls are there in a bag?

(a) 5

(b) 20

(c) 10

(d) 15

**3.Â What is the probability of getting a king of a red suit when a card is drawn from a well-shuffled deck of 52 cards?**

(a) 1/13

(b) 3/26

(c) 7/52

(d) 1/26

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