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For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is (¾) d, where ‘d’ is the separation between the plates of parallel plate capacitors. The new capacitance (C’) in terms of original capacitance (C0) is given by the following relation:

a. b. c. d. Answer: (a) C1 and C2 are in series and C’ is new capacitance Therefore, Therefore, Hence option (a)... View Article

A conducting bar of length L is free to slide on two parallel conducting rails as shown in the figure. Two resistors R1 and R2 are connected across the ends of the rails. There is a uniform magnetic field → B pointing into the page. An external agent pulls the bar to the left at a constant speed v. The correct statement about the directions of induced currents I1 and I2 flowing through R1 and R2 respectively is : a. I1 is in the clockwise direction and I2 is in the anticlockwise direction b. Both I1 and I2 are in a clockwise direction c. I1 is in the anticlockwise direction and I2 is in a clockwise direction d. Both I1 and I2 are in the anticlockwise direction

  Answer: (a) When the bar slides, the area of loop 1 decreases and that of loop 2 increases. Magnetic flux decreases in 1 and... View Article