Archives

∫0λ y / [√y + λ] dy =

1) (2 / 3) [2 - √2] λ √λ 2) (2 / 3) [2 + √2] λ √λ 3) (1 / 3) [2 - √2] λ √λ 4) (1 / 3) [2 + √2] λ √λ Solution: (1) (2 / 3) [2 - √2] λ... View Article