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If y2+loge(cos2x) = y, x∈(-π/2, π/2), then

a) |y’(0)|+|y’’(0)| = 1b) |y’’(0)| = 0c) |y’(0)|+|y’’(0)| = 3d) |y’’(0)| = 2Solution:yy’ + 2 (-tanx) = y’ ....(1)diff. w.r.t.x2y’’+2(y’)2 -2 sec2... View Article