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nitric acid ( hno3) acts only as an oxidizing agent while nitrous acid(hno2)acts both as an oxidizing as well as reducingagent. explain.

The oxidation number of nitrogen is HNO3 = +5; nevertheless, the maximum oxidation number of nitrogen is +5 and the minimum oxidation number of... View Article

if a solution has 100 times as many hydroxide ions as in pure water at 25ºc, then the ph of the solution at the same temperature will be

Temp = 25oC So, No of hydroxide in pure water is 10−7 A/C to this condition no of hydroxide ion is 2×10−7 So, poH = −log10[2×10−7] 7+0.301=7.301... View Article

if heat of atomisation of ch4(g) is x kj mol–1 then the bond energy of c – h bond (in kj/mol) will be

CH4 → C + 4H, ΔH= + 1665 kJ mol-1, Bond energy of (C – H) bond = 1665/4 = 416.2 kJ mol... View Article

A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?

Given, Selling price (SP) = Rs. 392 Profit percent = 22.5% Cost price (CP) = (100/122.5) × Rs. 392 = Rs. 320 So, the profit = SP - CP = Rs. 392 -... View Article

Find the integration of sinx cosx dx.

We know that, sin 2x = 2 sinx cosx So, sinx cosx = (1/2) sin 2x Now, ∫ sinx cosx dx = (1/2) ∫2 sin x cos x dx = (1/2) ∫sin 2x dx = (1/2) (-1/2)... View Article

Find the value of root 53.

The value of root 53 or the square root of 53 is:√53 = 7.28...This can be calculated by the long division method as follows.... View Article

What are the benefits of Vedic maths?

Some of the benefits of Vedic maths are listed below: Calculations become easy and short. We can do simplifications in less time. Students... View Article

What are factorial numbers?

Factorial of numbers can be calculated using the formula:n! = 1 × 2 × 3 × 4 × 5 × ... × (n - 1) × nLet... View Article

What is a perfect square number?

An integer that can be expressed as the square of another integer is called a perfect square. In other words, it is defined as the product of... View Article

Find the area bounded by the inverse of bijective function f(x) = 4x^3 + 6x, the x-axis and the ordinates x = 0 and x = 44.

Given bijective function is: f(x) = 4x3 + 6x f(0) = 4(0)3 + 6(0) = 0 ⇒ f-1(0) = 0 f(2) = 4(2)3 + 6(2) = 32 + 12 = 44 ⇒ f-1(44) = 2 So, the area... View Article

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