# NCERT Solutions For Class 6 Maths Chapter 8

## NCERT Solutions For Class 6 Maths Chapter 8 PDF Free Download

NCERT Solutions For Class 6 Maths Chapter 8, Decimals are intended to help students of class 8 to get habitual to the topic of decimals and practice the concepts thoroughly. These solutions are designed by our experts in BYJU’S, to provide exceptionally all possible methods to solve the questions based on CBSE syllabus for 6th class maths chapter 8. Students can download PDF of these materials to practice it online as well.

Sometimes students find it difficult to solve the exercise problems given at the end of the NCERT book for the practice of students. Therefore, we have introduced NCERT solutions for class 6, which will help students to resolve their doubts and difficulties with the help of solved questions. Apart from these, we have notes, question papers, which consist of sample papers and previous year question papers, and preparation tips study materials, which will be helpful for students to score good marks in the final exam.

## Class 6 Maths NCERT Solutions for Decimals

Decimal is a method of writing numbers where every digit describes the various powers of ten. It requires a dot to divide the fractional and integral parts of a number. Decimal point divides its fractional part on the right from the whole number on its left. The point acts as a separator between a unit and a component of a unit. The decimal numeral system is the conventional method for indicating non-integer and integer numbers. The system of expressing numbers in the decimal system is termed as Decimal notation. The decimal number system depends on the preceding. As we depart from left to right, the place value gets divided by 10.

Students are provided with all the topics covered in the chapter 8 Decimals such as;

• Introduction to Decimals and their representation on the number line
• Fractions as Decimals & Decimals as Fractions
• Comparing Decimals, operations on Fractions
• Decimals in daily life
• Word problems on decimals and more

### NCERT Questions For Decimals

#### Exercise 8.1

1. Using the given diagram write the data in form of numbers in the table given below:

 Hundreds (100) Tens (10) Ones (1) Tenths ($\frac{1}{10}$)

 Hundreds (100) Tens (10) Ones (1) Tenths ($\frac{1}{10}$) Number 0 3 1 2 31.2 1 1 0 4 110.4

2. Write the given decimals in the place value table.

(a) 20.4

(b) 0.4

(c) 18.5

(d) 302.1

 Hundreds (100) Tens (10) Ones (1) Tenths ($\frac{1}{10}$) Number (a) 0 2 0 4 20.4 (b) 0 0 0 4 0.4 (c) 0 1 8 5 18.5 (d) 3 0 2 1 302.1

3. Write the given values in the form of decimals:

(a) five-tenths

(b) Four tens and seven-tenths

(c) Sixteen point three

(d) Six hundred and eight-ones

(e) Nine hundred point one

(a) five-tenths = 5 tenths

= $\frac{5}{10}$

= 0.5

(b) Four tens and seven-tenths = 4 tens and 7 tenths

= $(4 \times 10) + \frac{7}{10}$

= 40 + 0.7

= 40.7

(c) Sixteen point three = 16.3

(d) Six hundred and eight-ones = 6 hundreds + 8 ones

= 600 + 8

= 608

(e) Nine hundred point one = 900.1

4. Write the fractions given below in the form of decimals:

(a) $\frac{5}{10}$

(b) $3 + \frac{7}{10}$

(c) $200 + 60 + 5 + \frac{1}{10}$

(d) $70 + \frac{8}{10}$

(e) $\frac{88}{10}$

(f) $4\frac{2}{10}$

(g) $\frac{3}{2}$

(h) $\frac{2}{5}$

(i) $\frac{12}{5}$

(j) $3\frac{3}{5}$

(k) $4\frac{1}{2}$

(a) $\frac{5}{10}$ = 0.5

(b) $3 + \frac{7}{10}$ = 3.7

(c) $200 + 60 + 5 + \frac{1}{10}$ = 200 + 60 + 5 + 0.1

= 265.1

(d) $70 + \frac{8}{10}$ = 70 + 0.8

= 70.8

(e) $\frac{88}{10}$ = $\frac{80 + 8}{10}$

= $\frac{80}{10}$ + $\frac{8}{10}$

= 8 + 0.8

= 8.8

(f) $4\frac{2}{10}$ = 4 + $\frac{2}{10}$

= 4 + 0.2

= 4.2

(g) $\frac{3}{2}$ = $\frac{3 \times 5}{2 \times 5}$

= $\frac{15}{10}$

= $\frac{10 + 5}{10}$

= $\frac{10}{10} + \frac{5}{10}$

= 1 + 0.5

= 1.5

(h) $\frac{2}{5}$ = $\frac{2 \times 2}{5 \times 2}$

= $\frac{4}{10}$

= 0.4

(i) $\frac{12}{5}$ = $\frac{12 \times 2}{5 \times 2}$

= $\frac{24}{10}$

= $\frac{20 + 4}{10}$

= $\frac{20}{10} + \frac{4}{10}$

= 2 + 0.4

= 2.4

(j) $3\frac{3}{5}$ = 3 + $\frac{3}{5}$

= 3 + $\frac{3 \times 2}{5 \times 2}$

= 3 + $\frac{6}{10}$

= 3 + 0.6

= 3.6

(k) $4\frac{1}{2}$ = 4 + $\frac{1}{2}$

= 4 + $\frac{1 \times 5}{2 \times 5}$

= 4 + $\frac{5}{10}$

= 4 + 0.5

= 4.5

5. Write the given decimals in the form of fraction. Reduce them to the lowest terms:

(a) 0.6

(b) 2.5

(c) 1.0

(d) 3.8

(e) 13.7

(f) 21.2

(g) 6.4

(a) 0.6 = $\frac{6}{10}$

= $\frac{3}{5}$

(b) 2.5 = $\frac{25}{10}$

= $\frac{5}{2}$

(c) 1.0 = $\frac{10}{10}$

= 1

(d) 3.8 = $\frac{38}{10}$

= $\frac{19}{5}$

(e) 13.7 = $\frac{137}{10}$

(f) 21.2 = $\frac{212}{10}$

= $\frac{106}{5}$

(g) 6.4 = $\frac{64}{10}$

= $\frac{32}{5}$

6. Express the following as cm using decimals:

(a) 30 mm

(b) 2 mm

(c) 116 mm

(d) 4cm 2mm

(e) 162 mm

(f) 83 mm

(a) Since, 10mm = 1cm

Therefore, 1mm = $\frac{1}{10}$ cm

Therefore, 30mm = $\frac{1}{10}$ x 30 = 3.0cm

(b) Since, 10 mm =1cm

Therefore, 1mm = $\frac{1}{10}$ cm

Therefore, 2mm = $\frac{1}{10}$ x 2 = 0.2 cm

(c) Therefore, 116 mm = $\frac{1}{10}$ x 116 = 11.6 cm

(d) Since, 10mm = 1cm

$4cm+\frac{2}{10}cm$

4 + 0.2 = 4.2 cm

(e) 1mm = $\frac{1}{10}$ cm

162 mm = $\frac{1}{10}\times 162 =16.2cm$

(f) Since, 10 mm = 1cm

Therefore, 1mm = $\frac{1}{10}$ cm

Therefore, 83 mm = $\frac{1}{10}\times 83 =8.3cm$

7. Between which two whole numbers do the given numbers lie? Then find the closest whole number to the given numbers.

(a) 5.1

(b) 0.8

(c) 6.4

(d) 2.6

(e) 4.9

(f) 9.1

(a) From 5 to 6, 5.1 is nearest to 5.

(b) From 0 to 1, 0.8 is nearest to 1.

(c) From 6 to 7, 6.4 is nearest to 6.

(d) From 2 to 3, 2.6 is nearest to 3.

(e) From 4 to 5, 4.9 is nearest to 5.

(f) From 9 to 10, 9.1 is nearest to 9

8. Show the given numbers on number line:

(a) 0.2

(b)1.9

(c) 1.1

(d) 2.5

9. From the given number line, write down decimal number represented by the points P, Q, R and S.

P = 0 + $\frac{8}{10}$

= 0.8

Q = 1 + $\frac{3}{10}$

= 1 + 0.3

= 1.3

R = 2 + $\frac{2}{10}$

= 2 + 0.2

= 2.2

S = 2 + $\frac{9}{10}$

= 2 + 0.9

= 2.9

10. (a) The length of Mahesh’s textbook is 10 cm and 6 mm. What will be the length of textbook in cm?

(b) The length of a rose plant is 75 mm. Write the length in cm form.

(a) 10 cm 6 mm = 9 cm + 6 mm

= 9 + $\frac{6}{10}$

= 9.6 cm

(b) 75 mm = $\frac{75}{10}$ cm

= 7.5 cm

#### Exercise 8.2

1. Write numbers according to the information given in the form of table.

 Ones Tenths Hundredths Number ( a ) – – – – ( b ) – – – – ( c ) – – – –

 Ones Tenths Hundredths Number ( a ) 0 5 6 0.56 ( b ) 1 0 8 1.08 ( c ) 1 2 7 1.27

2. Write the numbers from the table given below showing place value of numbers.

 Hundreds (100) Tens (10) Ones (1) Tenths ($\frac{1}{10}$) Hundredths ($\frac{1}{100}$) Thousandths ($\frac{1}{1000}$) (a) 0 0 2 5 7 0 (b) 1 0 6 4 9 1 (c) 0 1 8 9 2 0 (d) 2 1 3 5 0 3 (e) 0 2 3 0 1 5

(a) $2 + \frac{5}{10} + \frac{7}{100} = 2 + 0.5 + 0.07 = 2.57$

(b) $100 + 6 + \frac{4}{10} + \frac{9}{100} + \frac{1}{1000} = 100 + 6 + 0.4 + 0.09 + 0.001 = 106.491$

(c) $10 + 8 + \frac{9}{10} + \frac{2}{100} = 10 + 8 + 0.9 + 0.02 = 18.92$

(d) $200 + 10 + 3 + \frac{5}{10} + \frac{3}{1000} = 200 + 10 + 3 + 0.5 + 0.003 = 213.503$

(e) $20 + 3 + \frac{1}{100} + \frac{5}{1000} = 20 + 3 + 0.01 + 0.005 = 23.015$

3. Write the decimal values given below in place value table.

(a) 0.46

(b) 1.73

(c) 3.08

(d) 12.69

(e) 452.103

(a) $0.46 = 0.4 + 0.06 = \frac{4}{10} + \frac{6}{100}$

(b) $1.73 = 1 + 0.7 + 0.03 = 1 + \frac{7}{10} + \frac{3}{100}$

(c) $3.08 = 3 + 0.08 = 3 + \frac{8}{100}$

(d) $12.69 = 10 + 2 + 0.6 + 0.09 = 12 + \frac{6}{10} + \frac{9}{100}$

(e) $452.103 = 400 + 50 + 2 + 0.1 + 0.003 = 452 + \frac{1}{10} + \frac{3}{1000}$

 Hundreds (100) Tens (10) Ones (1) Tenths ($\frac{1}{10}$) Hundredths ($\frac{1}{100}$) Thousandths ($\frac{1}{1000}$) (a) 0 0 0 4 6 0 (b) 0 0 1 7 3 0 (c) 0 0 3 0 8 0 (d) 0 1 2 6 9 0 (e) 4 5 2 1 0 3

4. Write the following in the form of decimals.

(a) $30 + 8 + \frac{5}{10} + \frac{2}{100}$

(b) $200 + 50 + 3 + \frac{4}{100}$

(c) $\frac{8}{10} + \frac{2}{100} + \frac{7}{1000}$

(d) $25 + \frac{6}{10} + \frac{9}{1000}$

(e) $600 + 37 + \frac{7}{100}$

(f) $1 + \frac{2}{1000}$

(a) $30 + 8 + \frac{5}{10} + \frac{2}{100}$ = 30 + 8 + 0.5 + 0.02 = 38.52

(b) $200 + 50 + 3 + \frac{4}{100}$ = 200 + 50 + 3 + 0.04 = 253.04

(c) $\frac{8}{10} + \frac{2}{100} + \frac{7}{1000}$ = 0.8 + 0.02 + 0.007 = 0.827

(d) $25 + \frac{6}{10} + \frac{9}{1000}$ = 25 + 0.6 + 0.009 = 25.609

(e) $600 + 37 + \frac{7}{100}$ = 600 + 37 + 0.07 = 637.07

(f) $1 + \frac{2}{1000}$ = 1 + 0.002 = 1.002

5. Write in words the given below decimals.

(a) 0.05

(b) 1.35

(c) 106.54

(d) 12.09

(e) 0.058

(f) 2.007

(g) 102.107

(a) 0.05 = zero point zero five

(b) 1.35= one point three five

(c) 106.54 = one zero six point five four

(d) 12.09 = one two point three zero nine

(e) 0.058 = zero point zero five eight

(f) 2.007 = two point zero zero seven

(g) 102.107 = one zero two point one zero seven

6. Decimals are given below. Between which numbers in 10th places will the number will lie on number line?

(a) 0.08

(b) 0.23

(c) 0.97

(d) 0.15

(e) 0.46

(f) 0.68

(g) 0.89

(a) 0.08 – 0 and 0.1

(b) 0.23 – 0.2 and 0.3

(c) 0.97 – 0.9 and 1.0

(d) 0.15 – 0.1 and 0.2

(e) 0.46 – 0.4 and 0.5

(f) 0.68 – 0.6 and 0.7

(g) 0.89 – 0.8 and 0.9

7. Write the following decimals in the form of fractions in the lowest terms.

(a) 0.04

(b) 0.65

(c) 0.50

(d) 0.24

(e) 0.15

(f) 0.115

(g) 0.095

(a) 0.04 = $\frac{40}{100} = \frac{4}{10} = \frac{2}{5}$

(b) 0.65 = $\frac{65}{100} = \frac{13}{20}$

(c) 0.50 = $\frac{50}{100} = \frac{5}{10} = \frac{1}{2}$

(d) 0.24 = $\frac{24}{100} = \frac{6}{25}$

(e) 0.15 = $\frac{15}{100} = \frac{3}{20}$

(f) 0.115 = $\frac{115}{1000} = \frac{23}{200}$

(g) 0.095 = $\frac{95}{1000} = \frac{19}{200}$

#### Exercise 8.3

Q1.Which number is greater?

1. 0.3 or 0.5
2. 0.08 or 0.03
3. 5 or 0.9
4. 0.3 or 0.03
5. 2.6 or 2.61
6. 0.09 or 0.019
7. 1.7 or 1.70
8. 5.36 or 5.26
9. 2.6 or 2.6000
10. 4.89 or 4.9

1.  0.3 or 0.5

In these numbers, whole part is same but the tenth part of 0.3 is smaller than 0.5.

Therefore, 0.5 > 0.3

2. 0.08 or 0.03

In these numbers the hundredth place of 0.08 is greater than 0.03.

Therefore, 0.08 > 0.03

3. 5 or 0.9

In these numbers, whole part 5 is greater than 0 in 0.9.

Therefore, 5 > 0.9

4. 0.3 or 0.03

In these numbers the tenth place of 0.3 is greater than 0.03.

Therefore, 0.3 > 0.03

5. 2.6 or 2.61

In these numbers the hundredth place of 2.6 is smaller than 2.61.

Therefore, 2.61 > 2.6

6. 0.09 or 0.019

In these numbers, hundredth place of 0.019 is smaller than 0.09.

Therefore, 0.09 > 0.019

7. 1.7 or 1.70

In these numbers, whole part is same. Even tenth place is equal. But in first number there is no hundredth place that means that there is zero. So both the numbers are equal.

Therefore, 1.7 = 1.70

8. 5.26 or 5.36

In these numbers, whole part 5 is same. Now tenth place of 5.26 is smaller than that of 5.36.

Therefore, 5.36 > 5.26

9. 2.6 or 2.6000

In these numbers, whole part 2 is equal. Tenth place is also same. But there are three zeros in case of second number. In first number it is till tenth place but it implies that there are zeros present. So they are equal.

Therefore, 2.6 = 2.6000

10. 4.89 or 4.9

In these numbers, the whole part is same but tenth place of 4.89 is smaller than that of 4.9.

Therefore, 4.9 > 4.89

#### Exercise 8.4

Q1. Express in the form of rupees using decimal places.

1. 6 paise
2. 85 paise
3. 30 paise
4. 60 rupees 40 paise
5. 625 paise
6. 450 paise

We know that, 100 paise is equal to 1 rupee.

1. 6 paise = $\frac{6}{100}$ rupees = Re 0.06
2. 85 paise = $\frac{85}{100}$ rupees = Re 0.85
3. 30 paise = $\frac{30}{100}$ rupees = Re 0.30
4. 60 rupees 40 paise = $60 + \frac{40}{100}$ = Re 60.40
5. 625 paise = ($\frac{625}{100}$) rupees = Re 6.25
6. 450 paise = $\frac{450}{100}$ rupees = Re 4.50

Q2. Express the following in the form of metres using decimal places.

1. 16 cm
2. 5 cm
3. 3 m 25 cm
4. 5 m 8 cm
5. 625 cm
6. 213 cm

We know that, 100 cm is equal to 1 m.

1. 16 cm = $\frac{16}{100}$ m = 0.16 m
2. 5 cm = $\frac{5}{100}$ m = 0.05 m
3. 3 m 25 cm = ($3 + \frac{25}{100}$) m = 3.25 m
4. 5 m 8 cm = ($5 + \frac{8}{100}$) m = 5.08 m
5. 625 cm = $\frac{625}{100}$ m = 6.25 m
6. 213 cm = $\frac{213}{100}$ m = 2.13 m

Q3. Express the following in the form of centimetres using decimal places.

1. 6 mm
2. 50 mm
3. 155 mm
4. 10 cm 8 mm
5. 98 mm
6. 289 mm

We know that, 10 mm is equal to 1 cm.

1. 6 mm = $\frac{6}{10}$ cm = 0.6 cm
2. 50 mm = $\frac{50}{10}$ cm = 5.0 cm
3. 155 mm = $\frac{155}{10}$ cm = 15.5 cm
4. 10 cm 8 mm = $10 + \frac{8}{10}$ cm = 10.8 cm
5. 98 mm = $\frac{98}{10}$ cm = 9.8 cm
6. 289 mm = $\frac{289}{10}$ cm = 28.9 cm

Q4. Express the following in the form of kilometres using decimal places.

1. 9 m
2. 78 m
3. 825 m
4. 9456 m
5. 25 km 726 m

We know that, 1000 m is equal to 1 km.

1. 9 m = $\frac{9}{1000}$ km = 0.009 km
2. 78 m = $\frac{78}{1000}$ km = 0.078 km
3. 825 m = $\frac{825}{1000}$ km = 0.825 km
4. 9456 m = $\frac{9456}{1000}$ km = 9.456 km
5. 25 km 726 m = (25 + $\frac{726}{1000}$) km = (25 + 0.726) km = 25.726 km

Q5. Express the following in the form of kilograms using decimal places.

1. 5 g
2. 56 g
3. 654 g
4. 5452 g
5. 15 kg 348 g
6. 54681 g

We know that, 1000 g is equal to 1 kg.

1. 5 g = $\frac{5}{1000}$ kg = 0.005 kg
2. 56 g = $\frac{56}{1000}$ kg = 0.056 kg
3. 654 g = $\frac{654}{1000}$ kg = 0.654 kg
4. 5452 g = $\frac{5452}{1000}$ kg = 5.452 kg
5. 15 kg 348 g = (15 + $\frac{348}{1000}$) kg = (15 + 0.348) kg = 15.348 kg
6. 54681 g = $\frac{54681}{1000}$ kg = 54.681 kg

A decimal refers to the representation of numbers in a system that comprises of a decimal separator (Like 1.00, 4.119, 0.455, etc). These are the decimal fractions i.e. the fractions of the type p/10q, where ‘p’ is an integer, and q = non-negative integer. Decimal Numbers can be represented on a Number Line. To represent 10s, the gap between the whole numbers on the number line is separated into 10 identical elements where every element represents a 10th.

The Central Board of Secondary Education follows the NCERT curriculum (2018-2019) for all the classes from 1st to 12th and is responsible to conduct board examination for class 10th and class 12th. Class 6 is also one of the crucial stages of a student’s life where he/she learns the basic concepts given in all subjects and grow their thinking power. Students can relate those concepts with their daily life to get an idea of logic applied. All these concepts are useful for higher classes as well.

Learn from NCERT solutions for class 6 Maths subjects for all chapter, here. Get interesting online learning materials from BYJU’S and download its app to get interactive videos and contents to learn Maths concepts and principles in a more effective way.

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