NCERT Solutions For Class 6 Maths Chapter 1 are provided here for students of class 6 who are looking to secure a good score in mathematics. These solutions are prepared in order to encourage students to understand the concepts of numbers and how to perform different operations on them. These materials are prepared with respect to class 6th CBSE syllabus (2018-2019) by our experts and keeping into consideration, the types of questions asked in the NCERT textbook.

The NCERT Solutions for Class 6 Maths, Knowing Our Numbers, showcases topics such as;

- Comparing numbers Making different types of numbers
- Identifying smaller and greater numbers
- Arranging the orders of numbers
- Introduction to 10,000 and 1,00,000
- Revisiting the place value
- Introduction to international and Indian system of numeration
- Estimation of numbers and operations on numbers up to 5 digits
- Bracket expansion
- Roman Numerals

These are the important topics based on which solutions are prepared for Class 6th Maths Chapter 1. Apart from these students can also go through the other learning materials such as notes, books, worksheets, etc. available on our website. These materials are in PDF format and you can download them and practice offline as well. Click here to get the NCERT solutions for all the chapters of Maths.

### NCERT Solutions Class 6 Maths Chapter 1 Exercises

- NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.1
- NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.2
- NCERT Solutions Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.3

### NCERT Questions For Knowing The Numbers

**Exercise 1.1**

*Question 1:*

*Answer the following questions*

*a) How many ten thousand make up 1 lakh?*

**Answer:**

Ten

*b) How many hundred thousand make up one million?*

**Answer:**

Ten

*c) How many ten lakh make up one crore?*

**Answer:**

Ten

*d) One crore is equivalent to how many millions?*

**Answer:**

Ten

*Question 2: *

*With proper use of periods, express the following in numeric format. *

a) Seventy two lakh fifty six thousand four hundred six

b) Eight crore six lakh fifty one

c) Six crore sixty two lakh thirty one thousand two hundred three.

d) Seventy six million five hundred ninety thousand four hundred and three

e) Twenty two lakh forty thousand nine

**Answer:**

a) 72, 56, 406

b) 80, 06, 00,051

c) 6, 62, 31, 203

d) 76, 590, 403

e) 22, 40, 009

*Question 3: *

*With proper use of period, give the names as per Indian numerical system for below numbers.*

*a) 98606873 b) 9657394*

*c) 99900046 d) 98543812*

**Answer:**

a) 9, 86, 06, 873

Nine crore eighty six lakh six thousand eight hundred seventy three

b) 96, 57,394

Nine six lakh fifty seven thousand three hundred ninety four

c) 9, 99, 00, 046

Nine crore ninety nine lakh forty six

d) 9, 85, 43, 812

Nine crore eighty-five lakh forty three thousand eight hundred twelve.

__Exercise – 1.2__

__Exercise – 1.2__

**Question 1: **

*A dress exhibition was held for 4 days in a mall. The number of shopkeeper sold dress at the counter on the 1 ^{st} , 2^{nd} , 3^{rd} and final day was 1094, 1812, 2050 and 2051.*

*Find the total number shopkeepers sold dress on all the four days.***Answer: **

Number of dress sold on 1^{st} day= 1,094

Number of dress sold by shopkeepers on 2^{nd} day= 1,812

Number of dress sold by shopkeepers on 3^{rd} day= 2,050

Number of dress sold by shopkeepers on 4^{th} day = + 2051

Total dress sold by shopkeepers 1,094+1,812+2,050+ 2,051 = 7,007

Therefore, shopkeepers sold 7,007 dress on all the 4 days.

*Question 2: *

*Vivek Dhankrish is a famous baseball player. He scored so far 6980 runs in league matches. He wants to complete 10,000 runs. How many runs should he take to reach 10,000?*

**Answer: **

Runs to take = 10,000

Runs to be scored = –6,980

Runs required = 3,020

Therefore, he needs 3,020 more runs.

*Question 3: *

*In an college election, the successful student registered 5,77,500 votes and his rival student got 3,48,700 votes. Give the margin of the successful student win the election.*

**Answer: **

Number of votes secured by successful student= 5,77,500

votes secured by his opponent student =–3,48,700

Margin between them

= 2,28,800

Therefore, the successful candidate won by of 2,28,800 votes.

*Question 4: *

*Dress store sold dress worth Rs.2,85,891 in the first week of June and dress worth Rs.4,00,768 in the 2 ^{nd} week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?*

**Answer: **

Dress sold in 1^{st} week

= 2,85,891

Dress sold in 2^{nd} week

= + 4,00,768

Total dress sold= 6,86,659

Since, 4,00,768,> 2,85,891

Therefore sale of 2^{nd} week is greater than that of 1^{st} week.

Dress sold in 2^{nd} week

=4,00,768

Dress sold in first week= – 2,85,891

More dress sold in second week= 1,14,877

Therefore, 1,14,877 more dress were sold in 2^{nd} week.

*Question 5:*

*Find the difference between the largest and the smallest number that can be written using the digits 6, 2, 7, 4, 3 each only once.*

**Answer: **

Largest five digit number using digits 6,2,7,4,3

= 76432

Smallest five-digit number using digits 6,2,7,4,3

= –23467

Difference= 52965

Therefore, the difference is 52965.

*Question 6: *

*A factory machine, on an average, manufactures 2,825 bolts a day. How many bolts did it produce in the month of March 2006?*

**Answer: **

Number of bolts manufactured in one day

= 2,825

Number of days in

the month of march(31 days)

= 2,825 x 31

= 87,575

Therefore the factory machine produced 87,575 bolts in the month of march 2006.

*Question 7: *

*A shopkeeper had Rs.78,592 with her. He placed an order for purchasing 40 TV sets at Rs. 1,200 each. How much money will he have after the product is purchased?*

**Answer: **

The cost of one TV= Rs. 200

Total cost of 40 TVs = 1200 x 40=Rs. 48,000

Now,

Total money with shopkeeper =Rs.78,592

The sum of Money spent by him= –Rs. 48,000

Money left remaining with him= Rs. 30,592

Therefore, Rs.30,592 will remain with him after the product is been purchased.

*Question 8:*

*A boy multiplied 7236 by 65 instead by multiplying it with 56. By how much was his answer larger than the exact answer?*

**Answer:**

Wrongly multiplied answer = 7236 x 65 = 470340

Exact answer = 7236 x 56 = 405216

Difference given by the answers

= 470340 – 405216

= 65,124

*Question 9:*

*To knit a pant 2 m 15 cm cotton cloth is needed. Out of 40 m cotton cloth, how many pants can be knitted?*

**Answer: **

Cotton Cloth required to knit one pant = 2 m 15 cm

= 2 x 100 cm + 15 cm

= 215 cm

Length of cotton cloth = 40 m = 40 x 100 cm = 4000 cm

Number of pants can be Knitted = 4000 ¸215= 18

Therefore, 18 shirts can be knitted.

*Question 10: *

*Dresses is packed in cardboards, each weighing 4 kg 500 g. How many such cardboards can be loaded in a van, which is not able to carry beyond 800 kg?*

**Answer: **

The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g

Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g

Number of boxes = 800000¸4500 =177

Therefore, 177 boxes can be loaded.

*Question 11: *

*The distance between the office and the house of an employee’s house is 1 km 875 m. Every day he walks two ways. Find the total distance by him in 6 days.*

**Answer: **

Distance between Office and home

= 1.875 km

Distance between home and office

= + 1.875 km

Total distance covered in 1 day

= 3.750 km

Distance covered in 6 days

= 3.750 x 6 = 22.500 km

Therefore, 22 km 500 m distance covered in six days.

*Question 12: *

*A bottle has four liters and 500 ml of buttermilk. In how many bottles each of 25 ml capacity, can it be filled?*

**Answer: **

Capacity of buttermilk in a vessel = 4litres

500 ml =4 x 1000 ml + 500 ml = 4500 ml

Capacity of one glass = 25 ml

Number of glasses can be filled = 4500¸25=180

Therefore, 180 bottles can be filled by buttermilk.

__Exercise – 1.3__

__Exercise – 1.3__

**QUESTIONS 1:**

*Determine the following by using general rule:*

*(i) 768 + 830*

*(ii) 596 – 340*

*(iii) 5432 + 3129*

*(iv) 24850 – 22720*

*Answer:*

(i) 768 rounding off to 800

830 rounding off to __800 __

Estimated sum = __1600__

(ii) 596 rounding off to 600

340 rounding off to __300__

Estimated difference = __300__

(iii) 5432 rounding off to 5000

3129 rounding off to __3000__

Estimated sum = __8000__

(iv) 24850 rounding off to 25000

22720 rounding off to __23000__

Estimated difference= __2000__

*Question 2:*

*Estimate the following (by rounding off the values to nearest hundreds) and a closer estimate (by rounding off to nearest tens):*

*(i) 440 + 324 + 4650*

*(ii) 1,08,747 – 47,593*

*(iii) 8235 – 392*

*(iv) 4,89,338 – 48,375*

*Answer:*

** (i) **440 rounding off to 400

324 rounding off to 300

4650 rounding off to __4700__

Estimated sum = __5400__

** (ii) **108747 rounding off to 108700

47593 rounding off to __47600__

Estimated difference = __61100__

** (iii) **8235 rounding off to 8200

392 rounding off to __400__

Estimated difference = __7800__

** (iv) **489338 rounding off to 489300

48375 rounding off to __48400__

Estimated difference = __440900__

*Question 3:*

*Determine the following by using general rule:*

*(i) 568 x 180*

*(ii) 4280 x 2490*

*(iii) 1190 x 589*

*(iv) 5270 x 29*

*Answer:*

**(i) **568 x 180

568 rounding off to 600

180 rounding off to 200

The estimated product = 600 x 200 = 1,20,000

**(ii) **4280 x 2490

4280 rounding off to 4300

2490 rounding off to 2500

The estimated product = 4300 x 2500 = 1,07,50,000

**(iii) **1190 x 589

1190 rounding off to 1200

589 rounding off to 600

The estimated product = 1200 x 600 = 7,20,000

**(iv) **5270 x 29

5270 rounding off to 5500

29 rounding off to 30

The estimated product = 5500 x 30 = 1,65,000

Students can prepare for their main exams conducting in 2019, with the help of NCERT solutions, provided by BYJU’S, as it will help to make you understood the concepts and basics of maths and score well. These solutions carry solved questions, which gives the best method to solve the problems.

Knowing the numbers is one of the important topics in mathematics for the students of class 6, which forms the foundation for various topics in mathematics. As we know, almost all the topics covered in Maths are related to numbers. Therefore, it is necessary to understand the basic concepts of numbers. The various mathematical operations include Addition, Subtraction, Multiplication, Division of numbers on which a student must have exceptionally good knowledge. Therefore, it is crucial for students to have a good knowledge of the topic. And also, this will result in forming a stronger base for higher level classes maths concepts.

Keep visiting BYJU’S, for more updated materials and also get NCERT Solutions for class 6 Science subject here. Also, download BYJU’S-The Learning App and get learning videos and exceptionally interesting contents to make your study more joyful.