# NCERT Solutions for Class 7 Maths Exercise 2.4 Chapter 2 Fractions and Decimals

NCERT Solutions for Class 7 Maths Exercise 2.4 Chapter 2 Fractions and Decimals are the best study materials for those students who find difficulty in solving problems. This exercise of NCERT Solutions for Class 7 Maths Chapter 2 contains the topics division of fractions, division of whole numbers by a fraction, division of a fraction by a whole number and division of a fraction by another fraction. Students who wish to score good marks in Maths should practise NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals.

## NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals â€“ Exercise 2.4

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### Access Answers to Maths NCERT Solutions for Class 7 Chapter 2 â€“ Fractions and Decimals Exercise 2.4

1. Find.

(i) 12 Ã· Â¾

Solution:-

We have

= 12 Ã— reciprocal of Â¾

= 12 Ã— (4/3)

= 4 Ã— 4

= 16

(ii) 14 Ã· (5/6)

Solution:-

We have

= 14 Ã— reciprocal of (5/6)

= 14 Ã— (6/5)

= 84/5

(iii) 8 Ã· (7/3)

Solution:-

We have

= 8 Ã— reciprocal of (7/3)

= 8 Ã— (3/7)

(iv) 4 Ã· (8/3)

Solution:-

We have

= 4 Ã— reciprocal of (8/3)

= 4 Ã— (3/8)

= 1 Ã— (3/2)

= 3/2

(v) 3 Ã·

Solution:-

While dividing a whole number by a mixed fraction, first convert the mixed fraction into an improper fraction.

We have

== 7/3

Then,

= 3 Ã· (7/3)

= 3 Ã— reciprocal of (7/3)

= 3 Ã— (3/7)

= 9/7

(vi) 5 Ã·

Solution:-

While dividing a whole number by a mixed fraction, first convert the mixed fraction into an improper fraction.

We have

== 25/7

Then,

= 5 Ã· (25/7)

= 5 Ã— reciprocal of (25/7)

= 5 Ã— (7/25)

= 1 Ã— (7/5)

= 7/5

2. Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.

(i) 3/7

Solution:-

Reciprocal of (3/7) is (7/3) [âˆµ ((3/7) Ã— (7/3)) = 1]

So, it is an improper fraction.

An improper fraction is a fraction in which the numerator is greater than its denominator.

(ii) 5/8

Solution:-

Reciprocal of (5/8) is (8/5) [âˆµ ((5/8) Ã— (8/5)) = 1]

So, it is an improper fraction.

An improper fraction is a fraction in which the numerator is greater than its denominator.

(iii) 9/7

Solution:-

Reciprocal of (9/7) is (7/9) [âˆµ ((9/7) Ã— (7/9)) = 1]

So, it is a proper fraction.

A proper fraction is a fraction in which the denominator is greater than the numerator of the fraction.

(iv) 6/5

Solution:-

Reciprocal of (6/5) is (5/6) [âˆµ ((6/5) Ã— (5/6)) = 1]

So, it is a proper fraction.

A proper fraction is a fraction in which the denominator is greater than the numerator of the fraction.

(v) 12/7

Solution:-

Reciprocal of (12/7) is (7/12) [âˆµ ((12/7) Ã— (7/12)) = 1]

So, it is a proper fraction.

A proper fraction is a fraction in which the denominator is greater than the numerator of the fraction.

(vi) 1/8

Solution:-

Reciprocal of (1/8) is (8/1) or 8 [âˆµ ((1/8) Ã— (8/1)) = 1]

So, it is a whole number.

Whole numbers are collections of all positive integers, including 0.

(vii) 1/11

Solution:-

Reciprocal of (1/11) is (11/1) or 11 [âˆµ ((1/11) Ã— (11/1)) = 1]

So, it is a whole number.

Whole numbers are collections of all positive integers, including 0.

3. Find:

(i) (7/3) Ã· 2

Solution:-

We have

= (7/3) Ã— reciprocal of 2

= (7/3) Ã— (1/2)

= (7 Ã— 1) / (3 Ã— 2)

= 7/6

=

(ii) (4/9) Ã· 5

Solution:-

We have

= (4/9) Ã— reciprocal of 5

= (4/9) Ã— (1/5)

= (4 Ã— 1) / (9 Ã— 5)

= 4/45

(iii) (6/13) Ã· 7

Solution:-

We have

= (6/13) Ã— reciprocal of 7

= (6/13) Ã— (1/7)

= (6 Ã— 1) / (13 Ã— 7)

= 6/91

(iv) Ã· 3

Solution:-

First, convert the mixed fraction into an improper fraction.

We have,

== 13/3

Then,

= (13/3) Ã— reciprocal of 3

= (13/3) Ã— (1/3)

= (13 Ã— 1) / (3 Ã— 3)

= 13/9

(iv) 3 Â½ Ã· 4

Solution:-

First, convert the mixed fraction into an improper fraction.

We have

= 3 Â½ = 7/2

Then,

= (7/2) Ã— reciprocal of 4

= (7/2) Ã— (1/4)

= (7 Ã— 1) / (2 Ã— 4)

= 7/8

(iv) Ã· 7

Solution:-

First, convert the mixed fraction into an improper fraction.

We have

== 31/7

Then,

= (31/7) Ã— reciprocal of 7

= (31/7) Ã— (1/7)

= (31 Ã— 1) / (7 Ã— 7)

= 31/49

4. Find.

(i) (2/5) Ã· (Â½)

Solution:-

We have

= (2/5) Ã— reciprocal of Â½

= (2/5) Ã— (2/1)

= (2 Ã— 2) / (5 Ã— 1)

= 4/5

(ii) (4/9) Ã· (2/3)

Solution:-

We have

= (4/9) Ã— reciprocal of (2/3)

= (4/9) Ã— (3/2)

= (4 Ã— 3) / (9 Ã— 2)

= (2 Ã— 1) / (3 Ã— 1)

= 2/3

(iii) (3/7) Ã· (8/7)

Solution:-

We have

= (3/7) Ã— reciprocal of (8/7)

= (3/7) Ã— (7/8)

= (3 Ã— 7) / (7 Ã— 8)

= (3 Ã— 1) / (1 Ã— 8)

= 3/8

(iv) Ã· (3/5)

Solution:-

First, convert the mixed fraction into an improper fraction.

We have,

== 7/3

Then,

= (7/3) Ã— reciprocal of (3/5)

= (7/3) Ã— (5/3)

= (7 Ã— 5) / (3 Ã— 3)

= 35/9

(v) 3 Â½ Ã· (8/3)

Solution:-

First, convert the mixed fraction into an improper fraction.

We have

= 3 Â½ = 7/2

Then,

= (7/2) Ã— reciprocal of (8/3)

= (7/2) Ã— (3/8)

= (7 Ã— 3) / (2 Ã— 8)

= 21/16

(vi) (2/5) Ã· 1 Â½

Solution:-

First, convert the mixed fraction into an improper fraction.

We have

= 1 Â½ = 3/2

Then,

= (2/5) Ã— reciprocal of (3/2)

= (2/5) Ã— (2/3)

= (2 Ã— 2) / (5 Ã— 3)

= 4/15

(vii) Ã·

Solution:-

First, convert the mixed fraction into an improper fraction.

We have

== 16/5

== 5/3

Then,

= (16/5) Ã— reciprocal of (5/3)

= (16/5) Ã— (3/5)

= (16 Ã— 3) / (5 Ã— 5)

= 48/25

(viii) Ã·

Solution:-

First, convert the mixed fraction into an improper fraction.

We have

== 11/5

== 6/5

Then,

= (11/5) Ã— reciprocal of (6/5)

= (11/5) Ã— (5/6)

= (11 Ã— 5) / (5 Ã— 6)

= (11 Ã— 1) / (1 Ã— 6)

= 11/6

### Access other exercises of NCERT Solutions for Class 7 Chapter 2 â€“ Fractions and Decimals

Exercise 2.1 Solutions

Exercise 2.2 Solutions

Exercise 2.3 Solutions

Exercise 2.5 Solutions

Exercise 2.6 Solutions

Exercise 2.7 Solutions

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