*According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 12.
NCERT Solutions Class 9 Maths Chapter 14 – Statistics Exercise 14.2 are the best guide for the students preparing for the CBSE examinations. They contain all the relevant study materials that can help them score well in the board examinations. NCERT Solutions Class 9 Chapter 14 – Statistics are important for the examination as well as for higher classes. If the students are thorough with the basic concepts of this chapter, they will find it easy to grasp the advanced concepts in the higher classes.
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Exercise 14.1 Solutions 2 Questions
Exercise 14.3 Solutions 9 Questions
Exercise 14.4 Solutions 6 Questions
Access Answers to NCERT Class 9 Maths Chapter 14 – Statistics Exercise 14.2
1. The blood groups of 30 students of Class VIII are recorded as follows:
A, B, O, O, AB, O, A, O, B, A, O, B, A, O, O,
A, AB, O, A, A, O, O, AB, B, A, O, B, A, B, O.
Represent this data in the form of a frequency distribution table. Which is the most common, and which is the rarest, blood group among these students?
Solution:
Frequency is the number of students having the same blood group. The frequency is represented in the table or the frequency distribution table.
Blood Group | Number of Students
(Frequency) |
A | 9 |
B | 6 |
O | 12 |
AB | 3 |
Total | 30 |
The most common Blood Group is the blood group with the highest frequency: O
The rarest Blood Group is the blood group with the lowest frequency: AB
2. The distance (in km) of 40 engineers from their residence to their place of work was found as follows:
5 Â Â 3 Â Â 10 Â Â 20 Â Â 25 Â Â 11 Â Â 13 Â Â 7 Â Â 12 Â Â 31
19 Â Â 10 Â Â 12 Â Â 17 Â Â 18 Â Â 11 Â Â 32 Â Â 17 Â Â 16 Â Â 2
7 Â Â 9 Â Â 7 Â Â 8 Â Â 3 Â Â 5 Â Â 12 Â Â 15 Â Â 18 Â Â 3
12 Â Â 14 Â Â 2 Â Â 9 Â Â 6 Â Â 15 Â Â 15 Â Â 7 Â Â 6 Â Â 12
Construct a grouped frequency distribution table with class size 5 for the data given above, taking the first interval as 0-5 (5 not included). What main features do you observe from this tabular representation?
Solution:
Since the given data is very large, we construct a grouped frequency distribution table of class size 5. ∴, class intervals will be 0-5, 5-10, 10-15, 15-20 and so on. The data is represented in the grouped frequency distribution table as
In the given table, the classes do not overlap. Also, we find that the houses of 36 out of 40 engineers are below 20 km of distance.
3. The relative humidity (in %) of a certain city for a month of 30 days was as follows:
98.1 Â Â 98.6 Â Â 99.2 Â Â 90.3 Â Â 86.5 Â Â 95.3 Â Â 92.9 Â Â Â 96.3 Â Â Â 94.2 Â Â Â 95.1
89.2 Â Â 92.3 Â Â 97.1 Â Â 93.5 Â Â 92.7 Â Â 95.1 Â Â 97.2 Â Â Â 93.3 Â Â Â 95.2 Â Â Â 97.3
96.2 Â Â 92.1 Â Â 84.9 Â Â 90.2 Â Â 95.7 Â Â 98.3 Â Â 97.3 Â Â Â 96.1 Â Â Â 92.1 Â Â Â 89
(i) Construct a grouped frequency distribution table with classes 84 – 86, 86 – 88, etc.
(ii) Which month or season do you think this data is about?
(iii) What is the range of this data?
Solution:
(i) Since the given data is very large, we construct a grouped frequency distribution table of class size 2.
∴, class intervals will be 84-86, 86-88, 88-90, 90-92 and so on. The data is represented in the grouped frequency distribution table as
Relative humidity (in %) | Frequency |
84-86 | 1 |
86-88 | 1 |
88-90 | 2 |
90-92 | 2 |
92-94 | 7 |
94-96 | 6 |
96-98 | 7 |
98-100 | 4 |
Total | 30 |
(ii) The humidity is very high in the given data. Since the humidity is observed to be high during the rainy season, the data here must be about the rainy season.
(iii) The range of a data = The maximum value of the data–minimum value of the data
= 99.2−84.9
= 14.3
4. The heights of 50 students, measured to the nearest centimetres, have been found to be as follows:
161 Â Â 150 Â Â 154 Â Â 165 Â Â 168 Â Â 161 Â Â 154 Â Â 162 Â Â 150 Â Â 151
162 Â Â 164 Â Â 171 Â Â 165 Â Â 158 Â Â 154 Â Â 156 Â Â 172 Â Â 160 Â Â 170
153 Â Â 159 Â Â 161 Â Â 170 Â Â 162 Â Â 165 Â Â 166 Â Â 168 Â Â 165 Â Â 164
154 Â Â 152 Â Â 153 Â Â 156 Â Â 158 Â Â 162 Â Â 160 Â Â 161 Â Â 173 Â Â 166
161 Â Â 159 Â Â 162 Â Â 167 Â Â 168 Â Â 159 Â Â 158 Â Â 153 Â Â 154 Â Â 159
(i) Represent the data given above by a grouped frequency distribution table, taking the class intervals as 160 – 165, 165 – 170, etc.
(ii) What can you conclude about their heights from the table?
Solution:
(i) The data given in the question can be represented by a grouped frequency distribution table, taking the class intervals as 160 – 165, 165 – 170, etc., as
Height (in cm) | No. of Students
(Frequency) |
150-155 | 12 |
155-160 | 9 |
160-165 | 14 |
165-170 | 10 |
170-175 | 5 |
Total | 50 |
(ii) It can be concluded from the given data and the table that 35 students, i.e., more than 50% of the total students, are shorter than 165 cm.
5. A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follows:
0.03 Â Â 0.08 Â Â 0.08 Â Â 0.09 Â Â 0.04 Â Â 0.17
0.16 Â Â 0.05 Â Â 0.02 Â Â 0.06 Â Â 0.18 Â Â 0.20
0.11 Â Â 0.08 Â Â 0.12 Â Â 0.13 Â Â 0.22 Â Â 0.07
0.08 Â Â 0.01 Â Â 0.10 Â Â 0.06 Â Â 0.09 Â Â 0.18
0.11 Â Â 0.07 Â Â 0.05 Â Â 0.07 Â Â 0.01 Â Â 0.04
(i) Make a grouped frequency distribution table for this data with class intervals as 0.00 – 0.04, 0.04 – 0.08, and so on.
(ii) For how many days was the concentration of Sulphur dioxide more than 0.11 parts per million?
Solution:
(i) The grouped frequency distribution table for the data given in the question with class intervals as 0.00 – 0.04, 0.04 – 0.08, and so on is given below.
Concentration of sulphur dioxide in the air
(in ppm) |
Frequency |
0.00 − 0.04 | 4 |
0.04 − 0.08 | 9 |
0.08 − 0.12 | 9 |
0.12 − 0.16 | 2 |
0.16 − 0.20 | 4 |
0.20 − 0.24 | 2 |
Total | 30 |
(ii) The number of days in which the concentration of sulphur dioxide was more than 0.11 parts per million = 2+4+ 2 = 8
6. Three coins were tossed 30 times simultaneously. Each time the number of heads occurring was noted down as follows:
0 1 2 2 1 2 3 1 3 0
1 3 1 1 2 2 0 1 2 1
3 0 0 1 1 2 3 2 2 0
Prepare a frequency distribution table for the data given above.
Solution:
The frequency distribution table for the data given in the question is given below.
Number of Heads | Frequency |
0 | 6 |
1 | 10 |
2 | 9 |
3 | 5 |
Total | 30 |
7. The value of π up to 50 decimal places is given below:
3.14159265358979323846264338327950288419716939937510
(i) Make a frequency distribution of the digits from 0 to 9 after the decimal point.
(ii) What are the most and the least frequently occurring digits?
Solution:
(i) The frequency distribution of the digits from 0 to 9 after the decimal point is given in the table below.
Digits | Frequency |
0 | 2 |
1 | 5 |
2 | 5 |
3 | 8 |
4 | 4 |
5 | 5 |
6 | 4 |
7 | 4 |
8 | 5 |
9 | 8 |
Total | 50 |
(ii) The digit having the least frequency occurs the least. Since 0 occurs only twice, it has a frequency of 2. ∴, the least frequently occurring digit is 0.
The digit with the highest frequency occurs the most. Since 3 and 9 occur eight times, it has a frequency of 8. ∴, the most frequently occurring digits are 3 and 9.
8. Thirty children were asked about the number of hours they watched TV programmes in the previous week. The results were found as follows:
1 Â Â 6 Â Â 2 Â Â 3 Â Â 5 Â Â 12 Â Â 5 Â Â 8 Â Â 4 Â Â 8
10 Â 3 Â Â 4 Â Â 12 Â 2 Â Â 8 Â Â 15 Â Â 1 Â Â 17 Â 6
3 Â Â 2 Â Â 8 Â Â 5 Â Â 9 Â Â 6 Â Â Â 8 Â Â 7 Â Â 14 Â 12
(i) Make a grouped frequency distribution table for this data, taking class width 5 and one of the class intervals 5-10.
(ii) How many children watch television for 15 or more hours a week?
Solution:
(i) The grouped frequency distribution table for the data given in the question, taking class width 5 and one of the class intervals 5-10, is given below.
Number of Hours | Frequency |
0-5 | 10 |
5-10 | 13 |
10-15 | 5 |
15-20 | 2 |
Total | 30 |
(ii) From the given table, we can conclude that 2 children watched television for 15 or more hours a week.
9. A company manufactures car batteries of a particular type. The lives (in years) of 40 such batteries were recorded as follows:
2.6 Â Â 3.0 Â Â 3.7 Â Â 3.2 Â Â 2.2 Â Â 4.1 Â Â 3.5 Â Â 4.5
3.5 Â Â 2.3 Â Â 3.2 Â Â 3.4 Â Â 3.8 Â Â 3.2 Â Â 4.6 Â Â 3.7
2.5 Â Â 4.4 Â Â 3.4 Â Â 3.3 Â Â 2.9 Â Â 3.0 Â Â 4.3 Â Â 2.8
3.5 Â Â 3.2 Â Â 3.9 Â Â 3.2 Â Â 3.2 Â Â 3.1 Â Â 3.7 Â Â 3.4
4.6 Â Â 3.8 Â Â 3.2 Â Â 2.6 Â Â 3.5 Â Â 4.2 Â Â 2.9 Â Â 3.6
Construct a grouped frequency distribution table for this data, using class intervals of size 0.5 starting from interval 2 – 2.5.
Solution:
The grouped frequency distribution table for the data given in the table, using class intervals of size 0.5 starting from interval 2 – 2.5, is given below.
Lives of batteries (in years) | No. of batteries
(Frequency) |
2-2.5 | 2 |
2.5-3 | 6 |
3-3.5 | 14 |
3.5-4 | 11 |
4-4.5 | 4 |
4.5-5 | 3 |
Total | 40 |
The exercise contains a total of 9 questions. Frequency distribution tables are required to be provided for the data mentioned in the questions. The solutions are provided in the NCERT Solutions Class 9 Maths Chapter 14 – Statistics Exercise 14.2. The students can refer to the exercise solutions for reference.
Key Features of NCERT Solutions for Class 9 Maths Chapter 14 – Statistics Exercise 14.2
- The solutions are provided by the subject experts.
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- The answers to the questions provided are accurate.
- All the questions mentioned in the textbook can be found, along with the solutions, here.
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