 # NCERT Solutions for class 9 Maths Chapter 14- Statistics Exercise 14.4

NCERT Solutions are very helpful to the students preparing for the examinations. They act as a guide that the students can refer in case of any doubts. NCERT Solutions for Class 9 Maths Chapter 14- Statistics Exercise 14.4 contains the solutions to all the questions provided on page number 269 in the textbook.

NCERT Solutions Chapter 14- Statistics is an important chapter from the examination perspective. There is a chapter Statistics in Class 10 as well. Having conceptual knowledge of this chapter will help the students grasp the concepts easily in the higher classes as well.

NCERT Solutions Maths Class 9 contains the solutions provided by the subject experts. Every step of the solution is explained in detail, such that the students find it easy to understand.

The students can practise the exercises provided in the NCERT Solutions and analyse their shortcomings. These solutions will surely help the students score well in the first and second term examinations.

### Download PDF of NCERT Solutions for Class 9 Maths Chapter 14- Statistics Exercise 14.4    ### Access Other Exercise Solutions of Class 9 Maths Chapter 14- Statistics

Exercise 14.1 Solutions 2 Questions

Exercise 14.2 Solutions 9 Questions

Exercise 14.3 Solutions 9 Questions

### Access Answers to NCERT Class 9 Maths Chapter 14 – Statistics Exercise 14.4

1. The following number of goals were scored by a team in a series of 10 matches:

2, 3, 4, 5, 0, 1, 3, 3, 4, 3

Find the mean, median and mode of these scores.

Solution:

Mean = Average = Sum of all the observations/Total number of observations

= (2+3+4+5+0+1+3+3+4+3)/10

= 28/10

= 2.8

Median,

To find the median, we first arrange the data in ascending order.

0, 1, 2, 3, 3, 3, 3, 4, 4, 5

Here,

Number of observations (n) = 10

Since the number of observations are even, the median can be calculated as: = 3

Mode,

To find the mode, we first arrange the data in ascending order.

0, 1, 2, 3, 3, 3, 3, 4, 4, 5.

Here,

We find that 3 occurs most frequently (4 times)

∴ Mode = 3

2. In a mathematics test given to 15 students, the following marks (out of 100) are recorded:

41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60
Find the mean, median and mode of this data.

Solution:

Mean=Average = Sum of all the observations/Total number of observations

= (41+39+48+52+46+62+54+40+96+52+98+40+42+52+60)/15

= 822/15

= 54.8

Median,

To find the median, we first arrange the data in ascending order.

39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98

Here,

Number of observations (n) = 15

Since the number of observations are odd, the median can be calculated as:

Median = [(n+1)/2]th observation

= [(15+1)/2]th observation

= (16/2)th observation

= 8th observation

= 52

Mode,

To find the mode, we first arrange the data in ascending order.

39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98

Here,

We find that 52 occurs most frequently (3 times)

∴ Mode = 52

3. The following observations have been arranged in ascending order. If the median of the data is 63, find the value of x.

29, 32, 48, 50, x, x+2, 72, 78, 84, 95

Solution:

Number of observations (n) = 10

Given that Median = 63

Since the number of observations are even, the median can be calculated as: 63 = [5th observation+(5+1)th observation]/2

63 = [5th observation+6th observation]/2

63 = (x+x+2)/2

63 = (2x+2)/2

x = 63-1

x = 62

4. Find the mode of 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18.

Solution:

Mode,

To find the mode, we first arrange the given data in ascending order.

14,14,14,14,17,18,18,18,22,23,25,28

Here,

We find that 14 occurs most frequently (4 times)

∴ Mode = 14

5. Find the mean salary of 60 workers of a factory from the following table: Solution:

 Salary (xi) Number of workers (fi) fixi 3000 16 48000 4000 12 48000 5000 10 50000 6000 8 48000 7000 6 42000 8000 4 32000 9000 3 27000 10000 1 10000 Total Σfi = 60 Σfixi = 305000 , the mean salary is ₹5083.33

6. Give one example of a situation in which

(i) the mean is an appropriate measure of central tendency.

(ii) the mean is not an appropriate measure of central tendency but the median is an appropriate measure of central tendency.

Solution:

(i) Mean marks obtained in the examination

(ii) Runs scored by Mahendra Singh Dhoni in 7 matches are,

39, 51, 56, 102, 83, 48, 91

Here,

Mean = (39+51+56+102+83+48+91)/7

= 470/7

= 67.1.

Median,

Arranging in ascending order we get 39, 48 51, 56, 83, 91, 102

n = 7

Median = [(n+1)/2]th observation

= ( (7+1)/2)th observation

= (8/2)th observation

= 4th observation

= 56

The exercise contains a total of 6 questions based on the concepts of mean, median and mode. The answers to these questions are provided in the NCERT Solutions Class 9 Maths Chapter 14- Statistics Exercise 14.4. The students can refer to these solutions in case of any doubts.

### Key Features of NCERT Solutions for Class 9 Maths Chapter 14- Statistics Exercise 14.4

• The solutions are provided by the subject experts.
• NCERT Solutions for Class 9 Maths Chapter 14- Statistics Exercise 14.4 will help the students score well in the first term examinations.
• The answers to the questions provided are accurate.
• All the questions mentioned in the textbook can be found along with the solutions here.