In this exercise, we shall discuss the RHS triangle construction and the steps involved in them. The primary objective is to help students improve their problem-solving abilities, which in turn, helps in boosting their confidence level to achieve high marks in their exams. Students can refer to and download RD Sharma Solutions for Class 7 Maths Exercise 17.5 Chapter 17 Constructions. These solutions are formulated by BYJU’S subject experts in Maths.
RD Sharma Solutions for Class 7 Maths Chapter 17 – Constructions Exercise 17.5
Access answers to Maths RD Sharma Solutions for Class 7 Chapter 17 – Constructions Exercise 17.5
Exercise 17.5 Page No: 16.3
1. Draw a right triangle with a hypotenuse of length 5 cm and one side of length 4 cm.
Solution:
Steps of construction:
1. Draw a line segment QR = 4 cm.
2. Draw ∠QRX of measure 90o.
3. With centre Q and radius PQ = 5 cm, draw an arc of the triangle to intersect ray RX at P.
4. Join PQ to obtain the desired triangle PQR.
5. PQR is the required triangle.
2. Draw a right triangle whose hypotenuse is of length 4 cm, and one side is of length 2.5 cm.
Solution:
Steps of construction:
1. Draw a line segment QR = 2.5 cm.
2. Draw ∠QRX of measure 90o.
3. With centre Q and radius PQ = 4 cm, draw an arc of the triangle to intersect ray RX at P.
4. Join PQ to obtain the desired triangle PQR.
5. PQR is the required triangle.
3. Draw a right triangle having hypotenuse of length 5.4 cm, and one of the acute angles of measure 30o
Solution:
Let ABC be the right triangle at A such that hypotenuse BC = 5.4 cm. Let C = 30o.
Therefore ∠A + ∠B + ∠C = 180o
∠B = 180o − 30o− 90o = 60o
Steps of construction:
1. Draw a line segment BC = 5.4 cm.
2. Draw angle CBY = 60o
3. Draw angle BCX of measure 30o with X on the same side of BC as Y.
4. Let BY and CX intersects at A.
5. Then ABC is the required triangle.
4. Construct a right triangle ABC in which AB = 5.8 cm, BC = 4.5 cm and ∠C = 90o.
Solution:
Steps of construction:
1. Draw a line segment BC = 4.5 cm.
2. Draw ∠BCX of measure 90o
3. With centre B and radius AB = 5.8 cm, draw an arc of the triangle to intersect ray CX at A.
4. Join AB to obtain the desired triangle ABC.
5. ABC is the required triangle.
5. Construct a right triangle, right angled at C in which AB = 5.2 cm and BC= 4.6 cm.
Solution:
Steps of construction:
1. Draw a line segment BC = 4.6 cm.
2. Draw ∠BCX of measure 90o
3. With centre B and radius AB = 5.2 cm, draw an arc of the triangle to intersects ray CX at A.
4. Join AB to obtain the desired triangle ABC.
5. ABC is the required triangle.
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