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The heights of 50 students, measured to the nearest centimeters, have been found to be as follows: 161 150 154 165 168 161 154 162 150 151 162 164 171 165 158 154 156 172 160 170 153 159 161 170 162 165 166 168 165 164 154 152 153 156 158 162 160 161 173 166 161 159 162 167 168 159 158 153 154 159 (i) Represent the data given above by a grouped frequency distribution table, taking the class intervals as 160 – 165, 165 – 170, etc. (ii) What can you conclude about their heights from the table?

Solution Grouped frequency distribution table with classes 160 – 165, 165 – 170, etc… The data is represented in the grouped... View Article

A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of 30°, which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be 60°. Find the time taken by the car to reach the foot of the tower from this point.

Let AB be the tower. D is the initial and C is the final position of the car respectively. As man is standing at the top of the tower so,... View Article

A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is 60°. From another point 20 m away from this point on the line joing this point to the foot of the tower, the angle of elevation of the top of the tower is 30° (see Fig.) . Find the height of the tower and the width of the canal.

From diagaram AB = tower = ? CB = canal = ? From right ΔABD, tan 30° = AB/BD 1/√3 = AB/(20+BC) AB = (20+BC)/√3 …... View Article