# Ncert Solutions For Class 7 Maths Ex 10.5

## Ncert Solutions For Class 7 Maths Chapter 10 Ex 10.5

Q1:

Construct a right angled Δ$\Delta$ ABC, where $\angle$ B = 90o  BC = 8 cm and AC = 10 cm

Solution:

To construct:

A right angled triangle ABC where $\angle$ B = 90o BC = 8cm and AC = 10cm

Construction:

(i) Draw a line segment BC = 8cm

(ii) At point B, draw BP  $\perp$  BC

(iii) taking C as the center, draw an arc of radius 10cm

(iv) this arc cuts BP at point X

(V) join XB

It is the required right angled triangle ABC.

Q2 :

Construct a right angled triangle whose hypotenuse is 6cm long and one of the legs is 4cm long.

Solution:

TO construct:

A right angled triangle ABC where AC = 6cm and BC = 4cm

Construction:

(i) Draw a line segment BC = 4cm

(ii) At point X, draw BX  $\perp$  BC

(iii) Taking C as the center and radius 6cm, draw an arc. (Hypotenuse)

(iv) This arc cuts the BX at point A

(v) Join AC

It is the required right angled triangle ABC.

Q3 :

Construct an isosceles right angled triangle PQR, where $\angle$PQR = 90o and PR = 6cm.

Solution:

To construct:

An isosceles right triangle PQR where $\angle$R = 90o, PR = QR = 6cm

Construction:

(i) Draw a line segment PR = 6cm

(ii) At point R, draw XR  $\perp$  RP

(iii) Taking R as the center and radius 6 cm, draw an arc

(iv) This arc cuts RX at point Q

(v) Join QP

It is the required isosceles right angled triangle PQR