# NCERT Solutions for Class 7 Maths Exercise 10.5 Chapter 10 Practical Geometry

NCERT Solutions for Class 7 Maths Exercise 10.5 Chapter 10 Practical Geometry in simple PDF are given here. Constructing a Right-Angled Triangle When The Length of One Leg and Its Hypotenuse are given (RHS Criterion) is the only topic covered in this exercise of NCERT Solutions for Class 7 Maths Chapter 10. To help students with their exam preparation to achieve good marks in Maths, students are advised to try solving the problems from NCERT Solutions for Class 7 Maths, Chapter 10 Practical Geometry. Then refer to these solutions to know the best way of approaching the different questions.

## Download the PDF of NCERT Solutions For Class 7 Maths Chapter 10 Practical Geometry â€“ Exercise 10.5

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### Access Other Exercises of NCERT Solutions For Class 7 Maths Chapter 10 â€“ Practical Geometry

Exercise 10.1 Solutions

Exercise 10.2 Solutions

Exercise 10.3 Solutions

Exercise 10.4 Solutions

### Access Answers to NCERT Class 7 Maths Chapter 10 â€“ Practical Geometry Exercise 10.5

1. Construct the right angled Î”PQR, where mâˆ Q = 90Â°, QR = 8cm and

PR = 10 cm.

Solution:-

Steps of construction:

1. Draw a line segment QR = 8 cm.

2. At point Q, draw a ray QY to making an angle of 90o i.e. âˆ YQR = 90o.

3. With R as a center and radius 10 cm, draw an arc that cuts the ray QY at P.

4. Join PR.

Then, Î”PQR is the required right angled triangle.

2. Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long

Solution:-

Let us consider Î”ABC is a right angled triangle at âˆ B = 90o

Then,

AC is hypotenuse = 6 cm â€¦ [given in the question]

BC = 4 cm

Now, we have to construct the right angled triangle by the above values

Steps of construction:

1. Draw a line segment BC = 4 cm.

2. At point B, draw a ray BX to making an angle of 90o i.e. âˆ XBC = 90o.

3. With C as a center and radius 6 cm, draw an arc that cuts the ray BX at A.

4. Join AC.

Then, Î”ABC is the required right angled triangle.

3. Construct an isosceles right-angled triangle ABC, where mâˆ ACB = 90Â° and

AC = 6 cm.

Solution:-

Steps of construction:

1. Draw a line segment BC = 6 cm.

2. At point C, draw a ray CX to making an angle of 90o i.e. âˆ XCB = 90o.

3. With C as a center and radius 6 cm, draw an arc that cuts the ray CX at A.

4. Join AB.

Then, Î”ABC is the required right angled triangle.